10 Coordination Flashcards
EQ
A myelinated axon conducts impulses faster than a non-myelinated axon. Explain this difference. (3)
- (In myelinated) action potential/depolarisation
only at node(s); - (In myelinated, nerve impulse) jumps from node
to node/saltatory; - (In myelinated) action potential/impulse does
not travel along whole length;
EQ
Explain the shape of the curve for sodium ions between 0.5 ms and 0.7 ms (rapid increase) (3)
(Ion) channel proteins open;
Sodium in;
Changes membrane potential/makes inside of axon less
negative/positive/depolarisation/ reaches threshold;
More channels open/positive feedback;
EQ
During an action potential, the membrane potential rises to +40 mV and then falls. Use
information from the graph to explain the fall in membrane potential. (3)
Potassium channels open;
Potassium out;
Sodium channels close;
EQ
After exercise, some ATP is used to re-establish the resting potential in axons. Explain
how the resting potential is re-established.. (2)
Pump/active transport/transport against concentration
gradient;
Of sodium from axon/sodium out/of potassium in;
EQ
Describe how hormones are different in the cells they affect. (1)
Hormones have widespread effect / affect different organs /
affect different parts of the body / affect distant organs / only
affect cells with right receptor;
EQ
Describe how hormones and local chemical mediators reach the cells they affect. (2)
- Hormones in blood;
- Local chemical mediators spread by diffusion / spread
directly;
EQ
Synapses are unidirectional. Explain how acetylcholine contributes to a synapse being
unidirectional. (2)
- (Acetylcholine) released from/in presynaptic side;
- Diffusion from higher concentration/to lower concentration;
- Receptors in postsynaptic (side) / binds on postsynaptic
(side) ;
EQ
The black mamba’s toxin kills prey by preventing their breathing. It does this by
inhibiting the enzyme acetylcholinesterase at neuromuscular junctions. Explain how
this prevents breathing. (3)
1. Acetylcholine not broken down / stays bound to receptor; 2. Na+ ions (continue to) enter / (continued) depolarisation / Na+ channels (kept) open / action potentials/impulses fired (continuously); 3. (Intercostal) muscles stay contracted / cannot relax;
EQ
Serotonin is a neurotransmitter released in some synapses in the brain. It is
transported back out of the synaptic gap by a transport protein in the pre-synaptic
membrane.
7 (a) Serotonin diffuses across the synaptic gap and binds to a receptor on the post-synaptic
membrane.
Describe how this causes depolarisation of the post-synaptic membrane. (2)
- Causes sodium ion channels to
open; - Sodium ions enter (cell and
cause depolarisation);
EQ
It is important that a neurotransmitter such as serotonin is transported back out of
synapses. Explain why. (2)
- (If not removed) keeps binding (to
receptors); - Keeps causing action
potentials/depolarisation (in postsynaptic
membrane); - Prevents information being
carried across synapse/described
consequence;
EQ
What conclusion can be made from the results for treatment B? (1) (grows horizontally, 0 degree curvature)
1. (Cells in) root tip detect gravity / respond to gravity; OR 2. IAA/auxin is produced in the root tip;
EQ
(low on top, high on bottom)
Explain how this distribution of IAA causes the root to bend (2)
1. Greater (elongation) growth on top of root/less growth on bottom of root; 2. (IAA) at bottom of root/where IAA concentration high inhibits expansion/elongation (of cells); 3. (IAA) at top of root/where IAA concentration low leads to expansion/elongation (of cells);
EQ
When a young shoot is illuminated from one side, IAA stimulates growth on the shaded
side. Explain why growth on the shaded side helps to maintain the leaves in a
favourable environment. (2)
- Causes plant to bend/grow towards light / positive
phototropism; - (Light) required for photosynthesis;
EQ
The pea seedlings were kept in the dark after each treatment. Explain why this was
necessary. (1)
1. (Seedlings) respond to light / are phototropic; OR 2. (Only) measuring the effect of gravity / response to gravity;
EQ
Name the process by which IAA moves from the growing regions of a plant shoot to
other tissues. (1)
Diffusion;
EQ
Suggest how indoleacetic acid (IAA) could have caused the results for:
treatment A (grows downwards, 60 degree curvature)
treatment B (upper half of root tip removed, grows downwards, 30 degree curvature)
) 1. IAA/auxin moves to lower side / more IAA/auxin on lower side; 2. Lower side grows less/slower / upper side grows more /faster / inhibits growth on lower side;
- Less IAA/auxin (produced);
- Lower side grows
more/faster / less inhibition
of growth on lower side;