Transition Metals. Flashcards

1
Q

What are the four standard properties of transition metals.

A

Form Complexes.
Formation of coloured ions.
Variable oxidation states.
Catalytic activity.

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2
Q

Define a transition metal.

A

One which formes at least one stable ion with a partially full d-sub shell of electrons.

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3
Q

Define a ligand.

A

An atom ion or molecule that forms a dative covalent bond by donating a lone electron pair to a central transition metal ion.

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4
Q

Define a Complex.

A

A central metal ion surrounded by ligands.

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5
Q

State why Zn is not a transition metal.

A

Zn only has the ability to form Zn2+ and so has a complete d orbital of electrons , hence does not meet the definition of having a partially complete d sub shell.

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6
Q

Define the term Co-ordination number.

A

The number of coordinate bonds formed to a central metal ion in a complex.

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7
Q

Define the term monodentate ligand.

A

Form one coordinate bond per ligand

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8
Q

Define the term bidentate ligand.

A

Can form two coordinate bonds per ligand.

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9
Q

Define the term multidentate ligand.

A

general term: ligand that have more than one Atom with a lone pair capable of coordinate bonding to a central metal ion.

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10
Q

Give some examples of monodentate ligand.

A

H20, NH3 and Cl -

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11
Q

What needs to be remembered about how ligands form bonds.

A

If an atom on the ligand has been used for forming a bond with lone pairs , it can’t donate another lone pair from the same atom , another atoms lone pairs would need to be used if it was multidentate. Sometimes even if there are more possible atoms available the ligand can be limited by being bidentate.

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12
Q

Give some examples of bidentante ligands.

A

Ethan-1,2-diamine , ethandioate- oxoate ion- which does have 4 oxygens but only uses 2 , and benzene-1,2-diol are all bidentate.

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13
Q

Give an example of a hexadentate ligand. State where the Lone pairs come from.

A

EDTA is the main hexadentate ligand. The lone pairs come from 2 nitrogen atoms and 4 oxygen atoms.

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14
Q

What shapes do complexes with small ligands typically form , For example [Ni(NH3)6]2+ or [Cu(H20)6]2+. NH3 and H20 are small ligands.

A

Small ligands often form octahedral shaped complexes.

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15
Q

Draw both [Ni(NH3)6]2+ , [Cu(H20)6]2+

A

Both octehedral.

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16
Q

What types of ligands will generally form tetrahedral shaped complexes and give an example of a ligand that does this.

A

Larger ligands like Cl- form tetrahedral complexes.

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17
Q

Draw out a [CuCl4]2-

A

should be tetrahedral.

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18
Q

What two shapes can complexes with coordination number 4 form.

A

tetrahedral or square planar.
generally tetrahedral but can be square planar for cis plantin which is platinum with stuff or nickel stuff is ocasinly square planar. Chloride ions are generally tetrahedral.

As a rule platinum will be square planar.

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19
Q

what shape is [Ni(NH32)Cl2] and [Ni(Cn)4]2-

A

square planar

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20
Q

Give an example of a linear complex and state a use for this complex.

A

Tollens reagent is a linear complex [Ag(NH3)2]+

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21
Q

What is the requirement for a complex to exhibit geometric E/Z isomerism.

A

Must be octahedral or square planar in shape.

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22
Q

Draw and name both the isomers of [Ni(NH3)2Cl2]

A

Square planar so will have a cis and trans form , e and z.

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23
Q

Draw and name both isomers of [Cr(H20)4Cl2]+

A

This is ocehedral so will have a e and z form , depending if the cl atom is diagonaly apart or not.

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24
Q

Give the condition needed for optical isomerism in a complex and state how this differs from organic.

A

complexes with 2 or more bidentate ligands will form two optical isomers. No need to think in terms of specific chiral carbon case as with organic the 4 different groups doesn’t mater here as they are still non superimposable.

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25
Q

Using en as an abbreviation for Ethan-1,2-diamine state the type of and draw out the isomerism shown in [Cr(en)3]2+ and also [CrCl2(en)2] and {Cr(C2O4)3 } 3-.

A

Ethan-1,2-diamine is a bidentate ligand and so there will be optical isomerism as shape is not important. See page 23 in the text book and also page 4 on the sheet for examples.

Note these types of complexes with coordination number six are still octahedral with the biodentate ligands, and so can be drawn as such with the wedges and dotted lines 90 degrees bond angle.

