Week 5: Glycolysis and the PPP Flashcards

1
Q

What are the starting materials of glycolysis? What other input is required in the priming phase?

A

Glucose, 2 ADP, 2Pi, 2 NAD+

2 ATP are required to create G-6-P and F-1,6-BP respectively

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2
Q

What are the products of glycolysis?

A

2 Pyruvate, 4 ATP, 2 H+, 2 NADH, 2 H20

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3
Q

What are the glycolysis intermediates and how do we remember them?

A

**Goodness = Glucose

Gracious = G-6-P

**Father = Fructose-6-P

*Franklin = Fructose-1,6-Bisphosphate

Did = Dihydroxyacetone Phosphate (DHAP)

*Go = Glyceraldehyde-3-Phosphate

*By = 1,3-Bisphosphoglycerate

Picking = 3-Phosphoglycerate

Pumpkins = 2-Phosphoglycerate

to

Prepare = Phosphoenolpyruvate

**Pies = Pyruvate

* = key steps, reversible and

** = key steps, irreversible

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4
Q

What are the glycolysis enzymes and how do we remember them?

A

Hungry = Hexokinase

Peter = Phosphohexose Isomerase

Pan = PFK-1

And = Aldolase

The = Triose Phosphate Isomerase

Growling = G3P Dehydrogenase

Pink = Phosphoglycerate kinase

Panther = Phosphoglycerate mutase

Eat = Enolase

Pies = Pyruvate kinase

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5
Q

What are the ways that we can regenerate NAD+

A

Aerobically in mitochondria: 2 NADH + 2H+ + O2 => 2 NAD+ + 2H2O

Anaerobically in the cytosol: Pyruvate + 2 NADH + 2H+ => L-lactate + 2 NAD+

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6
Q

What are the main purposes of the PPP?

A

(1) To produce NADPH + H+ from NADP+
(2) to synthesize ribose-5-phosphate for biosynthesis

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7
Q

What does the carbohydrate product of the PPP feed into?

A

The ribose-5-phosphate from the PPP feeds into the de novo nucleotide biosynthesis pathway, and is converted to PRPP by PRPP synthetase, then to 5-phosphoribosylamine by glutamine-PRPP amidotransferase

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8
Q

What is the key step of the PPP and why is it important?

A

The G-6-P dehydrogenase enzyme (first step) converts NADP+ to NADPH + H+ a

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9
Q

What are the two phases of the PPP and why are they important?

A

(1) The oxidative phase converts G-6-P to 2 NADPH + 2 H+, and the…
(2) Nonoxidative phase uses transketolases/transaldolases to return unused ribulose-5-phosphate to G-6-P

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10
Q

What is NADPH used for? What is the main point of this process, and what cells in the body use it in particular?

A

It is used as a reducing cofactor for the glutathione reductase reaction, reducing oxidized glutathione molecules (GSSG) to 2 GSH molecules

This is a key means by which the body reduces reactive oxygen species (ROS). The RBCs of the body use this mechanism because they don’t have mitochondria that would help them neutralize ROS otherwise.

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11
Q

Explain how favism relates to the PPP

A

Favism is the result of a deficiency in G-6-P dehydrogenase, leading to a lack of NADPH to reduce ROS. If patients with this disease eat fava beans, the metabolites can produce dangerous superoxide radicals and H2O2 (hydrogen peroxide) that can damage tissues and cells–especially RBCs.

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12
Q

Why is step 1 of glycolysis significant in terms of (1) thermodynamics and (2) biochemical pathways?

A

(1) Large, -ΔG due to the energy released from ATP bond severing, large -ΔH
(2) Phosporylating glucose traps it in the cell, and prevents it from traveling outwards through GLUT transporters. Further, G-6-P can enter other pathways including the PPP.

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13
Q

Why is step 3 of glycolysis significant in terms of (1) thermodynamics and (2) the glycolysis pathway? What allosteric regulators are involved, and (3) what is the extra-glycolytic molecule that helps regulate it?

