Word Problems Flashcards
RECOGNITION:
1) What is this Q testing?
2) Solve the Q without looking at the answer
1) Overlapping Sets! (it’s testing a technique)
2) Lol look at GMATClub, I actually don’t know of the top
RECOGNITION:
1) What technique can be used to solve the problem in the attached image?
2) Solve the Q, what’s the answer?
1) Overlapping sets!
* When things are categorized (e.g., “GMAT test takers <650 vs. 650+”), that is a clue to use overlapping sets*
Keys here:
- Since not given any numbers in problem (and since not given for Total), pick a Smart Number for Total (in this case 100 is best since %s)
- Careful with the phrasing (20% of Test Takers who take the exam only once) –> in this case, set a variable for Total folks who take it only once (X)… THEN once you finish reading the problem, you realize X = 60
Overlapping Sets:
What is the process for overlapping sets problems?
- Recognize the problem
- Look for “categorization” of items in the Q text
- Set up matrix
- Think: What are we solving for?
- Fill out the Total Box!
- Ideally, use a # given to us for Total
- If not pinned down to a number, use a smart number
- OR you can use a variable (if they DO pin you down with a number in Q Text)
How shoudl you tackle the rates of two different things (vehicles, people, etc.) in these 2 scenarios:
1) When 2 things are working together (moving towards each other / travelling in opposite directions)
2) When 2 things are working against each other (1 thing is catching up to another)
1) ADD the rates!
IE…If X and Y are travlling towards each other at 20 MPH and 30 MPH respectively, they cut the rate down at 50MPH!
2) Subtract the rates!
IE…Final Rate = the work that the lagging piece needs to do
IE…Distance = distance that the lagging piece needs to make up
Two trains, X and Y, started simultaneously from opposite ends of a 100-mile route and traveled towards each other on parallel tracks. Train X, traveling at a constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at a constant rate, completed the 100 mile trip in 3 hours. How many miles had train X traveled when it met Train Y?
1) What is the key to work/rate problems?
2) If you’re using “real world” scenarios, what is an easy, organized technique to use?
1) Get something down on your fucking paper!!! Need to draw it out instead of visualizing it in your head!2) Use a DISTANCE CHART (starting at 0 hours, 0 distance, and see how the trains track over the hours) –> example in attachment
Two trains, X and Y, started simultaneously from opposite ends of a 100-mile route and traveled towards each other on parallel tracks. Train X, traveling at a constant rate, completed the 100-mile trip in 5 hours; train Y, traveling at a constant rate, completed the 100 mile trip in 3 hours. How many miles had train X traveled when it met Train Y?
1) If you’re using Algebra, what should the setup look like?
1) Draw a R/W chart!!!
2) Add these rates since they’re WORKING TOGETHER (moving towards each other)!
- X’s distance = 100 (making Y’s distance = 100 - x)
- ADD the rates (so 53 MPH = combined rate)
- They will travel the SAME TIME (just label this T)
- FINAL EQUATION: 100 = 53T
-Time will be a little under 2 hours…only answer can be A (since B = 40, and 40 would be at 2hours)
Car A is 20 miles behind Car B, which is traveling in the same direction along the same route as Car A. Car A is traveling at a constant speed of 58 miles per hour and Car B is traveling at a constant speed of 50 miles per hour. How many hours will it take for Car A to overtake and drive 8 miles ahead of Car B?
A) 1.5
B) 2.0
C) 2.5
D) 3.0
E) 3.5
- *Keys here:**
- Set up D = RT chart for both cars!
- Subtract Rates and use X’s Rate and Distance to solve (since this is lagging piece)
- Time is the same for both (so just use T)
- REMEMBER YOU HAVE 2 EQUATIONS (so can plug X = 50T into the equation X+28 = 58T)!!
Standard Deviation:
1) (+)(-): What happens to Standard Deviation if you add or subtract the same value to each number in the set?
1) (X)(/): What happens to Standard Deviation if you multiply or divide the same value to each number in the set?
1) If you ADD or SUBTRACT the same number to each number in the set, the SD stays the same
2) MULTIPLY: the SD gets larger (numbers are more spread out)
DIVIDE: the SD gets smaller (numbers are closer together)