Trigonometry Flashcards

1
Q

4 formulas that require right triangles

A

sin x = opp / hyp
cos x = adj / hyp
tan x = opp / adj
a² + b² = c²

SOH-CAH-TOA & Phythagorean Theorem

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2
Q

2 formulas that do not require right triangles

A

a² = b² + c² - 2bc cos A
a / sin A = b / sin B = c / sin C

Cosine Law & Sine Law

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3
Q

1 formula that works for all triangles (right or non-right)

A

A + B + C = 180°

Sum of the angles of a triangle

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4
Q

Formula to find an angle when you know 3 side lengths and no angles

A

cos A = (b² + c² - a²) / (2bc)
to find angle A

Cosine Law in reverse

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5
Q

Formula to find a side length when you know 2 side lengths in a right triangle

A

a² + b² = c²

Pythagorean Theorem

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6
Q

Formula to find a side length when you know 2 side lengths & the angle between them

A

a² = b² + c² - 2bc cos A

Cosine Law

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7
Q

Formula to find a side length when you know 1 angle & its opposite side length, plus the angle opposite the unknown side

A

a / sin A = b / sin B = c / sin C

Sine Law

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8
Q

Formula to find an angle when you know 1 angle & its opposite side length, plus the side length opposite the unknown angle

A

sin A / a = sin B / b = sin C / c

Sine Law

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9
Q

Formula to find a side length when you know 1 side length and 1 angle in a right triangle

A

One of…
sin x = opp / hyp
cos x = adj / hyp
tan x = opp / adj

depending on the angle & sides you know

SOH-CAH-TOA

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10
Q

Formula to find an angle when you know 2 side lengths in a right triangle

A

One of…
sin x = opp / hyp
cos x = adj / hyp
tan x = opp / adj

depending on the angle & sides you know

SOH-CAH-TOA

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11
Q

When using the Cosine Law to solve for a side length, what last step is always necessary?

A

Square Root

since if the Cosine Law used is
a² = b² + c² - 2bc cos A
then the side length needed would be a
but this cosine law gives a²

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12
Q

When using the Pythagorean Theorem to solve for a side length, what last step is always necessary?

A

Square Root

since if the Pythagorean Theorem used is
c² = a² + b²
then the side length needed would be c
but this Pythagorean Theorem gives c²

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13
Q

When using the Cosine Law to solve for an angle, what last step is always necessary?

A

Inverse Cosine

since if the Cosine Law used is
cos A = (b² + c² - a²) / (2bc)
then the side length needed would be A
but this cosine law gives cos A

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14
Q

When using the Sine Law to solve for an angle, what 2 last steps are always necessary?

A

Multiplication & Inverse Sine

since if the Sine Law used to find A is
sin A / a = sin B / b
then you would need to
1 – multiply both sides by a giving
sin A = a * sin B / b
2 – then the angle would be A but this formula gives sin A

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