Trig ch 6 Flashcards
How to find the value of cosec, sec and cot?
1/Cosx,secx, cot.
Work out the value on the sin, cos and tan and do the reciprocal of that value.
What does the cosec curve look like?
inverted parabola which intersects sin graph at max and min points.
Asymptotes beside where the U’s level off (asymptote every 180*)
What does the sec curve look like?
asymptotes at 90* and 270*.
n shaped parabola at minimum of cos graph.
Half parabolas either side of the asymptotes at 90 and 270.
What are two differences between sec and cosec curve?
In cosec asymptotes are every 180* (180,360), whilst in sec asymptotes are every 180* (90,270).
In cosec, there is a U and an n.
In sec, there is an l, n and l shape.
How do you know where the asymptotes will be on reciprocal curves?
Where the sin/cos/tan x=0 as this will cause the reciprocal curve to be 1/0 which is undefined and needs asymptote.
Why do the reciprocal trig curves have the shapes they take?
Because as the decimal values of the original trig graph gets smaller the larger the reciprocal graph gets.
It then gets to 0 which causes it to be undefined and have an asymptote.
What does the cot graph look like?
Reflected tan graph, asymptotes stay in the same place.
What are the maxima/ minima and asymptotes for cot graph?
asymptotes at 180 and 360 then negative cubics in between these asymptotes.
How to solve equations involving sec, cosec and cot
Convert them to expressions in times of sin, cos and tan
What is the domain and range of sec graph?
Domain = x is all real numbers but x cannot equal 180n-90. Range = f(x) is greater than of equaled to 1 and f(x) is less than -1
What is the domain and range of cosec graph?
Domain = x is all real values and not equal to 180n Range = f(x) greater than or equal to 1 and f(x) is less than or equaled to 1.
What is the domain and range of cosec graph?
Domain = x is all real values not equal to 180n Range g(x) is all real values.
What is the domain and range of the cot graph?
Domain= x is all real values except from 180n Range= f(x) is all real values
why would cos^3x=8 have no solutions?
once you cube root cos^2x=+-2
As cos graph has max at 1 and min at -1 there can be no solutions.
What to do when solving when there is a 2x inside the angle?
- Change the range by multiplying by 2.
- Find all the solutions in this range.
- Then divide all the solutions by 2 and see which ones fit the initial range.