1.3 Chemical calculations (re) Flashcards

1
Q

This may be our downfall, for such a teacher we were given it’s basically gon be solo yolo, but what is the purpose for teachers?

Bruh

A

You raise a good point!

he definitely raised a good point guys

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2
Q

Formula for relative atomic mass?

75% Cl-35 and 25% Cl-37

A

% x atomic number / 100
also add em at the top

(75x35)+(25x37)/100
= 35.5

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3
Q

What’s a mass spectrometer?
(3 things)

A
  • An analytical technique
  • Used to identify different isotopes
  • And find overall relative atomic mass of an element
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4
Q

Explain step 1: Ionisation in mass spectrometry?
(5 things)

A
  1. A sample of an element is vapourised and injected
    - Into mass spectrometer
    - Where high voltage passed over chamber
    - Causes electrons to be removed from atoms (ionised)
    - Leaving 1+ charged ions in chamber
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5
Q

Explain step 2: Acceleration in mass spectrometry?
(2 things)

A
  1. Positively charged ions are accelerated towards
    - Negatively charged detection plate
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6
Q

Explain step 3: Ion drift in mass spectrometry?
(4 things)

A
  1. Ions deflected by magnetic field
    - Into a curved path
    - Radius of their path dependent on
    - Charge & mass of ion
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7
Q

Explain step 4: Detection in mass spectrometry?
(4 things)

A
  1. When positive ions hit negatively charged detection plate,
    - They gain an electron
    - Producing flow of charge
    - Greater current produced = greater abundance
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8
Q

Explain step 5: Analysis in mass spectrometry?
(4 things)

A
  1. Current values used in combination
    - With flight times to produce
    - Spectra print-out
    - With relative abundance of each isotope displayed
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9
Q

In mass spectrum, why do we see a half traced version of the ion?
(5 things)

A
  • During ionisation process, 2+ charged ion may be produced
  • Will be affected more by magnetic field
  • Producing curved path of a smaller radius
  • As a result, mass to charge ratio (m/z) is halved
  • Can be seen on spectra as a trace at half the expected m/z value
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10
Q

In mass spectrum:
What m/z?
What relative abundance?

> _>

A
  1. Mass to charge ratio
  2. Relative atomic mass?

icl i haven’t seen where u had to put a number for a certain bar so i reckon u don’t get fucked up by this one

I changed it lol

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11
Q

For mass spectra graph, how u gain mass for the 2 isotopes

A

Formula for mass of 2 isotopes:

1(relative abundance x m/z)+2(relative abundace x m/z)/ra1 + ra2

May seem a lil hard to remember but gl bro B)

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12
Q

How to gain empirical formula?

48.38% carbon, 8.12% hydrogen, rest is O2 (43.50%)

% = their mass

A

mass/mr = a number (mols?)
then divide that number with it (the smallest number u’ve gained)
double it if the number is not whole

48.38/12 = 4.03 divided by 2.72
8.12/1.01 = 8.02 divided by 2.72
43.5/16 = 2.72 divided by 2.72
(O has a 2, perhaps i should’ve done that 2 to gain real empirical formula)
2.72 is the smallest number

C = 1.5 x 2 = 3
H = 3 x 2 = 6
O = 1 x 2 = 2

C3H6O2

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13
Q

How to gain molecular formula?

CH has molar mass of 78.1g/mol

A

molar mass/mr empirical formula

CH = 12 + 1.01 = 13.01

78.1/13.01 = 6.00 = 6

C6H6

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14
Q

Formula for moles?

A

Mass/molar mass = n

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15
Q

How to gain mass of one molecule?

H2

A

Mr x number of atoms
then divide it by avogadro’s constant (6.02x10^23)

1.01 x 2 = 2.02 mr
2.02/6.02x10^23 = 3.36x10^-24

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16
Q

How to gain number of molecules in a compound?

1.058 mole of H2O

A

n x avogadro’s constant

1.058 x (6.02x10^23) = 6.37x10^23

17
Q

How to gain moles from molar volume + volume?

120cm^3 of hydrogen at RTP (24.5 molar volume)

A

Volume (v) = number of moles (n) x molar volume (Vm)
(also divide volume into dm^3)
0.12/24.5 = 0.0049 or 4.89 x 10^-3

18
Q

How to understand mole ratio?

H2O + 2H2O

A
  1. Gain moles (so use n = m/M)
  2. The 2 on the second H2O is very important (lol)
    1:2 mole ratio
  3. So then that means mols for second H2O
    is double mols of first H2O

:v

19
Q

What is the ideal gas equation?

and what’s the 3 points to note?

