Week 3 - Filtration by the glomerulus Flashcards

1
Q

How does the renal artery divide?

A

Renal artery → segmental arteries → interlobar arteries → arcuate arteries → interlobular arteries → afferent arterioles

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2
Q

What is the role of afferent arterioles?

A
  • The afferent arterioles each deliver blood to a single nephron
  • The diameter of each afferent arteriole is slightly greater than the diameter of the associated efferent arteriole
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3
Q

Describe glomerular filtration

A

The diameter difference between the afferent and efferent arteriole increases the pressure of the blood inside the glomerulus

  • This increased hydrostatic pressure helps to force the below components out of the blood in the glomerular capillaries
  • – Most of the water
  • – Most/all of the salts
  • – Most/all of the glucose
  • – Most/all of the urea
  • Only 20% of the delivered blood is actually filtered, 80% exits via the efferent arteriole
  • These are all filtered as they are relatively small particles
  • RBCs and plasma proteins are not filtered because they are too large
  • The water and solutes that have been forced out of the glomerular capillaries pass into the Bowman’s space and are called the glomerular filtrate or the ultrafiltrate
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4
Q

Why does the basement membrane and podocytes not allow protein movement?

A

They have negatively charged glycoproteins, which repel protein movement
- This charge can be lost in many diseases, causing proteinurea

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5
Q

Describe the renal filtration barrier

A

There are 3 layers to pass through

  • Capillary endothelium
  • – Water, salts, glucose
  • – Filtrate moves between cells
  • Basement membrane
  • – Acellular gelatinous layer of collagen/glycoproteins
  • – Permeable to small proteins
  • – Glycoproteins repel protein movement
  • Podocyte layer
  • – Pseudopdia interdigitate to form filtration slits
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6
Q

Which forces are involved in plasma filtration?

A
  • Hydrostatic pressure in the capillary (favours filtration)
  • Hydrostatic pressure in the Bowman’s capsule (opposes filtration)
  • Osmotic pressure difference between the capillary and tubular lumen (opposes filtration)
    Net filtration pressure = 10mmHg
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7
Q

What is tubular reabsorption?

A
  • Only about 1% of glomerular filtrate actually leaves the body
  • The rest is reabsorbed into the blood while it passes through the renal tubules
  • This recovery process is called tubular reabsorption
  • There are 3 mechanisms
  • – Osmosis
  • – Diffusion
  • – Active transport
  • The majority of the glomerular filtrate is reabsorbed in the PCT
  • – Includes some water and all of the glucose
  • An energy demanding process
  • – Mostly for the reabsorption of Na+ ions
  • – Reabsorption of other things in the filtrate is coupled to the active reabsorption of Na+ ions
  • – Na+ is pumped out of tubular cells across the basolateral membrane by 3Na-2K-ATPase
  • – Na+ moves across the apical membrane down its concentration gradient
  • – Water moves down the osmotic gradient created by the reabsorption of Na+
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8
Q

Describe renal secretion

A
  • Provides a 2nd route, other than glomerular filtration, for solutes to enter the tubular fluid
  • Useful as only 20% of plasma is filtered each time the blood passes through the kidney
  • Helps to maintain blood pH
  • Substances secreted into the tubular fluid:
  • – Protons
  • – Potassium
  • – Organic anions and cations
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9
Q

Describe a model for organic cation secretion in the PCT

A
  • Entry by passive carrier:
  • – Mediated diffusion across the basolateral membrane down favourable concentration and electrical gradients, created by the 3Na-2K-ATPase pump
  • Secretion into the lumen:
  • – H+-OC+ exchanger that is driven by the H+ gradient created by the Na+-H+ antiporter
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10
Q

Describe reabsorption in the PCT

A

Reabsorption in the PCT is isosmotic

  • Driven by sodium uptake
  • Other ions accompany sodium to maintain electro-neutrality (e.g. chloride and bicarbonate)
  • Solutes move from tubular lumen → intersticium → capillaries
  • Reabsorption can be transcellular or paracellular
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11
Q

What is the role of active transport and co-transport in tubular reabsorption and secretion?

A

Different segments of the tubule have different types of Na+ transporters and channels in the apical membranes

  • Allows Na+ to be the driving force for reabsorption, using the concentration gradient set up by 3Na-2K-ATPase
  • – Proximal tubule = Na-H antiporter, Na-Glucose symporter (SGLUT)
  • – Loop of Henle = Na-K 2Cl symporter
  • – Early distal tubule = Na-Cl symporter
  • – Later distal tubule and collecting duct = ENaC
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12
Q

How is glucose reabsorbed?

A

Reabsorbed in the PCT using the Na-glucose symporter (SGLUT)

  • Moves against its concentration gradient
  • Moves into the tubule cells
  • Glucose then moves out of the tubule cell on the basolateral side by facilitated diffusion
  • 100% of glucose is normally reabsorbed
  • System has a maximum capacity (transport maximum, Tm)
  • – If the plasma concentration exceeds Tm, the rest spills over into the urine
  • – If this happens, water follows into the urine, causing frequent urination (polyuria)
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13
Q

What is clearance?

A

Clearance = the volume of plasma from which a substance can be completely cleared to the urine per unit time

  • Clearance = (amount in urine x urine flow rate) / arterial plasma concentration
  • Significance: Used to measure glomerular filtration rate
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14
Q

What is the glomerular filtration rate?

A
  • The volume of plasma from which any substance is completely removed by the kidney in a given amount of time
  • A measure of the filtration process of all the nephrons
  • A measure of kidney function
  • Normal GFR for males = 115-125 ml/min
  • Normal GFR for females = 90-100 ml/min
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15
Q

How can you measure GFR?

A
  • A substance must be freely filtered across the glomerulus
  • This substance must not be reabsorbed, secreted or metabolised by the cells of the nephron
  • Must pass directly into the urine
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16
Q

How do you work out the renal plasma flow?

A
  • The kidney receives ~1.1 litres of blood a minute
  • About 45% of this is RBCs and 55% is plasma
  • We can hence calculate renal plasma flow: 55% of 1.1L = 605ml/min of plasma
17
Q

What is the filtration fraction?

A
  • The proportion of a substance that is actually filtered
  • FF = glomerular filtration rate / renal plasma flow
  • About 20%
18
Q

Describe the auto regulation of renal blood flow

A
  • Autoregulatory mechanisms keep the GFR within normal limits when arterial BP is within physiological limit (80-180mmHg)
  • The purpose of autoregulation of renal blood flow is to maintain GFR
  • Selective vasoconstriction or dilatation must occur to maintain renal blood flow at a constant rate
  • Mediated by the combined and interacting contributions of 2 mechanisms:
  • – Myogenic response
  • – Tubular-glomerular feedback
19
Q

What happens in the myogenic response?

A

Due to the smooth muscle in the walls, which resists stretching

  • If arterial BP rises → afferent arteriole constriction
  • If arterial BP falls → afferent arteriole dilation
20
Q

What happens in tubular-glomerular feedback?

A
  • Changes in tubular flow rate as a result in changes in GFR change the amount of NaCl that reaches the distal tubule
  • Macula densa cells can respond to these changes
  • – If NaCl increases: adenosine is released, causing vasoconstriction of afferent arteriole
  • – If NaCl decreases: prostaglandins released causing vasodilation of afferent arteriole