Ultrasound: Wave propagation Flashcards

1
Q

What range of frequencies is normally used in medical ultrasound imaging?

A

1.5 - 15 MHz

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2
Q

What range of wavelengths is normally used in medical ultrasound imaging?

A

100 - 1000 um

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3
Q

Which clinical application uses the lowest ultrasonic frequencies?

A

Cardiac

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4
Q

Which clinical application uses the highest ultrasonic frequencies?

A

Musculoskeletal

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5
Q

Which clinical application uses a phased array transducer?

A

Cardiac

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6
Q

What type of ultrasonic wave is used in B-mode imaging?

A

Pulsed longitudinal

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7
Q

What values of sound speed are typically observed in soft tissue?

A

1.54 +/- 0.10 km/s

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8
Q

Which of these tissue types usually has the lowest sound speed?

A

fat

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9
Q

Which of these tissue types usually has the highest sound speed?

A

bone

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10
Q

What are the shapes of the wavefronts in the near and far fields of a plane, circular transducer?

A

Plane and convex

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11
Q

How do the length of the near field and the angle of divergence of a plane, circular transducer change as the drive frequency is increased?

A

The former increases and the latter decreases

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12
Q

What, roughly, is the best spatial resolution achievable with commercial, non-ophthalmological ultrasound scanners?

A

300um

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13
Q

Calculate the sound speed in a soft tissue with a density of 1050 kg/m3, a bulk modulus of 2.5 GPa, and a shear modulus 5.0 kPa. Answer in units of m/s.

A

1540

The sound speed is simply c0 = (K/ρ0)1/2 where K is the bulk modulus and ρ0 is the density, giving a value of about 1540 m/s.

Note: the shear modulus is not used in the calculation of ‘sound speed’, which is normally assumed to refer to the longitudinal wave velocity

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14
Q

A focused, circular transducer has a diameter of 2 cm and a focal length of 15 cm. If it is driven at a frequency of 2.5 MHz, what is the beam width at the transducer? (Answer in mm).

A

20

The beam width at the transducer is simply the diameter of the transducer

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15
Q

A focused, circular transducer has a diameter of 2 cm and a focal length of 15 cm. If it is driven at a frequency of 2.5 MHz, calculate the beam width in the focal region. (Answer in mm)

A

9.25
If we assume c0 = 1540 m/s, then the wavelength is λ = c0/f = 0.62 mm.
The beam width in the focal region is w = Fλ/a = 9.3 mm.

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