UMP Test Flashcards
Uniformly Most Powerful (UMP) Test
A hypothesis test that is most powerful for all values in the alternative hypothesis space. Maximizes power uniformly over composite alternatives.
UMP Test Conditions
- Size condition: max P(X in R* | θ in H0) = α. 2. Power condition: for all θ in H1, P(X in R* | θ) ≥ P(X in R | θ) for any other test R of size α.
UMP Test: Step 1
Reduce the problem to a simple vs. simple test by selecting a specific parameter value (e.g., λ1 > λ0) from the composite alternative.
UMP Test: Step 2
Construct the most powerful test using Neyman-Pearson lemma for H0: λ = λ0 vs. H1: λ = λ1.
Likelihood Ratio Test for Exponential
Reject H0 if (λ0/λ1)^n * exp(-(λ0 - λ1) * sum Xi) ≤ c. Rejection region depends on whether λ1 > λ0 or λ1 < λ0.
Rejection Region for λ1 > λ0
Reject H0 if 2λ0 * sum Xi < χ²_{1-α, 2n}. This is a lower-tailed test using the chi-square distribution.
Rejection Region for λ1 < λ0
Reject H0 if 2λ0 * sum Xi > χ²_{α, 2n}. This is an upper-tailed test using the chi-square distribution.
Chi-Square Relation
If Xi ~ Exp(λ), then 2λ * sum Xi ~ χ²_{2n}. Used to derive the critical region of the UMP test.
UMP for Two-Sided Alternative?
No UMP test exists for H1: λ ≠ λ0 because different values of λ1 require different rejection regions. No single region works uniformly.
Key Insight for UMP Tests
A UMP test for one-sided alternatives can be derived using Neyman-Pearson if the rejection region does not depend on specific λ1, only its inequality to λ0.