Vectors Flashcards

1
Q

Two types of measurable quantity

A

Scalar

Vector

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2
Q

Scalar

A

A quantity with a magnitude (size)

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3
Q

Vector

A

A quantity with a magnitude and direction

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4
Q

When multiplying a vector by a scalar, what stays the same and what changes

A

The direction remains the same, the magnitude changes

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5
Q

Component form of vector

A

( x y z )

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6
Q

given the points P (3,4), Q(5,2) and O (0,0), find the vector joining them

A

(2, -2)

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7
Q

PQ = ?

A

q - p

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8
Q

How is magnitude written

A

|u| or |AB|

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9
Q

How is magnitude of a vector calculated

A

Using Pythagoras

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10
Q

|PQ| = ?

A

/a^2 + b^2

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11
Q

What is a unit vector

A

A parallel vector to the original vector with a magnitude of 1

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12
Q

Unit vector magnitude

A

/l^2 + m^2 + n^2 = 1

l^2 + m^2 + n^2 = 1

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13
Q

How to find unit vector of original vector

A

Divide original vector by its magnitude

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14
Q

How many unit vectors does a vector have

A

Two, +ve and -ve

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15
Q

Method for unit vectors

A

Find magnitude of original vector

Divide vector by its length

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16
Q

Find the components of the unit vector, u, parallel to vector v if v = (3 4 )

A

( 3 / 5, 4 / 5 )

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17
Q

Find two unit vectors of the vector a = ( 12, 3, 4 )

A

+ - ( 12/13 , 3/13, 4/13)

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18
Q

What to use to find a component of a unit vector

A

/ l^2 + m^2 + n^2 = 1

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19
Q

u = (a, 1/3, 1/3) is a unit vector.

Find the two values of a

A

+ - /7 / 3

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20
Q

Method for proving unit vector

A

Use l^2 + m^2 + n^2 = 1

Statement to prove

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21
Q

Is (2/3 1/3 -2/3 ) a unit vector

A

Yes since l^2 + m^2 + n^2 = 1

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22
Q

Orgin coordinates

A

0, 0

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23
Q

0, 0

A

Origin

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24
Q

unit vector i

A

( 1 0 0)

