11: Engineering Physics Flashcards

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1
Q

First Law of Thermodynamics (4)

A
  • Q = ΔU + W
  • Q is energy transferred to the system by heating
  • ΔU is the increase in internal energy
  • W is work done by the system
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2
Q

Ideal Gas Equation

A

p V = n R T

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3
Q

Isothermal Changes (4)

A
  • Where the temperature of the system is constant
  • The gas’s absolute temperature determines its internal energy
  • So ΔU = 0, meaning Q = W
  • Hence, supplying heat energy to the system results in an equivalent amount of work being done by the gas so its volume increasing
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4
Q

Isothermal Change Equation

A

p V = constant

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5
Q

Adiabatic Changes (3)

A
  • Where no heat is transferred in or out of the system
  • So Q = 0 meaning ΔU = -W
  • Hence, any change in the internal energy of the system is caused by work done by/on the system
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6
Q

Adiabatic Change Equation

A

p V^γ = constant

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7
Q

Constant Pressure Change Equation

A

V / T = constant

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8
Q

Constant Volume Changes (3)

A
  • If volume is constant, no work is done by/on the system
  • So W = 0 meaning Q = ΔU
  • Hence, all heat energy transferred to the system goes into increasing its internal energy
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9
Q

Constant Volume Change Equation

A

p / T = constant

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10
Q

p-V Diagrams for Isothermal Changes (3)

A
  • p-V diagram for a compression, where work is done on the system:
    Textbook p539 Figure 2
  • p-V diagram for an expansion, where work is done by the system:
    Textbook p539 Figure 2
  • The higher the temperature of the process, the further from the origin the p-V diagram is
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11
Q

p-V Diagrams for Adiabatic Changes (3)

A
  • The p-V curves for adiabatic processes have a steeper gradient than isothermal processes
  • More work is done to compress gas adiabatically than isothermally:
    Textbook p540 Figure 4
  • The gas does less work if it expands adiabatically instead of isothermally
    Textbook p541 Figure 5
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12
Q

p-V Diagram for Constant Volume Changes (3)

A
  • p-V diagrams for changes with constant volume are straight vertical lines
  • No work is done as volume doesn’t change and there is no area under the line
  • If a system is heated at constant volume, its pressure will increase:
    Textbook p541 Figure 6
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13
Q

p-V Diagram for Constant Pressure Changes (3)

A
  • p-V diagrams for constant pressure changes are straight horizontal lines
  • The work done is the area of the rectangle under the graph – W = p ΔV
  • Textbook p541 Figure 7
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14
Q

Work Done =

A

Area below the graph

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15
Q

Work Done per Cycle =

A

Area of loop

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16
Q

Four-Stroke Petrol Engine Cycle (4)

A
  • Induction
  • Compression
  • Expansion
  • Exhaust
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17
Q

Induction (3)

A
  • The piston moves down, increasing the volume of the gas (air-fuel mix) as the inlet valve is open
  • The pressure of the gas remains constant just below atmospheric pressure
  • Indication diagram: Textbook p544 Figure 1
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18
Q

Compression (5)

A
  • The inlet valve is closed and the piston moves up the cylinder
  • This does work on the gas, increasing the pressure
  • Just before the piston is at the end of this stroke, the spark plug creates a spark, igniting the gas
  • The temperature and pressure increase at almost constant volume
  • Indication diagram: Textbook p544 Figure 3
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19
Q

Expansion (4)

A
  • The hot gas expands and does work on the piston, pushing it down
  • The work done by the gas is greater than the work done to compress it as it is now at a higher temperature
  • Just before the piston is at the end of this stroke, the exhaust valve opens, reducing the pressure
  • Indication diagram: Textbook p545 Figure 4
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20
Q

Exhaust (3)

A
  • The piston moves up the cylinder and the burnt gas leaves through the exhaust valve
  • The pressure remains almost constant
  • Indication diagram: Textbook p545 Figure 5
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21
Q

