Ultrasound: Introduction to B-mode scanning Flashcards

1
Q

If the distance to a target in a tissue mimicking phantom is 10 cm, how long does it take to receive an echo from that target?

A

130 us

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2
Q

If a B-mode image has a depth of 10 cm and is made up of 100 lines, what is the maximum achievable frame rate?

A

About 80 Hz

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3
Q

In which clinical application is A-mode widely used?

A

ophthalmology

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4
Q

In which clinical application is M-mode widely used?

A

cardiac

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5
Q

Which parameters are displayed along the vertical and horizontal axes of an M-mode trace?

A

Depth and ‘physiological time’, measured in seconds

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6
Q

Which image formats are used by phased and curved array transducers, respectively?

A

Sector and fan-shaped

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7
Q

What is the typical duration of an ultrasonic pulse used for B-mode imaging?

A

About two cycles

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8
Q

Which component of an ultrasound scanner limits its dynamic range most severely?

A

Digital video display

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9
Q

Typically, how many elements do modern 1D linear array transducers have?

A

Between 192 and 256

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10
Q

Typically, how wide are the elements in modern 1D linear array transducers?

A

Between 0.15 and 0.20 mm

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11
Q

Which parameters determine the axial and lateral resolution of an ultrasound scanner, respectively?

A

Half the pulse duration and the beam width in the scan plane

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12
Q

An L8–4 transducer has three frequency settings, called ‘gen’, ‘res’ and ‘pen’. What respective transmit frequencies might these correspond to?

A

6, 7 and 5 MHz

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13
Q

If the voltage amplitude of the largest echoes in a signal is 1 V and the dynamic range of the signal is 100 dB, calculate the the voltage amplitude of the smallest echoes. (Answer in μV)

A

10
The dynamic range is 100 = 5 × 20 dB, so the voltage amplitude of the smallest signals will be 105 times smaller, i.e. 1/105 V or 10 μV

The smallest echoes are likely to come from blood or other low-scatter liquids inside the body.

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14
Q

If a tissue-mimicking phantom has an ‘attenuation’ of 0.8 dB cm−1 MHz−1, what is the amplitude back at the surface of a 4 MHz plane wave that has been reflected from a plane interface at a depth of 10 cm? Assume that the initial amplitude of the wave is 1 MPa, and that the amplitude reflection coefficient of the interface is 20 %. (Answer in Pa)

A

125
The attenuation loss, 2afbz = 2 × 0.8 × 41.0 × 10 = 64 dB = (2 × 20) + (4 × 6) dB

Now, 20 dB corresponds to an acoustic pressure ratio of 10, and 6 dB corresponds to an acoustic pressure ratio of 2, so that 64 dB corresponds to an acoustic pressure ratio of 102 × 24 = 1600 (i.e. 402)

In addition, the amplitude reflection coefficient at the interface is 0.2, so the final acoustic pressure ratio is 1600 × 5 = 8000

Hence, the amplitude of the wave is p = 1.0/8000 MPa = 125 Pa

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