Unit 3 - Differentiation: Composite. Implicit, and Inverse Functions Flashcards

1
Q

Composite function

A

Function inside another function

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2
Q

Chain Rule is used to find the

A

Derivative of composite functions

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3
Q

d/dx f(g(x)) =

A

f’(g(x)) * g’(x)

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4
Q

Explicit equation

A

Equation that is set to be equivalent to y

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5
Q

Implicit euqation

A

Equation that is not set to be equal to y

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6
Q

d/dx x =

A

1

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7
Q

d/dx y

A

dy/dx

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8
Q

To implicitly differentiate,

A

1 - take derivative normally, each time a ‘y’ is involved, include a dy/dx
2 - gather all terms with dy/dx on left side, everything else on right
3 - factor out dy/dx if necessary to create only one dy/dx term
4 - solve for dy/dx

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9
Q

To find slope with an implicit derivative,

A

you need both x and y values

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10
Q

To find equation of a tangent line for an implicitly differentiable equation, you need to

A

1 - find y and x values
2 - find the derivative using implicit differentiation
3 - use derivative to find slope at points
4 - substitute values into y -y1 = m (x-x1)

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11
Q

Horizontal tangent

A

Exists when slope is equal to zero

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12
Q

To calculate horizontal tangent for an implicit equation

A

1 - take derivative and set equal to zero
2 - numerator is equal to zero and solve
3 - substitute x-value into original equation to find y-value

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13
Q

Vertical tangent

A

Exists when slope is undefined

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14
Q

To calculate vertical tangent for an implict equation

A

1 - take derivative and set equal to undefined
2 - denominator is equal to zero and solve
3- substitute y-value into original equation to find x-value

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15
Q

Inverse function

A

Can be found by swapping input and output

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16
Q

Three ways to say that f and g are inverses

A

f is the inverse of g
g(x) = f-1(x)
f(g(x)) = x and g(f(x)) = x

17
Q

d/dx [f-1(x)] =

A

1 / f’ * [f-1(x)]

18
Q

Inverse trig function notation

A

notation with a “-1” as in “sin-1(x)”

with prefix “arc” as in arcsin

19
Q

d/dx sin-1(x) =

A

1 / square root of (1 - x^2)

20
Q

d/dx cos-1(x) =

A
  • 1 / square root of (1 - x^2)
21
Q

d/dx sec-1(x) =

A

1 / |x| square root of (x^2 - 1)

22
Q

d/dx csc-1(x) =

A
  • 1 / |x| square root of (x^2 - 1)
23
Q

d/dx tan-1(x) =

A

1 / x^2 + 1

24
Q

d/dx cot-1(x) =

A
  • 1 / x^2 + 1
25
Q

For inverse trig derivatives,

A

Use derivative multiplied by derivative of value in parentheses

26
Q

In order to simplify inverse trig derivatives,

A

1- determine whether den/nom is pos/neg
2- simply num with den and leave square root alone
3- determine if you need an absolute value

27
Q

For inverse trig function, the domain and range

A

of their normal trig function are switched

28
Q

Higher order derivatives notation

A

y^(n) or d^ny / dx^n

29
Q

Second derivative

A

Derivative of the derivative

30
Q

When calculating second der. with implicit diff.,

A

A dy/dx with remain, then you substitute