Four-Stroke Diesel Engine Cycle (5)

A
  • In the induction stroke, only air is pulled into the cylinder
  • Diesel engines don’t have a spark plug, so in the compression stroke, the air is compressed until its temperature is high enough to ignite the fuel
  • Just before the end of the stroke, diesel is sprayed into the cylinder through a fuel injector and ignites
  • The expansion and exhaust strokes are the same as a petrol engine
  • The indicator diagram has a flatter peak at the start of the expansion stroke, showing the point where fuel is injected and heats up to combustion temperature:
    Textbook p545 Figure 7
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22
Q

Assumption of Theoretical Cycles (5)

A
  • The same gas is taken continuously around the cycle
  • The gas is pure air with an adiabatic constant γ = 1.4
  • Pressure and temperature changes can be instantaneous
  • The heat source is external
  • The engine is frictionless
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23
Q

Petrol Engine Cycle Theoretical Diagram (5)

A
  • A: The gas is compressed adiabatically
  • B: Heat is supplied at constant volume
  • C: The gas cools adiabatically
  • D: The system cools at constant volume
  • Textbook p546 Figure 8
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24
Q

Diesel Engine Cycle Theoretical Diagram (5)

A
  • A: The gas is compressed adiabatically
  • B: Heat is supplied at constant pressure
  • C: The gas cools adiabatically
  • D: The system cools at constant volume
  • Textbook p546 Figure 10
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25
Q

Comparison of Theoretical and Real Diagrams (7)

A
  • Curved corners: because valves take finite time to open and close
  • No constant volume process: because piston would have to stop
  • Compression and expansion not adiabatic curves: because energy is lost by heat transfer
  • The cycle is open because engine needs to
    draw in air and expel exhaust
  • Heating not at constant pressure: because fuel injection and combustion cannot be exactly controlled
  • Area of diagram is less because energy is lost by heat
    transfer and incomplete combustion
  • Pressure not as high because incomplete combustion
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26
Q

Indicated Power =

A

(Area of p–V loop) x (no. of cycles per second) x (no. of cylinders)

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27
Q

Output or Brake Power Equation

A

P = T ω

28
Q

Friction Power =

A

Indicated power - brake power

29
Q

Input Power =

A

Calorific value x fuel flow rate

30
Q

Engine Efficiency (5)

A
  • Mechanical efficiency is affected by the amount of energy lost through moving parts
  • Mechanical efficiency = brake power / indicated power
  • Thermal efficiency describes how well heat energy is transferred into work
  • Thermal efficiency = indicated power / input power
  • Overall efficiency = brake power / input power
31
Q

Impossibility of Engine Working only by First Law (4)

A
  • No engine can transfer all the heat energy it is supplied into useful work
  • Some heat ends up increasing the temperature of the engine
  • If the engine temperature reaches that of the heat source, then no heat flows and no work is done
  • So, engines cannot work by only the first law as Q and W would both be 0
32
Q

Second Law of Thermodynamics

A

The need for a heat engine to operate between a source and a sink

33
Q

Diagram of Heat Engine Operating between Heat Source & Heat Sink

A

Textbook p552 Figure 1

34
Q

Heat Engine Efficiency =

A

W / Q_H = (Q_H - Q_C) / Q_H

35
Q

Heat Engine Maximum Theoretical Efficiency =

A

(T_H - T_C) / T_H

36
Q

Reason for Lower Efficiencies of Practical Engines

A

There is usually a lot of waste heat, which is transferred to the surround area and lost

37
Q

Combined Heat & Power Schemes

A

They use waste heat to heat houses and supply heat to businesses nearby as well as generate electricity to use and supply to the national grid

38
Q

Refrigerators (4)

A
  • The cold space is inside the refrigerator and the hot space is the refrigerator’s surroundings
  • A refrigerator extracts heat energy from the cold space
  • Work is done to transfer heat energy via pipes on the back of the appliance
  • Refrigerators keep enclosed spaces cool so they can keep perishable food fresh
39
Q

