Two Tests (Exponential Distribution) Flashcards

1
Q

What is the parameter of interest in the Two Tests lecture?

A

The rate parameter λ of the Exponential distribution.

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2
Q

What are the hypotheses in the first test?

A

H0: λ = λ0 vs. HA: λ > λ0.

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3
Q

What statistic is used in the first test?

A

The sample mean X̄.

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4
Q

Why does a larger λ lead to a smaller X̄?

A

Because the mean of Exp(λ) is 1/λ, so increasing λ decreases expected values.

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5
Q

What is the rejection rule in the first test?

A

Reject H0 if X̄ < c.

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6
Q

How is X̄ related to the chi-squared distribution?

A

2nλX̄ ~ χ² with 2n degrees of freedom.

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7
Q

How do you compute the critical value c for the mean test?

A

c = χ²_{1−α,2n} / (2nλ0).

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8
Q

What R function is used to compute chi-square quantiles?

A

qchisq(probability, df).

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9
Q

What statistic is used in the second test?

A

The sample minimum Yₙ.

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10
Q

What is the rejection rule in the second test?

A

Reject H0 if Yₙ < c.

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11
Q

How is the sample minimum Yₙ distributed?

A

Yₙ ~ Exp(nλ).

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12
Q

How do you compute the critical value c for the minimum test?

A

c = -log(1−α) / (nλ0).

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13
Q

What is the power function?

A

The probability of rejecting H0 as a function of λ.

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14
Q

How does the power function behave for the mean-based test?

A

Increases quickly with λ and depends on n.

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15
Q

How does the power function behave for the minimum-based test?

A

Increases slowly and does not depend on n.

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16
Q

Which test is better and why?

A

The test based on X̄ is better because it has higher power and uses more information.

17
Q

Why is the minimum not a great test statistic?

A

Because it always piles near zero and doesn’t improve with larger n.

18
Q

What distribution does the minimum transformation become when scaled?

A

An Exp(1) distribution.

19
Q

What is the formula for the power function of the minimum test?

A

γ(λ) = (1−α)^(λ/λ0).

20
Q

What is the main advantage of the minimum test?

A

It has simple calculations and an exact rejection rule.