A

(1) Large, -ΔG due to the energy released from ATP bond severing, large -ΔH, IRREVERSIBLE
(2) This is a regulatory step of glycolysis–ATP will inhibit PFK-1 and ADP/AMP and citrate will activate it (conveys need for acetyl-CoA)
(3) fructose 2,6-bisphosphate is synthesized from high amounts of fructose-6-phosphate. Fructose 2,6-bisphosphate allosterically activates PFK-1 because it acts as a proxy, telling PFK-1 there’s lots of F-6-P around to use

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14
Q

Why is step 4 of the glycolysis pathway significant thermodynamically (1), what does it produce as intermediates (2), and why does it move forward (3)?

A

(1) There is a large +ΔG required to break the bonds of the F 1,6-BP molecule, but Le Chatelier prevails!
(2) G3P is made and keeps moving through the glycolytic pathway, and DHAP can be converted by triose phosphate isomerase OR shunted into the FA pathway to serve as a substrate for TAG production
(3) Because the G3P products of the reaction are removed so quickly, the reaction continues moving forward despite a +ΔG

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15
Q

Why is step 6 of glycolysis significant and reversible (1)? What drives the reaction forward (2) and why is ΔG not negative (3)?

A

(1) this step adds another INORGANIC phosphate group to G3P, and uses the high energy generated from severing the aldehyde bond to produce NADH
(2) Renewal of NAD+ substrate to be reduced to NADH drives the reaction forward
(3) IF the phosphate group were added via ATP bond-breaking, this reaction would likely be irreversible. HOWEVER, an inorganic phosphate is added, demanding some energy and creating a +ΔG

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16
Q

Why is step 7 of glycolysis significant (1)? What is produced, (2) and is the reaction reversible or irreversible (3)?

A

(1) This is the first ATP-generating step in glycolysis.
(2) It forms ATP from ADP and 1,3-bisphosphoglycerate
(3) Despite a large -ΔG, this reaction is reversible. However, that step will help drive the next two reactions foward, depleting the products and again favoring products thanks to MY GUY CHATELIER

17
Q

Why is step 10 of glycolysis significant (1)? What occurs in this step (2), and what are the thermodynamics of the reaction (3)?

A

(1) In this step, 1 ATP is formed for each pyruvate molecule (2 ATP net per glucose, or +2 ATP overall). It is also almost completely IRREVERSIBLE
(2) In this step, PEP transfers it’s phosphate group to ADP forming ATP
(3) This reaction has a very -ΔG and -ΔH thanks to the formation of ATP, and due to the fact that pyruvate is consumed almost immediately, so there will never be enough to drive the reaction backwards

18
Q

Describe the function that key enzymes of glycolysis perform for the overall pathway

A

(1) Hexokinase phosphorylates glucose to glucose-6-phosphate from ATP in an irreversible fashion (under intracellular conditions)–an irreversible reaction is an energy “waterfall”–can’t go back up. Phosphorylation also prevents glucose from exiting the cell through the GLUT4 transporter it came in through (1 ATP input) ΔG = -16.7 kJ/mol, irreversible

…after (2) isomerization to Fructose-6-phosphate…

(3) Phosphofructokinase-1 primes F-6-P with another phosphate group from ATP, forming Fructose 1,6-bisphosphate. (1 ATP input) ΔG = -14.2 kJ/mol, irreversible (also waterfall)
(4) Aldolase cleaves F 1,6-bP to Dihydroxyacetone phosphate (DHAP) and Glyceraldehyde-3-phosphate (G3P). ΔG = 23.8 kJ/mol, reversible

–> triose phosphate isomerase converts DHAP to G-3-P in a preparatory step

(5) Glyceraldehyde-3-phosphate dehydrogenase (GAPDH) forms 1,3-Bisphosphoglycerate from a Pi molecule. The binding energy that is released is absorbed to form an NADH from NAD+, which must be generated to sustain the forward reaction (1 NADH produced). ΔG = 6.3 kJ/mol, reversible
(6) Phosphoglycerate kinase forms 2 ATP (one each from each GAP molecule formed from glucose) and 2 molecules of 3-phosphoglycerate in the first payoff step of the reaction. ΔG = -18.5 kJ/mol, irreversible