A

pV = nRT

  1. Temp must be kelvin (0 degrees = 273K)
  2. Pressure must be in pascals (1atm = 101325 Pa)
  3. Volume must be m^3 (convert cm by dividing by 10^6)
20
Q

Define each symbol from ‘pV = nRT’

A

P = pressure (Pa)
V = volume (m^3)
n = number of moles (mols)
R = molar gas constant (8.31Jmol^-1 K-1)
T = temperature (K)

21
Q

What’s the simplified gas equation?
and when to use it?

A

P1V1/T1 = P2V2/T2
Only when the moles remain constant

22
Q

What equation if number of moles and volume remain constant?

(simplified gas equation)

A

P1/T1 = P2/T2

23
Q

What equation if number of moles and temperature remain constant?

(simplified gas equation)

A

P1V1 = P2V2

24
Q

What equation if number of moles and pressure remain constant?

(simplified gas equation)

A

V1/T1 = V2/T2

25
How to gain concentration of a certain chemical present in a solution? Conc. of NAOH solution when 4.0g of NaOH powder dissolved in 250cm^3 of distilled water? (**in moldm^-3**)
Know this: n = cv and rearrange for n = c = n/v and also know n = m/M 1. Since it's moldm^-3, - Convert 250cm^3 to dm^3 = 250/1000 = 0.25dm^-3 2. Gain mr of NaOH - 25 + 16 + 1.01 = 40.01 3. Gain moles - 4/40.01 = 0.0999 4. Divide Tingy n stuff - 0.0999/0.25 = 0.3996moldm^-3
26
How to find concentration of chemicals with just their solubility? Solubility of ammonium chloride , NH4Cl is 37.2g/100g water. What is the concentration in moldm^-3?
n = m/M moles = mass/mr 1. When u convert for dm^3, mass gotta be times by 10 - 37.2 & 100cm^3 = 372 & 1dm^3 2. n = m/M with the NH4Cl - 372/(14 + 4.04 + 35.5) = 6.95 moldm^-3 Doesn't make sense but just go with it man :(
27
Wat percentage yield?
uhhh idk the info it no say, only for actual and theoretical But here's the formula: Percentage yield = (Actual yield/Theoretical yield) x 100
28
2 reasons for how percentage yield may be below 100%?
1. Not all reactants react 2. Impurities in reactants
29
The simplified formula for percentage yield?
(what you get/what you should get) x 100
30
How would u get the theoretical yield specifically? 3.00g of ethanoic anhydride reacts with water to give ethanoic acid. (CH3CO)2O + H2O --> 2CH3COOH Calculate theoretical yield
1. Mole ratio first - It's 1:2 so 0.03 x 2 = 0.06 mols (Look in book for more details) 2. mass = mols x mr - 0.06 x 60.04 = 3.60g <-- that's the theoretical yield ig (don't include the 2 in front)
31
How to really get the percentage yield? When 18.0g of propan-1-ol (C3H8O) was reacted with excess acidified sodium dichromate, 7.20g of propanol (C3H6O) were obtained. Calculate percentage yield given the equation 3C3H8O + Na2Cr2O7 + 4H2SO4 --> 3C3H6O + Na2SO4 + 7H2O
1. We got the masses for the propanols sooo we gain mr first for both - 3C3H8O = 36 + 8.08 + 16 = 60.08 - 3C3H6O = 36 + 6.06 + 16 = 58.06 (**DON'T INCLUDE THE NUMBERS INFRONT OF EM**) 2. Do mass/mr = mols - 18/60.08 = 0.29 - 7.20/58.06 = 0.12 3. The real percentage yield (actual/theoretical) x 100 - 0.12/0.29 x 100 = 41.4%
32
What 2 things atom economy check?
1. How much of the reactants are turned into desirable products 2. And how much is waste product
33
Formula for atom economy?
(molecular mass of desired product/sum of molecular masses of all products) x 100
34
How to calculate atom economy for this one? CH3CH2OH + HBr --> CH3CH2Br + H2O The desired product is bromoethane
1. Gain mr of CH3CH2Br (that's bromoethane) - 24 + 5.05 + 79.9 = 108.95 2. Add mr of bromoethane with water - mr of H2O = 2.02 + 16 = 18.02 - 108.95 + 180.02 = 126.97 3. (Mr of bromoethane/Mr of resultant products altogether) x 100 - (108.95/126.97) x 100 = 85.8%
35
Look at the last question of atom economy in the book cuz it has both atom economy and percentage yield soooo ye
Ohhhhh kayyyyyyy.
36
We just keep continuing. Also questions are good for answering so ye idk do something, am currently sick rn
¬.¬