Heat Pumps (3)

A
  • The cold space is outdoors and the hot space is inside a house
  • A heat pump pumps heat into the hot space
  • They are used to heat rooms and water in homes
40
Q

Reversed Heat Engine Diagram

A

Textbook p555 Figure 1

41
Q

Coefficient of Performance

A

The amount of heat energy transferred per unit of work done

42
Q

Refrigerator Coefficient of Performance (3)

A
  • It’s the heat removed from the cold space, that’s important for a refrigerator
  • COP_ref = Q_C / W = Q_C / (Q_H - Q_C)
  • Maximum theoretical COP_ref = T_C / (T_H - T_C)
43
Q

Heat Pump Coefficient of Performance (3)

A
  • It’s the heat transferred to the hot space, that’s important for a heat pump
  • COP_hp = Q_H / W = Q_H / (Q_H - Q_C)
  • Maximum theoretical COP_hp = T_H / (T_H - T_C)
44
Q

Moment of Inertia

A

A measure of how much an object resists a change to its rotational speed

45
Q

Moment of Inertia for a Point Mass

A

I = m r²

46
Q

Moment of Inertia for an Extended Object

A

I = Σ m r²

47
Q

Factors Affecting Moment of Inertia (2)

A
  • The magnitude of the object’s mass
  • The distribution of the object’s mass about its centre of rotation
48
Q

Angular Kinetic Energy Equation

A

Eₖ = 1/2 I ω²

49
Q

Factors Affecting Energy Storage Capacity of a Flywheel (3)

A
  • Increase its mass to increase its moment of inertia and so kinetic energy stored
  • Increase its angular speed to increase its kinetic energy stored
  • Use a wheel with spokes or a heavier rim so more mass is concentrated further from the axis of rotation, increasing its moment of inertia and kinetic energy stored
50
Q

Flywheel

A

A heavy wheel, which has a high moment of inertia in order to resist changes to its rotational motion

51
Q

Uses of Flywheels in Machines (3)

A
  • Flywheels are charged as they are spun, turning input torque into rotational kinetic energy. If it keeps spinning at the same rate, it stores the energy for later use
  • Just enough power is continuously input to overcome frictional torque, keeping the flywheel fully charged
  • When extra energy is needed, the flywheel decelerates, transferring some of its kinetic energy to another part of the machine
52
Q

Uses of Flywheels for Smoothing Torque & Speed (4)

A
  • Flywheels are used in machines to smooth engine and load (torque due to resistance forces) torque
  • In systems where the power supplied can vary, flywheels keep the angular velocity of rotating components constant. It uses each spurt of power to charge and delivers the energy smoothly
  • In systems where the force to exert can vary, flywheels are used. If the load torque is too high, the flywheel decelerates, releasing extra energy
  • If the engine torque is greater than the load torque, the flywheel charges by accelerating to store the spare energy
53
Q

Angular Displacement

A

The angle through which a point has been rotated

54
Q

Angular Velocity

A

The angle a point rotates through per unit time

55
Q

Angular Speed

A

The magnitude of angular velocity

56
Q

Angular Acceleration

A

The rate of change of angular velocity

57
Q

Angular Velocity Equation

A

ω = Δθ/Δt

58
Q

Angular Acceleration Equation

A

α = Δω/Δt

59
Q

Torque Equations

A
  • T = F r
  • T = I α
60
Q

Angular Momentum Equation

A

angular momentum = I ω

61
Q

Conservation of Angular Momentum

A

Assuming no external torques act, the total angular momentum of a system remains constant

62
Q

Angular Impulse =

A

Change in angular momentum

63
Q

Angular Impulse Equation

A

T Δt = Δ(I ω)

64
Q

Rotational Dynamics Work Done Equation

A

W = T θ

65
Q

Rotational Dynamics Power Equation

A

P = T ω