1.2 amount of substance Flashcards
how many particles are in a mole?
6.022 x 10^23
no of particles=
no of moles x avogadros constant
moles=
mass/Mr
What is the ideal gas equation?
lets you find no of moles in volume at any temp and pressure
pV=nRT
Pa, m^3, mol,8.31JK-1mol-1, k (add 273)
what is an ionic equation?
only includes reacting particles and products
1) balance equation
2) rewrite as ions 3)remove anything on both sides
4) check charges are balanced
how do you work out calculating masses?
1) write balanced equation
2)work out how many moles of reactant you have
3) use molar ratio to find how many moles of product will be formed
4) calculate mass of product
dont use big nos in Ar as these are taken into account with ratio
How do calculate gas volumes?
1) balance equation
2) find moles of reactant
3)use molar ratio to find moles of product
4) put moles of product into ideal gas equation
what is a titration?
neutralisation reaction to find conc of acid/ alkali solution
2 indicators used in titrations?
methyl orange is red in acid and yellow in alkali
phenolphthalein is colourless in acid and pink in alkali
How do you do a titration calculation?
draw table of acid, alkali and conc, vol, mol
fill in what know (vol in dm3
work out moles you can
use molar ratio to find other moles
find conc
what is the empirical formula?
smallest whole number ratio of atoms of eahc element in a compound
what is the molecular formula?
actual number of atoms in a molecule
how do you work out molecular formula from empirical
1) find empirical mass by adding up Ar of each atom eg 83
2) divide molecular mass by empirical eg 166/83=2
3) do empirical formula x answer to 2 eg C4H302 X 2 = C8H604
how do you calculate empirical formula?
1) calculate moles of each element by doing % or mass (assume you’ve got 100g of compound) / Ar
2) divide each no of moles by smallest no of moles you found to get the ratio
3) may have to multiply to get whole numbers
What is maximum theoretical yield?
the yield you would get assuming no chemicals are lost.