1 Flashcards

1
Q

Bonds

A

Bonds have a FACE VALUE which is the final payment paid on the MATURITY DATE along with the last of the coupon payments paid every so often.

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2
Q

Correct price

A

Equilibrium price: non arbitrage pricing (for which arbitrage strategies don’t occur)

If too low or hard go then profits can be made and unstable as the demand for the low price causes it to rise so a price that’s stable is one that doesn’t introduce arbitrage opportunities

Eg selling price can be worked out from prices for others

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3
Q

Amount invested for n years with an interest rate compounded a number of times a year

A

An amount A invested for n years at a yearly interest rate r compounded m times a year yields at the end of this a period

A( 1 + (r/m)) ^mn

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4
Q

Present value

A

The present value, of a payment occurring in the future, is the number resent price of entitlement to that payment

•deposit £A yields £B withdrawn after t years so we pay A now to receive B in t years- the present value of B paid in t years is A

PRESENT VALUE 
—————-multiply by (1 + (r/m))^mn  to
 FUTURE PAYMENT
—————-multiply by (1 + (r/m))^-mn  to
PRESENT VALUE
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5
Q

Continuously compounded interest rates

A

An amount A invested for t-years accruing a yearly interest rate of r compounded continuously, yields at the end of this period £Ae^rt

present value of an amount X with continuously compounded interest is Xe^-rt

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6
Q

Example: borrow £1000 for 3 years at an 5% annual interest rate compounded every 6 months

A

Example: borrow £1000 for 3 years at an 5% annual interest rate compounded every 6 months

A=1000
r=0.05
m= 2 (times a year)
n= 3 (years)

Loan = 1000(1+ 0.05/2)^ 6 = £1158.69

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7
Q

Example: pay in X for ten years paying an interest rate of 3% per year compounded yearly

A

Example: pay in X for ten years paying an interest rate of 3% per year compounded yearly

After ten years we have
X ( 1 + (0.03/1))^10
= 1.03^10• X

So if we wAnt £1 in ten years must deposit 1/1.03^10 = 0.74

(Present value of £1 is 74p and the right price to pay for this is this, otherwise we could could perform an arbitrage strategy by borrowing and repaying loans )

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8
Q

Example: £100,000 mortgage with a fixed annual interest rate of 6% compounded monthly, what are the repayments per month if we are repaying in 20 years

A

Example: £100,000 mortgage with a fixed annual interest rate of 6% compounded monthly, what are the repayments per month if we are repaying in 20 years

The bank is willing to pay for all future payments a certain amount: based on the total of the present values
Let the repayments be P

The LAST (future payment) repayment P  has present value 
P(1+ (0.06/12))^ -(240) 

The second to last (future payment) has present value
P(1+(0.06/12))^-239

The second has present value P(1+0.06/12)^-2
The first payment has present value P(1+0.06/12)^-1

The bank wants the sum of all the PRESENT values of the repayments to equal 100,000:

100,000= (from k=1 to 240)Σ P(1+0.06/12)^-k

Hence. P=716.43

(Note: the future value of 100,000 /240 is 1379 which is not equal to this, nor is 100000/240 = 416)

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9
Q

Zero coupon bond

A

A bond in which only one payment (final) is paid on the maturity of the bond with no other payments

The price p of a £B face value zero coupon with maturity in t years is therefore the PRESENT VALUE p of £B paid t years into the future

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10
Q

Proposition 1: zero coupon bond and continuously compounded interest

A

PROPOSITION 1: let P be the price of a zero coupon bond with face value £1 and maturing in t years. Let r be the continuously compounded interest rate for t year deposits and loans. Then

P = exp ( -rt)

PRESENT VALUE FOUND FROM FUTURE VALUE SO NEGATIVE EXPONENT

Proof: arbitrage strategies otherwise
P> e^-rt
Issue a zero coupon bond with face value £1 and maturing in t years, collect price P and deposit this for t years, withdrawing e^rt after t years then pay face value £1 of bond and pocket pe^rt -1 >0

P< e^-rt
Similarly borrow P for t years and buy the bond.. finally pocketing 1-Pe^rt >0

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11
Q

Discount curve

P(t)

A

Function of time P(t) whose value at any t ≥ 0 is the present value of one unit of currency paid in t years. Equivalently P(t) is the price of a 0 coupon bond with face value 1 maturing in t-years.

PRESENT VALUE OF FUTURE PAYMENT

So if we are FINDING this from a future payment we use a negative power

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12
Q

Yield curve

Y(t)

or r(t)

A

Function Y(t) whose value at any time t>0 is the interest paid on t year deposits

Y(5) is the value of the interest paid on a 5 year deposit

Values Y(t) SPOT INTEREST RATES OR YIELDS

• yield curves aren’t directly observable finding interest rate which fit observes prices of assets, by linear interpolation

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13
Q

Converting between Spot interest rates/ yields and present values

A

Finding present value from “future payment” (yield) so we use negative power in exponent
P(t) = exp(-Y(t)*t)

Y(t) = - log (P(t)) /t

P(t) is Finding the present value of zero coupon of ONE UNIT of currency so we can use to multiply by units for more than £1.