…(7) phosphoglycerate mutase transfers phosphate group to middle of 3-phosphoglycerate, making 2-phosphoglycerate. ΔG = 4.4 kJ/mol…

…(8) enolase performs a dehydration reaction on 2-phosphoglycerate to form phosphoenolpyruvate (PEP) (1 H2O produced). ΔG = 7.5 kJ/mol, reversible

(9) Pyruvate kinase transfers the phosphate group on phosphoenolpyruvates to ADP, forming 2 ATP (two PEP molecules from the earlier cleavage step). ΔG = -31.4 kJ/mol, highly irreversible

19
Q

Explain metabolites and conditions that influence the rate of the forward reaction of glycolysis and how they exert their effect

A
20
Q

Explain the different ways glycolysis proceeds under aerobic and anaerobic conditions

A

Under aerobic conditions, 2 NADH, 2 H+ along with O2 from breathing use electrons to pump H+ ions across the mitochondrial membrane. 2 NAD+ are regenerated via oxidative mechanisms.

Under anaerobic conditions, NAD+ is regenerated from NADH by reducing pyruvate to L-Lactate in a highly favorable reaction catalyzed by lactate dehydrogenase. The majore disadvantage is that NADH cannot send its high-energy electrons through the ETC, and though the reaction proceeds very quickly/explosively, the low ATP yield via lactate fermentation cannot be sustained for long.

22
Q

Describe the multiple functions of glycolytic enzymes including key intermediates like dihydroxyacetone phosphate

A
23
Q

Describe the functions performed by the pentose phosphate pathway (PPP)

A

G-6-P has a carbon removed and oxidized to CO2. In the process, 2 NADPH molecules are generated along with D-Ribose 5-phosphate, which are used to make nucleotides. The main purpose is to generate NADPH and D-Ribose 5-phosphate. The first step is dehydrogenation of G-6-P to 6-phosphoglucono-δ-lactone by glucose-6-phosphate dehydrogenase.

The most important aspect of the PPP is the production of substrates for biosynthesis, including for fatty acid biosynthesis and inactivation of reactive oxygen species (ROS). Glutathione (GSSG) acts as a ROS neutralizer.

24
Q

Explain a disease (favism) associated with a deficiency in the PPP

A

Respiration and oxidants such as divicine (found in fava beans) can generate free oxygen radicals. These can be transformed into highly reactive hydrogen peroxide and hydroxyl free radicals, which cause oxidative damage to lipids, proteins, and DNA.

Glutathione peroxidase can oxidize hydrogen peroxide to water using glutathione.

Favism is a when a genetic deficiency of glucose-6-phosphate dehydrogenase (forms NADPH to reduce glutathione that has absorbed free radicals) allows for oxidative stress from fava beans to produce free radicals that damage tissue in those suffering from the disease.

25
Q

Explain the bioenergetics of the glycolytic pathway, involving entropy, enthalpy, and the overall ΔG of the reaction

A

Glycolysis is a function of (1) ΔH–the exothermic or endothermic nature of the overall and individual reactions, (2) ΔS, the entropy produced (should be negative and high), and, overall, a highly -ΔG for the whole pathway. Remember that enzymes can only lower the barrier of activation, and DO NOT change the overall ΔG.

26
Q

What are the starting materials and products of glycolysis?

A

Starting Materials:

Glucose

2 ADP

2 Pi

2 NAD+

Products:

2 pyruvate

2 ATP

2 H+

2 NADH

2 H2O

27
Q

What is the definition of fermentation?

A

When ATP is generated without net oxidation of a metabolic fuel (i.e. glycolysis proceeding to produce lactate through the fermentation pathway)

28
Q

Explain the regulation of PFK-1

A

Phosphofructokinase-1 is allosterically inhibited by high levels of ATP (don’t need the forward reaction to produce more), and is allosterically activated by high levels of AMP and ADP (need the forward reaction to produce more). High levels of citrate (end product of TCA cycle) inhibit PFK-1 and fructose 2,6-bisphosphate activates PFK-1 (phosphorylated by PFK-2–the small pool of F 2,6-bP is created at the same time as PFK-1 substrates accumulate, signaling to PFK-1 to generate the forward reaction)