Ultrasound: Wave propagation Flashcards
What range of frequencies is normally used in medical ultrasound imaging?
1.5 - 15 MHz
What range of wavelengths is normally used in medical ultrasound imaging?
100 - 1000 um
Which clinical application uses the lowest ultrasonic frequencies?
Cardiac
Which clinical application uses the highest ultrasonic frequencies?
Musculoskeletal
Which clinical application uses a phased array transducer?
Cardiac
What type of ultrasonic wave is used in B-mode imaging?
Pulsed longitudinal
What values of sound speed are typically observed in soft tissue?
1.54 +/- 0.10 km/s
Which of these tissue types usually has the lowest sound speed?
fat
Which of these tissue types usually has the highest sound speed?
bone
What are the shapes of the wavefronts in the near and far fields of a plane, circular transducer?
Plane and convex
How do the length of the near field and the angle of divergence of a plane, circular transducer change as the drive frequency is increased?
The former increases and the latter decreases
What, roughly, is the best spatial resolution achievable with commercial, non-ophthalmological ultrasound scanners?
300um
Calculate the sound speed in a soft tissue with a density of 1050 kg/m3, a bulk modulus of 2.5 GPa, and a shear modulus 5.0 kPa. Answer in units of m/s.
1540
The sound speed is simply c0 = (K/ρ0)1/2 where K is the bulk modulus and ρ0 is the density, giving a value of about 1540 m/s.
Note: the shear modulus is not used in the calculation of ‘sound speed’, which is normally assumed to refer to the longitudinal wave velocity
A focused, circular transducer has a diameter of 2 cm and a focal length of 15 cm. If it is driven at a frequency of 2.5 MHz, what is the beam width at the transducer? (Answer in mm).
20
The beam width at the transducer is simply the diameter of the transducer
A focused, circular transducer has a diameter of 2 cm and a focal length of 15 cm. If it is driven at a frequency of 2.5 MHz, calculate the beam width in the focal region. (Answer in mm)
9.25
If we assume c0 = 1540 m/s, then the wavelength is λ = c0/f = 0.62 mm.
The beam width in the focal region is w = Fλ/a = 9.3 mm.