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14
Q

Constructing yield curves

A
  • use the equation to convert between P(t) and Y(t)
  • P(t) can be found: when it’s a zero coupon bond ….by dividing present price by the face value ( as defined for one unit only)

•P(t) can be found when not a zero coupon bond:
By calculating the total payments made worth ( ie summing the present value for each payment, which changes as payments are made at different times)
•Y(t) is found from p(t)

REMEMBER CALCULATIONS ONLY APPLY TO ZERO COUPIN BONDS

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15
Q
Example finding P(t) and Y(t)
Semi annual  coupon bonds
Face value: 
100 |100|100|100|100
Maturity yrs: 
0.25| 0.5| 1.  |1.5. |2
Annual interest:
  0.  |. 0.  | 0. |. 4. |6
Price: 
98.3|96.5|93.7|95.5|97.2
A

•P(0.25) = 98.3/100 , Y(0.25) = 6.86%
•P(0.5) = 0.965 Y(0.5) =7.13%
•P(1)= 0.937, Y(1) =6.51%
Following aren’t zero coupon bonds:

• P(1.5)=
Annual interest is 4, paid 2 a year cost is 95.5 which is the present value of the total of these FUTURE payments
= £2 each 0.5 years

             £2    £2    £2    £102 |——|——-|——|—--|——| 0     0.25  0.5     1     1.5     2
2P(0.5)
\+ 2P(1) 
\+ 2P(1.5)
\+ 102 P(2) 
= 95.5

And using others P(2) =0.826

• Y(2)) =7.42%
spot interest yields
(n/ year payments found from = annual interest*FACE VALUE)/ payments per year, not price but face value)

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16
Q

Forward rate agreement

A

Contracts in which one party agrees to pay the other party a pre-specified interest rate on a deposit o curing during a specified period of time IN THE FUTURE

For an interval of time, in the future.

17
Q

The forward rate

PROP: In a market with no arbitrage opportunities the interest rates of forward rate agreements are equal to the corresponding forward rates

ie if given a rate r for some period t1 to t2 ,that isn’t the forward rate, then we CAN find an arbitrage opportunity

A

Let 0 ≤ t₁ (less than) t₂ and let r₁ and r₂ be the respective t₁ and t₂ year interest rates. The FORWARD RATE r₁₂ for the period from t₁ to t₂ is ( r₂t₂ -r₁t₁) /(t₂-t₁)

Proof: By finding arbitrage strategies o/w
• Let the forward rate agreement time period start in t₁ years and end in t₂ years. Let r be the pre-specified interest rates and let r₁₂ =( r₂t₂ -r₁t₁) /(t₂-t₁)
• if r is bigger than r₁₂:
Enter the agreement as the depositor. Borrow e^-r₁t₁ for t₂ years at spot interest rate r₂ and deposit for t₁ years at spot interest rate r₁.
At t= t₁ withdraw deposit e^-r₁t₁* e^r₁t₁ = 1. Deposit this until t=t₂ at agreed rate r.
At t =t₂ obtain balance of deposit e^r(t₂-t₁).
Pay back loan, which is now (e^-r₁t₁)e^r₂t₂= e^( r₂t₂ -r₁t₁),
pocketing e^r(t₂-t₁) - e^( r₂t₂ -r₁t₁) which is larger than 0 .

(Since r is larger than ( r₂t₂ -r₁t₁) /(t₂-t₁) , r(t₂-t₁) is larger than ( r₂t₂ -r₁t₁) and exp is increasing funct. )

• if r is less than r₁₂: (rate too cheap)
Enter the agreement as borrower. Borrow e^-r₁t₁ for t₁
years at spot interest rate r₁ and deposit e^-r₁t₁ for t₂ years at spot interest rate r₂.
At t=t₁ borrow 1 at agreed rate r. Balance of first loan is e^-r₁t₁ * e^r₁t₁ = 1. So repay this first loan. .
At t =t₂ 2nd loan is now e^r(t₂-t₁)) and the deposit has balance e^-r₁t₁*e^r₂t₂= e^(r₂t₂-r₁t₁)

ie 1st loan and deposit, 2nd loan and pay off first loan, t2 withdraw deposit and pay off 2nd loan

Pocket e^(r₂t₂-r₁t₁)- e^r(t₂-t₁) , which is larger than 0.

18
Q

GEOMETRIC SERIES

A

*ensure ratio is less than 1
(negative power helps this)
sum of finite series = a(1-r^n)/(1-r)

infinite= a/(1-r)

19
Q

Derivative

A

Asset whose price depends on the value of other assets