EEE past paper questions Flashcards
Equation for reaction when ammonia is heated with oxygen to form NO
4NH3 + 5O2 –> 4NO + 6H2O
How to determine initial rate of reaction using graph
Tangent at t = 0
What is bronsted-lowry acid?
A proton donor
Large scale uses for hydrogen
Production of ammonia
Hydrogenation of ethene
Fuel or fuel cells
When presented with table of redox half equations and electrode potentials, why is HCl not suitable for acidifying potassium manganite solution for titration (H2SO4 is)
electrode potential for MnO4 system is more positive than for Cl2 system
MnO4- oxidises Cl- to form Cl2 giving incorrect results
and either: MnO4- does not react with SO42- because sae sides of half equation or there is no SO32- in H2SO4 to react with MnO4-
Two advantages of vehicles using fuel cells
Less CO2 or less greenhouse gases produced
Greater efficiency
3MnO4 2- + 2H2O 2MnO4 - + MnO2 + 4OH-
how can equilibrium position be shifted by bubbling CO2 gas through the mixture?
CO2 reacts with H2O forming acid : H2O + CO2 -> H2CO3
then the acid reacts with hydroxide ions: H2CO3 + OH- -> H2O + HCO3-
Equilibrium shifts to right to restore the OH-
Explain why enthalpy change of hydration of magnesium ions is more exothermic than for calcium ions
Magnesium ions have greater charge density because they are smaller ions
Thus, the have stronger bonding with H2O because greater electrostatic attraction
Reaction between ammonia and oxygen to make NO
2NH3 + 2.5O2 -> 2NO + 3H2O
Two large scale uses for hydrogen
Production of ammonia, hydrogenation of ethene, fuel or fuel cells
What is d block element?
elements who’s highest energy sub shell is a d-sub shell
KOH electrolyte decomposes forming H2 at one electrode and O2 at the other, predict the half equations
4OH- -> O2 + 2H2O + 4e-
2H2O + 2e- -> H2 + 2OH-
CO + 2H2 CH3COH
Temp increased, pressure constant, Kc decreased, what happened to equilibrium?
Equilibrium shifts to left
suggest why methanol is added to petrol?
adds oxygen
1st electron affinity of oxygen is negative, second is positive. Why is second positive?
Oxide ion and electron are both negative, so energy is required to overcome the repulsion