Unit 1:3 (pt 1) Flashcards
Find the percentage mass
- Find Mr of compound
- Find Mr of the element
- %= 1st step/ 2nd step x 100
Using ratio
If 350g of A produces 600cm3 of B. How much B will be produced from 175g of A.
- Ratio = A:B
350g : 600cm3
175g: Xcm3
2.Put X on top right side
175:X
350:600
- Rearrange
(175x600)/350 = X
Figure out how many particles are in compounds / number of molecules
Number of moles x avogadro’s constant (6.02x10^23)
Moles,mass, Mr formula
Mass
n x Mr
Number of atoms in Xg
number of molecules x number of atoms in compound
Calculations Involving Reacting Masses
- Calculate the number of moles
- Look at the ratio
- calculate the mass
Empirical Formula
- Mass (g) of each element
- Calculate number of moles
- Divide by the smallest
Molecular Formula
actual ratio of atoms in the molecule
The Mr must be the same as the molecule’s actual Mr
Determination of xH2O
- Calculate the moles of anhydrous compound
- Calculate the moles of H2O lost.
- Ratio
moles of H2O lost / moles of anhydrous compound
Percentage Yield equation
% = (actual yield/ theoretical yield) x 100
Actual yield
mass in grams of the purified product after it has been dried
Theoretical yield
What should be produced for a 100% yield
Why can’t percentage yields always be 100%?
The reaction is reversible
Filtration
Transferring liquids
Unexpected reactions
Atom economy equation
%atom economy = (Mr of useful products/ Mr of all reactants) x 100
Reasons for good and bad atom economy
> HIgh a.e is better for profits and environment.
making lots of waste=problem
low a.e use resources quickly, produce lot of waste materials that need to be disposed. = unsustainable, raw materials run out.
low a.e aren’t profitable
raw materials = expensive
waste products expensive to remove
more than 1 way to create a product = find a reaction that gives useful by-products
highest a.e = ones with 1 product