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26
Q

Give the shape of {Cr(C2O4)3 } 3-. and carefully explain why.

A

Headphone looking asymmetrical molecule , since the ligand is bidentate it doesnt have on of the traditional shapes. Only relivebnce is knowing this bidentate ligand complex will have optical isomerism.

27
Q

Give the shape of {Cr(C2O4)3 } 3- and explain it.

A

Octahedral since there is two bidentate ligands and so a total of 6 co ordinate bonds.

28
Q

Define the chelate effect.

A

The substitution of a monodentate ligand with a bidentate or multidentate ligand leading to a more stable complex.

29
Q

The the species that is produced when copper sulphate is dissolved in water.

A

[Cu(H20)6]2+

30
Q

Draw [Cr(en)3]3+, name the ligand and give its charge . Give the coordination number.

A

See page 2 of sheet. Octahedral with 90 degree bond angles and coordinate number six.

Neutral ligand.

31
Q

Draw [Cr(C2O4)3]3- , name the ligand. Give the coordination number.

A

See page 2 of sheet. Octahedral with 90 degree bond angles and coordinate number six.

32
Q

Give an equation for what would happen if EDTA was added to a solution of copper sulphate.

A

[Cu(H20)6]2aq + EDTA 4- —> [CuEDTA]2- aq + 6H20

33
Q

What type of ligand is EDTA and what charge does it have.

A

It is a hexadentate ligand and carries as 4- charge.

34
Q

Give an equation for what would happen if you added ethane-1,2-diamine to a solution of copper sulphate. Explain why there is this many moles in the equation.

A

[Cu(H20)6]2+ 3en –> [Cu(en)3]2+ 6H20
Coordination number remains as 6 so Half the species are needed as the ligands are now bidentate rather than monodentate.

35
Q

Give an equation for what would happen if you added ethandioate to a solution of copper sulphate. Explain why there is this many moles in the equation.

A

[Cu(H20)6]2+ 3C202 2- –> [Cu(C2O4)3]4- + 6H20

Coordination number remains as six and son a bidnetate ligand will need to form the same number of six bonds.

36
Q

Explain fully why multidentate ligands will replace monodentate ligands , give some of the key cases to look out for.

A

Due to the chilate effect. There is in an increase in entropy when this process takes place as there is more moles of reactants in the products than reactants. less species are replaces by more species in the reactions increasing disorder. There is a similar number of bonds in both complexes and so there is little change in enthalpy. Hence delta g will be negative as possitive entropy change and small enthalpy change.

37
Q

Describe briefly the structure of haemoglobin and why it is that carbonmonoxide is so toxic to humans.

A

Consists of Fe 2+ with a coordination number of 6. 4 of the sites are taken up by a tetradentate ligand , called poryphrin forming a complex called haem. A fifth nitrogen atom acts as a ligand below the plane , part of a complex protein called globin. This leaves a spot open for :O2. :O2 Is a bad ligand so can easily leave and rejoin, better ligands like carbon monoxide will bond irreversibly and destroy the oxygen carrying capacity of haemoglobin.

38
Q

Construct a balanced symbol equation for the reaction of acidified potassium manganate with Fe2+ (aq). What do you find is the ratio you need to know for calculations of Fe2+ to MnO4 - . N.B Recall the ratio quickly.

A

5 times as many iron2 moles of manganate ion.

39
Q

Outline a method for the analysis of iron tablets that contain iron(II) sulphate in them.

A

Using a beurtte gradually add the intense purple potassium manganate to a solution containing Fe2+ ions acidified with H2SO4. The end point of the titration will come when the solution turns purple from colourless and then you can use the 5Fe to 1 Mn04- ratio to calculate moles.

40
Q

Why would a redox titration involving iron and manganate not need an indicator.

A

The colour of the mixture changes as the reaction proceeds.

41
Q

Why is the solution containing Fe2+ ions acidified with excess sulphuric acid in a redox titration.

A

To provide the H+ ions for the redox reaction.

42
Q

Why can Hydrochloric acid not be used as an alternative to sulphuric acid in a redox titration.

