Week 6 Integration 1 Flashcards

1
Q

how is the area under a curve found

A

integration

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2
Q

what is the integration addition rule

A

∫f(x) + g(x) dx = ∫f(x)dx + ∫g(x)dx

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3
Q

what is the integration constant rule

A

∫cf(x)dx = c∫f(x)dx

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4
Q

what is the integration reversed limits rule

A

b a
∫f(x) dx = - ∫f(x) dx
a b

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5
Q

what is the splitting up the range integration rule

A

b c b
∫f(x) dx = ∫f(x)dx + ∫f(x)dx
a a c

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6
Q

what is unique of odd functions integrated over symmetric limits (a, -a)

A

the integral is equal to 0

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7
Q

what is unique of even function integrated over symmetric limits (a, -a)

A

it is equal to two times the integration of one of the limits and 0 so the limits on this new integral are a and 0

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8
Q

what is the value of the perfect integral

∫ f’(x) / f(x) dx

A

ln[f(x)] + c

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9
Q

what is the value of the perfect integral

∫ f(x)f’(x) dx

A

1/2 f^2(x) +c

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10
Q

what is the value of the perfect integral

∫ f’(x) / sqrt[f(x)] dx

A

2[f(x)]^1/2 + c

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11
Q

how do we determine if an integral with a singularity diverges or not

A

we integrate close to the singularity

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12
Q

what is the 4 step procedure for integration by substiution

A

1 choose a reasonable substitution
2 differentiate to change variable of the integration
3 make the substitution
4 perform the integration

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13
Q

what is the value of the following standard integral and the appropriate substitution
∫ 1 / sqrt[a^2 - x^2]

A

value is arcsin(x/a) + c

substitution is x = asin(u)

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14
Q

what is the value of the following standard integral and the appropriate substitution
∫ 1 / sqrt[x^2 - a^2]

A

value is arccosh(x/a) + c

substitution is x = acosh(u)

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15
Q

what is the value of the following standard integral and the appropriate substitution
∫ 1 / sqrt[x^2 + a^2]

A

value is arcsinh(x/a) + c

substitution is x = asinh(u)

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16
Q

what is the value of the following standard integral and the appropriate substitution
∫ 1 / x^2 + a^2

A

value is 1/a arctan(x/a) + c

substitution is x = atan(u)

17
Q

what is the 4 step procedure for integrating using partial fractions

A

1 factorise denominator
2 separate into partial fractions
3 determine the values of the two denominators and sub back into expression
4 integrate the expression