Alkenes. Flashcards
What type of hydrocarbon are alkenes.
They are unsaturated hydrocarbons. They will have at least one C=C somewhere within their structure.
What is the general formula of an alkene.
General formula is CnH2n
One is the one thing an alkene must contain in its structure.
Alkenes contain a carbon- carbon double bond somewhere in their structure.
Describe , geometrically , the arrangement of bonds around the C=C.
the arrangement of bonds around the
>C=C< is planar and has the bond angle 120 degrees.
Key Points: Planar and 120 degrees.
Draw and label the C=C double bond itself and hence explain the type of species this leaves alkene vulnerable to attack from as a result of this structure.
Should see picture on notes.
Description: C=C double covalent bond consists of one sigma (σ) bond and one pi (π) bond.
C-C Pi bond goes horizontal and is above and below the sigma bond which is sandwidged.
The carbon carbon sigma bond goes in between and sticks out vertically , two between each carbon.
Define unsaturated.
Refer to “the presence off at least one C=C within the structure”.
Defne electrophile.
An electrophile is a an electron pair acceptor, it likes the electrons so takes em.
Give the change in functional group when bromine reacts with ethene , give the conditions and state also name and outline a mechanism for this reaction. Name the product that is formed.
Change in functional group: alkene INTO dihalogenoalkane
Reagent: Bromine
Conditions: Room temperature (not in UV light) Mechanism: Electrophilic Addition
Type of reagent: Electrophile, Br+ Plus is a dipole .
Product formed is 1,2-dibromoethane.
Give the electrophile for when bromine molecule reacts with ethene. Draw also the intermediate which is formed and state the specific name for this structure.
Give the electrophile when hydrogen bromide reacts with ethene. Name and outline an overall mechanisms for this reaction.
(Brδ+)
Carbocation will form which is an intermediate species with a. positive charge.
How can a bromine molecule Br2 undergo a electrophilic addition when it is a molecule that his not in any way polar due to the even distribution of electron density.
Give the practical application of this reaction.
As the Br2 molecule approaches the alkene, the pi bond electrons repel the electron pair in the Br-Br bond. This INDUCES a DIPOLE. Br2 becomes polar and ELECTROPHILIC (Brδ+)
Draw in displayed formula the reaction that takes place between HBr and But-2-ene. Name the product that is formed. State what is meant by symmetrical.
Product formed is 2-bromobutane. The alkene is symmetrical so swapping over the Br and H does nothing.
Remember symmetry is in regards to the double bond in the alkene not the number of carbon atoms that are present. If the double bond is dead in the middle of the chain then swapping over the H and the Br changes nothing about the structure as you can just flip it.
Name and outline a mechanism for the reaction of hydrogen bromide and But-2-ene.
Will be electrophilic addition. That will form 2-bromobutane with no possible isomers.
In what type of electrophilic addition reaction would there be two possible products and why. Also state why one particular reaction could not possibly have any isometric products form. State the type of isomerism in question.
If the alkene is unsymmetrical, addition of hydrogen bromide can lead to two isomeric products. The carbon carbon double bond needs to not be in the dead middle of the chain ( remember its not about charge length but more if the double bond is in the middle).
The reaction of Bromine molecule (not HBr) with any alkene , symmetrical C=C position or nor will not produce position isomers since shaping a bromine with bromine changes nothing.
Must be H-Br with an asymmetric alkene to produce two functional group isomers.
Give Markownikoffs rule.
The major product will form via the negative species ( usually bromine but also with the sulphuric acid one ) adding to the most stable carbocation.
This means that in rather unhelpful terms the hydrogen will add to the carbon that has the most hydrogens already on it.
Just think the carbocation carbon that gets attached by Br: is the one with more alkyl groups on it.
Remember the Br-: that gets generated is not a electrophile that is the partially positive atom in the H-B
r . If anything this is a nucleophile.
What is the one type of electrophilic addition reaction that will produce position isomers.
H-Br or H-Cl ( any hydrogen halide) with an asymmetric alkene. Not Br-Br.