Waves and Acoustics Flashcards
The general equation for a harmonic oscillator (Sec. 1) is:
m d2ψ/dt2 = −sψ − b dψ/dt + F0 cos ωf t.
where m is the mass of the oscillator, s is a stiffness (and gives the restoring force), b is a resistance or damping and the driving force F0 oscillates at frequency ωf.
Solution of the general equation:
Acos(wt+phi)
A simple harmonic oscillator will respond at a frequency:
ω = ω0 = sqrt(s/m)
A driven harmonic oscillator will respond at:
the driving frequency ωf in the steady state
The impedance is defined as
the amplitude of the driving force divided by the complex amplitude of the oscillator velocity
Two (or more) oscillations can be
added to give a resulting oscillation
With the same frequency, the resultant can be found using
a phasor diagram or complex exponential arithmetic
• With different frequencies, the phenomenon of ____ is found. What is the equation?
ψ(t) = A cos ω1t + A cos ω2t = 2A cos ωt cos ∆ωt.
where ω = (ω1 + ω2)/2 and ∆ω = (ω1 − ω2)/2
Normal modes (Sec. 1.5) are
collective, harmonic motions of coupled oscillators
By considering combinations of the oscillators (for two, the sum and difference motions) we find
simple harmonic solutions
The wave equation (Sec. 2) is
where c is the speed of points of constant phase, or phase velocity.
Speed of a wave on a stretched string
c = sqrt(T / mu) with T the tension and µ the mass per unit length
The most general solution for the wave equation is
ψ(x, t) = f(x − ct) + g(x + ct)
When there is periodic motion, we write _____________ with k = ___ and λ (________) and ω =_____ is the angular frequency, f is the ____ and T ______ (or the time interval between two peaks or troughs)
- ψ(x, t) = f(kx − ωt) + g(kx + ωt)
- 2π/λ
- the wavelength (or distance between two peaks or two troughs)
- 2πf = 2π/T
- frequency
- time period
What is the solution for ψ(x, t), for a general periodic wave?
Aei(kx−ωt+φ)
There is energy associated with a wave: for a stretched string, the potential energy is
1/2 T A2k2sin2 (kx − ωt)