A

Manganate ions in Fe redox titrations will oxidise Fe2 into Fe3 that is a fact. the redox potential of the manganate reduction that you should know off by heart is 1.51. Wheres the one for Cl2/Cl- is 1.36. So the manganate ions will oxidise the Cl- ions into chlorine.
The manganate ions must only be oxidising the Fe2+m or too large a volume will be used and toxic Cl2 will be produced.
By running the Cl2 reaction backwards and and timing by 5 you can combine this with the manganate half equation.
Sulphate ion would not be oxidised so are suitable.

43
Q

Give the colour changes you would observe during a manganate iron(II) titration.

A

There will be an intense purple liquid being added to a pale green solution of Fe2+. Pale pink colour is produced as Mn2+ , this pale pink leaves a virtually colourless solution and removes the intense purple manganate being added. You reach an end point when the pink colour remains and the solution goes purple from colourless. Think of the Mn2+ as being seen as colourless compared to heir intense purple counterpart.

44
Q

Give the colour of Fe2+ aq

A

pale green

45
Q

Give the colour of MnO4 - aq

A

intense purple

46
Q

Give the colour of Fe3+ aq

A

pale violet

47
Q

Give the colour of Mn2+ aq

A

pale pink

48
Q

List the colours of the vanadium species. Give also the oxidation states.

A

VO2 + is yellow. 5
VO 2+ is blue 4
V3+ is green 3
V2+ is violet. 2

49
Q

Do some quality control tests on iron tablets and also go over the other common redox titrations.

A

d

50
Q

How many oxidation sates does vanadium have , give them all.

A

It has 4 oxidation states. 5,4,3,2 each has a different colour.

51
Q

What types of compounds are generally reducing. agents.

A

Compounds with low oxidation states like V 2+ or Fe2+ or Mn2+.

52
Q

What type of compounds are generally oxidising agents.

A

Compounds with high oxidation sates like the manganate ion.

53
Q

Describe chemically what would happen if zinc was added to a solution of acidified vanadium 5.

A

The vanadium five would be taken through each of its successive oxidation Staes from 5 all the way to 2 and the colour change would reflect this.

54
Q

Give an important property of zinc metal with acid.

A

It is a strong reducing agent and can reduce most metals from its highest oxidation state down to its lowest like reducing Fe3+ down to Fe2+.

Wants to give away electrons to climb up the charge ladder.

55
Q

Give the colour of each of the vanadium ions.

A

VO2 + is yellow yellow and blue mix to first green.
VO 2+ is Blue
V3+ is green
V 2+ is violet

56
Q

What shape are silver complexes generally.

A

Linear like Tollens. [Ag(NH3)2]+

57
Q

What shape are platinum complexes.

A

Always square planar like cisplatin - [Pt(NH3)2Cl2]

58
Q

What shape is NI(CH3)Cl2

A

square planar, in addition to platinum nickel complexes have a few exceptions that are square planar.

{NI(CN)4]-2 is also square planar so watch out for anything nickel that has a coordination number 4 since thats probably;y square planar.

59
Q

Explain when iron is added to an acidified solution of vanadium 5 there is two stages of green colours.

A

The yellow and blue colour of the VO2 + ion and the VO 2+ ions respectably merge to form the first green.
V3+ is just a green colour on its own.

60
Q

What is the short hand ratio for a manganate vs Fe(2) titration.

A

You always need to multiply the moles of the manganate ion by 5 to get the concentration of Fe2+ ions.

61
Q

How could you make a standard solution with an iron tablet to quality test it.

A

d

62
Q

Why can nitric acid not be used instead of sulphuric acid to acidify manganate titrations .

A

Manganate ions in Fe redox titrations will oxidise Fe2 into Fe3 that is a fact. the redox potential of the manganate reduction that you should know off by heart is 1.51. Wheres the one for Cl2/Cl- is 1.36. So the manganate ions will oxidise the Cl- ions into chlorine.
The manganate ions must only be oxidising the Fe2+m or too large a volume will be used and toxic Cl2 will be produced.
By running the Cl2 reaction backwards and and timing by 5 you can combine this with the manganate half equation.
Sulphate ion would not be oxidised so are suitable.

63
Q

Why can’t nitric acid be used instead of sulphuric acid for iron manganate titrations .

A

The reduction of the NO3- ion has a more possitive electrode potential than the Fe3+ to Fe2+ reduction so would help the manganate oxidise the iron3 ion and so a smaller volume of manganate than required would be used.

64
Q

Give the charge on en and the oxalate ion.

A

neural and 2- respectively.