W7 Flashcards
Calculating gibbs with multiple gases
G = NaUa + NbUb
Where Ua and Ub are the chemical potentials of gases A and B
High chem potential
Addition causes free energy to increase resulting in a high free energy for the system
Low chem potential
Addition causes free energy to increase only slightly
Higher free energy means
Higher driver for spontaneous reaction
Remember everything tries to loose its free energy to surroundings
When a reaction occurs the system goes in what direction
Direction of high chem potential to low until net potentials of products and reactanats balance
Equi constant equation
K = [C]c[D]d / [A]a[B]b
Le chateliers principle
When external change is made to a system the system responds to oppose the change. If OH is added to the left the equi will move to the right
3mols on the left and 2 mols on right, the forward reaction is favoured so equi moves right
More reactants the equi moves right
Moe products the equi moves left
If T increases
Equi move in endo direction to produce heat
If T decreases
Equi move in exo direction to release hear
If P increases
Equi move to side which would reduce pressure = side with less mols
If P decrease
Equi move to side which would increase pressure = side with more mols
Gibbs using equi constant equation
△G = -RT ln(k)
Van hoff equaiton
Derived from △G=-RTln(k) and △G= △H-T△S to give:
ln(k) = (△S/R) - (△H / RT)
Molarity
Number of moles of solute in 1 L of solution
Molality
Number of moles of solute in 1000 g of solvent
Mole fraction
Number of moles of the solute divided by the total number of moles of the solute plus the solvent