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25
( 1 0 0)
Unit vector i
26
Unit vector j
( 0 1 0)
27
( 0 1 0)
Unit vector j
28
Unit vector k
( 0 0 1)
29
( 0 0 1)
Unit vector k
30
i, j, k =
i = x j = y k = z
31
Express 4i - 8j + 3k in component form
( 4 -8 3)
32
Express 7j - 2k in component form
( 0 7 -2)
33
Express (2 5 -1) in the form of i, j, and k
2i + 5j - k
34
Express (-2 0 5) in the form of i, j, and k
-2i + 5k
35
The vector, a, has the components (-3 0 4). Find the unit vector parallel to a in the form i, j, k.
(-3/5 0 4/5) = -3/5i + 4/5k
36
Parallel vectors relationship
if vector u = ( x y ), then ku = (kx ky)
37
Method for proving if 2 vectors are parallel
1. Take out highest common factor in each vector 2. Check for same vector 3. Express vector in terms of other
38
Prove u = (2 3) and v (6 9) are parallel
3u = v
39
Show a = (6 -2) and b = (21 -7) are parallel
a = 2/7b
40
show that p = (4 -10) and q = ( -6 15) are parallel
p = 2/-3q
41
are c = (12 9) and d = (16 8) parallel?
No, (4 3) ≠ ( 2 1)
42
Proving collinearity of vectors method
1. Find vector of first 2 coordinates 2. Find vector of last 2 coordinates 3. Statement
43
Prove the points A (2, 4) B (8, 6) and C (11, 7) are collinear with vectors
2BC = AB so parallel and share common point B
44
Prove the points A (0, 1, 2) B (1, 3, -1) and C (3, 7, -7) are collinear with vectors
Parallel since 2BC = AB and share common point B
45
Prove the points A (2, -3, 4) B (8, 3, 1) and C (12, 7, -1) are collinear with vectors
AB = 2/3 BC so parallel and common point B
46
The points A (-8, a, -12) B (2, -5, 3) and C (6, -15, b) are collinear. Find a and b
a = 20 b = 9
47
Section formula
na + mb/ ( m + n ) remember, A P B m n
48
P divides AB internally in the ratio 3:2. How do you write this
AP:PB = 3:2
49
P divides AB externally in the ratio 3:2. How do you write this
AP:PB = 3:-2 OR -3:2
50
Section formula method
1. Identify ratio and points 2. Use cross method to match up points and ratio 3. Sub into formula 4. Solve
51
AP:PB = 2:5 Find P, given that A is (3, 4) and B is (17, 11)
(7, 6)
52
P divides AB in the ratio 3:2 Find P given that A is (2, -3, 4) and B is (12, 7, -1)
P is (8, 3, 1)
53
Triangle ABC has the vertices A (3, 0, 6), B (0, 3, -3) and C (1, 0, -4). P divides AB in the ratio 1:2, Q is the midpoint of AC and R divides BC externally in the ratio 2:1. Find the coordinates of P, Q and R.
P = (2, 1,3) Q = (2, 0, 1) R = (2, -3, -5)
54
Find the coordinates of the point dividing joining E (5, 2, 1) and F (9, 10, 13). It divides externally in the ratio 1:3
(3, -2, -5
55
VABCO is a pyramid. AB = 8i + 2j + 2k AD = -2i + 10j - 2k AV = i + 7j + 7k Express CV in component form
( -5 -5 7)
56
EABCD is a pyramid EA = -7i - 13j - 11k AB = 6i + 6j - 6k AD = 8i - 4j + 4k K divides BC in the ratio 1:3. Find EK
EK = i- 8j - 16k
57
RATU, VWXY is a cuboid Express VT in terms of f, g, and h
- f - h + g
58
Scalar product equation (3 forms)
a.b = |a| |b| cos0 Where 0 is the angle between a and b (underlined) a.b = a1b1 + a2b2 + a3b3 Where a = (a1 a2 a3) and b = (b1 b2 b3) Cos0 = a.b / |a||b|
59
3 things to remember with scalar product
Vectors must be pointing away from the angle The scalar product is a scalar, not a vector! The an and b (underlined) are perpendicular, then a.b = 0
60
Find scalar product:
6
61
Find scalar product
1/2
62
Find scalar product:
0
63
Find the scalar product
-1
64
Find the scalar product:
-6
65
Find the scalar product:
-10 root 3
66
Find scalar of a (1 2 5) and b (-1 1 -2)
-9
67
Given P (1, 5, 8), Q (-2, 1, 3) and R (1, -6, 0), if PQ represents u and QR represents v, find u.v.
u.v = 34
68
S is (1, 2, -3), T is (11, -3, 7) U divides ST in the ratio 3:2. Find: Coordinate of U Value of SU.UT
a) (7, -1, 3) b) 54
69
Angle between two vectors formula
Cos0 = a.b / |a||b|
70
a = i + 2j + 2k and b = 2i + 3j + 6k. Calculate the angle between a and b (underlined a and b in all text)
17.8 degrees
71
Show that an and b are perpendicular if a = (2 3 -6) and b = (-3 2 0). a and b underlined
a.b = 0 since perp. Cos90 = 0
72
Vectors a = 2i - 5j + k and b = pi - 2j + 3k are perpendicular. (a and b underlined) Find the value of p
p = -7
73
R is (4, 4, 1) S is (3, 2, 0), T is (2, 0, 1). Calculate the size of the angle RST
131.8
74
scalar product if 0 < theta < 90
+ve
75
Scalar product if theta = 90
0
76
scalar product if 90 < theta < 180
-ve
77
a.(b + c) expanded
a.b + a.c
78
(a + b) . (c + d) expanded
a.c + a.d + b.c + b.d
79
unit vector.unit vector
0
80
let a = 2i - k, b = i + 2j + k, c = -j + k. evaluate a.b + a.c make a deduction and about a and b + c
a.b + a.c = 0 a is perpendicular to b + c
81
26
82
16
83
-36