Y2, C7 - Differential Equations Flashcards
How would you separate the variables in: dy/dx = f(x) g(y)
1/g(y) * dy/dx = f(x)
int(1/g(y)) * dy = int(f(x)) * dx
Find general solutions to dy/dx = -y/x
1/y * dy/dx = -1/x
int(1/y) * dy = int(-1/x) * dx
lnlyl = -lnlxl + lnlkl
y = k/x
Solve d/dx * (ysin(x))
sin * dy/dx + ycos(x)
Find general solutions of the equation x^3 dy/dx + 3x^2 * y = sinx
d/dx * (x^3 * y) = sinx
x^3 * y = int(sinx) dx
x^3 * y = -cosx
x^3 * y = -cos(x) + c
Using the reverse product rule, find general solutions to 4xy * dy/dx + 2y^2 = x^2
d/dx * (2xy^2) = x^2
2xy^2 = int(x^2)dx
2xy^2 = (1/3) * x^3 + c
y^2 = (1/6) * x^2 + c/2x
What is the integrating factor
e^(int(P)dx)
How do you solve equations in the form dy/dx + Py = Q
(where P and Q are functions of x)
Reverse product rule
What form of equation can you use the reverse product rule on
dy/dx + Py + Q
(where P and Q are functions of x)
What is the integrating factor of dy/dx - 4y = e^x
I.F. = e^(int(-4dx))
= e^-4x
What do you do once you have found the integrating factor
Multiply all terms in the expression by the integrating factor
Then solve the usual way (reverse product rule)
What do you do if there is a coefficient in front of the dy/dx term in an expression of form dy/dx + Py = Q
Divide all terms by the coefficient to remove
What would the solution of a * dy/dx + by = 0 be in the form of
y = Ae^(x * -b/a)
What would the solution of a(d2y/dx2) + b(dy/dx) + cy = 0 be in the form of
y = Ae^mx
What is the Auxiliary equation
am^2 + bm + c = 0
What does auxiliary mean
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