Trigonometry Flashcards
4 formulas that require right triangles
sin x = opp / hyp
cos x = adj / hyp
tan x = opp / adj
a² + b² = c²
SOH-CAH-TOA & Phythagorean Theorem
2 formulas that do not require right triangles
a² = b² + c² - 2bc cos A
a / sin A = b / sin B = c / sin C
Cosine Law & Sine Law
1 formula that works for all triangles (right or non-right)
A + B + C = 180°
Sum of the angles of a triangle
Formula to find an angle when you know 3 side lengths and no angles
cos A = (b² + c² - a²) / (2bc)
to find angle A
Cosine Law in reverse
Formula to find a side length when you know 2 side lengths in a right triangle
a² + b² = c²
Pythagorean Theorem
Formula to find a side length when you know 2 side lengths & the angle between them
a² = b² + c² - 2bc cos A
Cosine Law
Formula to find a side length when you know 1 angle & its opposite side length, plus the angle opposite the unknown side
a / sin A = b / sin B = c / sin C
Sine Law
Formula to find an angle when you know 1 angle & its opposite side length, plus the side length opposite the unknown angle
sin A / a = sin B / b = sin C / c
Sine Law
Formula to find a side length when you know 1 side length and 1 angle in a right triangle
One of…
sin x = opp / hyp
cos x = adj / hyp
tan x = opp / adj
depending on the angle & sides you know
SOH-CAH-TOA
Formula to find an angle when you know 2 side lengths in a right triangle
One of…
sin x = opp / hyp
cos x = adj / hyp
tan x = opp / adj
depending on the angle & sides you know
SOH-CAH-TOA
When using the Cosine Law to solve for a side length, what last step is always necessary?
Square Root
since if the Cosine Law used is
a² = b² + c² - 2bc cos A
then the side length needed would be a
but this cosine law gives a²
When using the Pythagorean Theorem to solve for a side length, what last step is always necessary?
Square Root
since if the Pythagorean Theorem used is
c² = a² + b²
then the side length needed would be c
but this Pythagorean Theorem gives c²
When using the Cosine Law to solve for an angle, what last step is always necessary?
Inverse Cosine
since if the Cosine Law used is
cos A = (b² + c² - a²) / (2bc)
then the side length needed would be A
but this cosine law gives cos A
When using the Sine Law to solve for an angle, what 2 last steps are always necessary?
Multiplication & Inverse Sine
since if the Sine Law used to find A is
sin A / a = sin B / b
then you would need to
1 – multiply both sides by a giving
sin A = a * sin B / b
2 – then the angle would be A but this formula gives sin A