Transition Elements - 2 (ligands, and sub reactions, isomers...) Flashcards

1
Q

Colour of Co2+ complex hydroxide precipitate and equation

A

Blue which turns beige in the presence of air

+ 2OH- -> (H2O)4(OH)2 + 2H2O

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2
Q

Colour of Fe2+ hydroxide precipitate and equation

A

Green, then turns brick red in presence of O2

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3
Q

Colour of Fe3+ hydroxide precipitate and equation

A

Brick red/ rusty brown

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4
Q

Colour of Cu2+ hydroxide precipitate and equation

A

Blue

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5
Q

What is a bidentate ligand?

A

A ligand which can donate two lone pairs of electrons to the central metal ion to form coordinate bonds

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6
Q

Ligand substitution in complexes:

Cu 2+ and ammonia, first a small amount then in excess

A

A small amount: pale blue precip. of Cu(OH)2

Excess: precip. dissolves, deep blue solution + 4NH3 [Cu(NH3)4(H2O)2]2+ + 4H2O

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7
Q

Cu 2+ and hydrochloric acid

A

Initially turns green then yellow solution

+ 4Cl- equil. [CuCl4]2- + 6H2O

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8
Q

Co 2+ and conc. hydrochloric acid

A

Dark blue solution

+ 4Cl- equil. [CoCl4]2- + 6H2O

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9
Q

Co 2+ and ammonia

A

Small amount: = 2NH3 -> (H2O)4(OH)2 + 2NH4+ green precip

Excess: start from same complex ion, + 6NH3 -> []6NH3 2+ + 6H2O beige then black on standing

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10
Q

What is a coordinate bond?

A

Bond in which both electrons in shared pair are donated by the same bonding atom

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11
Q

What is a ligand?

A

A molecule or ion which donates a pair of electrons to the central metal ion to form a coordinate bond

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12
Q

What is coordination number?

A

The total number of coordinate bonds formed between a central metal ion and its ligands

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13
Q

Why do transition metal ions form complex ions?

A

They are relatively small and have two or more charges, therefore their high charge density makes them strongly polarizing and able to attract lone pairs of electrons or ions on molecules

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14
Q

Requirement to act as a ligand

A

At least one lone pair of electrons

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15
Q

Formula and charges of following ligands:

  1. Water
  2. Ammonia
  3. Thiocyanate
  4. Cyanide
  5. Chloride
  6. Hydroxide
A
  1. :OH2 & neutral
  2. :NH3 & neutral
  3. :SCN- & -1
  4. :CN- & -1
  5. :Cl- & -1
  6. :OH- & -1
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16
Q

What is a monodentate ligand?

A

A ligand that donates just one pair of electrons to the central metal ion to form one coordinate bond

17
Q

Using VSEPR, describe how coordination number influences the shape of complex ions

A

Electron pairs repel each other, coordinate bonds are bonding electron pairs which will repel each other equally and as far apart as possible to minimize repulsion. Thus, number of coordinate bonds will influence the shape of the complex ion

18
Q

What type of complex ions does cis/trans isomerism occur in?

A

Octahedral complex ions that contain four of one type of ligand and two of another
Square planar complex ions

19
Q

Difference between cis and trans complex ion isomers

A

In the cis, the two ligands which are the same are at adjacent corners and 90~ to one another
In the trans, the two ligands which are the same are at opposite corners and 180~ to one another

20
Q

What is a bidentate ligand?

A

A ligand that can donate two lone pairs of electrons to the central metal ion to form two coordinate bonds.

21
Q

What is a hexadentate ligand?

A

A ligand with 6 lone pairs of electrons, each forming a coordinate bond to a metal ion in a complex ion

22
Q

Which complex ions form optical isomers?

A

Octahedral complexes that contain multidentate ligands

23
Q

Requirements for optical isomers

A

(No plane of symmetry)

  • A complex with three molecules or ions of a bidentate ligand
  • A complex with two molecules or ions of a bidentate ligand, and two molecules or ions of a monodentate ligand
  • A complex with one hexadentate ligand
24
Q

What is a ligand substitution?

A

A reaction in which one ligand in a complex ion is replaced by another ligand

25
Q

Reaction between copper (II) ions and ammonia

A

Small amount of ammonia: ammonia acts as base and blue precipitate of Cu(OH)2 is formed (from blue solution)
When excess ammonia is added, the pale blue precip dissolves and a deep blue solution is formed. Four of water ligands are replaced by ammonias.
[Cu(H2O)6]2+ + 4NH3 [Cu(NH3)4(H2O)2]2+ + 4H2O

26
Q

Reaction between copper (II) ions and conc. HCl

A

Blue solution turns green then yellow. When green, both the blue and yellow, aqua and the chloro complexes are present.
[Cu(H2O)6]2+ + 4Cl- [CuCl4]2- + 6H2O

27
Q

Cobalt (II) ions and conc. HCl

A

Pale pink solution turns dark blue.

[Co(H2O)6]2+ 4Cl- CoCl4 2- + 6H2O

28
Q

Cobalt (II) ions and ammonia

A

Small amount: Green precip of hydroxide
Excess: Straw coloured solution is formed
[Co(H2O)6]2+ + 6NH3 [Co(NH3)6]2+ + H2O

29
Q

What is the equation for Kstab?

A

[new complex]/[aqua complex][new ligands]^no. of moles of ligand in eqn.

30
Q

What does large Kstab value show about equilibrium?

A

The position of equilibrium lies to the right

31
Q

What does a large Kstab value show about stability and formation of ion?

A

Complex ions with larger Kstab values are more stable than those with lower ones, large stability shows that the ion is easily formed