Y1, C4 - Roots of Polynomials Flashcards
What is the sum of the roots of a quadratic, cubic and quartic equation
α + β = -b / a
α + β + γ = -b / a
α + β + γ + δ = -b / a
What is the sum of products of pairs of roots of a quadratic, cubic and quartic equation
αβ = c/a
αβ + αγ + βγ = c/a
αβ + αγ + αδ + βγ + βδ + γδ = c/a
What is the sum of the products of triples of roots for a quadratic, cubic and quartic equation
N/A
αβγ = -d/a
αβγ + αγδ + αβδ + βγδ = -d/a
What would the product of the all roots of a quartic
e / a
What would be the product of all roots of a cubic
-d / a
Find the sum and product of the roots of the quadratic x^2 + 2x + 3
Sum = -2
Product = 3
How would you find the value of (1 / α) + (1 / β)
Add them = (α + β) / αβ
Sub in previously found values
How would you find the value of α^2 + β^2
(α+β)^2 = α^2 + 2αβ + β^2
(α+β)^2 - 2αβ = α^2 + β^2
Sub in previously found values
How can the sum of product pairs be written in sigma notation
Sigma(αβ)
How can the sum of the roots be written in sigma notation
Sigma(α)
How can (1 / α) + (1 / β) + (1 / γ) be written
(αβ + αγ + βγ) / αβγ
What is the sum of products of quadruples
αβγδ = e/a
What is the sigma notation for the sum of products of quadruples
Sigma(αβγδ)
What comes after delta (δ) in the greek alphabet
Epsilon (ε)
How can we write the sum of squares for quadratics, cubics and quartics in sigma notation?
α^2 + β^2 = Sigma(α)^2 - 2Sigma(αβ)
α^2 + β^2 + γ^2 = Sigma(α)^2 - 2Sigma(αβ)
α^2 + β^2 + γ^2 + δ^2= Sigma(α)^2 - 2Sigma(αβ)
How can we write the sum of cubes for quadratic and cubics in sigma notation
α^3 + β^3 = Sigma(α)^3 - 3Sigma(αβ) * Sigma(α)
α^3 + β^3 + γ^3 = Sigma(α)^3 - 3Sigma(αβ) * Sigma(α) + 3αβγ
What is the sum of reciprocals for the quartic roots
(Sigma(αβγ)) / αβγδ
What would α^n * β^n * γ^n * δ^n equal
(αβγδ)^n
(Follows index laws)
How would you find the value of (α + 3)(β + 3)(γ + 3) using sigma notation
Multiply terms out
= αβγ + 3Sigma(αβ) + 9Sigma(α) + 27
Plug in known values
The quartic equation x^4 - 3x^3 + 15x + 1 = 0, has roots α, β, γ, δ. Find the equation with roots (2α+1),(2β+1), (2γ+1), (2δ+1)
Let w = 2x+1, rearrange to (w-1) / 2 = x
Substitute into equation as x
= ((w-1)^4 / 16) - 3((w-1)^3 / 2) + 15((w-1) / 2) + 1 = 0
Multiply through by 16
= (w-1)^4 = 6(w-1)^3 + 120(w-1) + 16 = 0
= w^4 - 10w^3 + 24w^2 + 98w -97 = 0
What should you do if you don’t know the value of ‘a’
Set it to 1