Transcription mechanism + Regulation of initiation Flashcards

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1
Q

Which organisms have timing and location of transcription and translation having an overlap?

A

Bacteria. - eukaryotes have them separated

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2
Q

What are the requirements for transcription?

A
  1. Single stranded (ss) DNA template. - non-coding DNA strand acts as template.
  2. All 4 RNA triphosphate nucleotides.
  3. DNA dependent RNA polymerase (a holoenzyme consisting of sub units).
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3
Q

What are the different forms of RNA polymerase?

A

Core enzyme
Holoenzyme

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4
Q

What does the core enzyme do?

A

Catalysing DNA-directed RNA synthesis.

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5
Q

What are the different parts of a core enzyme?

A

α2ββ’ (ω)

α - 40 kD each: function in enzyme assembly and activation.
β - 155 kD: catalytic domain and nucleotide binding.
β’ - 160 kD: template binding
ω - 6 kD; function unknown.

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6
Q

What does the holoenzyme do?

A

Capable of catalysing DNA-directed RNA synthesis and initiating RNA synthesis at the correct locations.

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7
Q

What are the different parts of the holoenzyme?

A

α2ββ’σ

α - 40 kD each: function in enzyme assembly and activation.
β - 155 kD: catalytic domain and nucleotide binding.
β’ - 160 kD: template binding
σ - various sizes; specificity factor, promoter binding and open complex formation.

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8
Q

What direction does the coding strand go?

A

5’ to 3’

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9
Q

What direction does the template/non-coding strand travel in relative to the coding strand?

A

3’ to 5’

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10
Q

Which direction is upstream of the transcription initiation site (relative to coding strand (strand on top))?

A

towards the 5’.

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11
Q

What are the stages of transcription?

A
  1. Template recognition.
  2. Initiation.
  3. Elongation.
  4. Termination.

1&2 are a part of initiation

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12
Q

What happens in template recognition?

A

RNA polymerase binds to duplex DNA. Then DNA is unwound at promoter. If there is a sigma factor then a holoenzyme was used.

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13
Q

What happens in the initiation part of transcription?

A

Chains of 2-9 bases are synthesised and released.

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14
Q

What happens in the elongation stage of transcription cycle?

A

RNA polymerase moves; RNA is synthesised by base pairing with one strand of DNA (sigma is released). Unwound region moves with RNA polymerase. RNA polymerase reaches end of gene.

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15
Q

What happens in the termination part of transcription?

A

RNA polymerase and RNA are released at terminator and DNA duplex reforms.

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16
Q

What is the K\/I equation for the equilibrium equation?

A

Ki = RPc/(R+P)
R = RNA polymerase
P = promoter
RPc = closed promoter complex

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17
Q

What are the kinetics of transcription initiation?

A

R + P –Ki–> <–K-i– RPc –K2–> <–K-2– RPo –K3–> <–K-3– RPi –K4–> RPE

i = one or initiation
o = open
c = closed
E = elongation
From initation to elongation there is no longer a reversible reaction
2 = II
3= III
4 = IV

18
Q

What is the rate of open complex formation called?

A

KII or K2

19
Q

What happens in K3?

A

There is NTPs in the forward reactions.
If the backward reaction happen (goes from initiation to open promoter complex) then abortive transcripts happened.

20
Q

What bit of kinetics transcription initiation is called the promoter clearance?

A

KIV or K4
Its the bit that is irreversible when it moves from initiation to elongation.

21
Q

What happens when polymerase binds to DNA?

A

It binds non-specifically to DNA with low affinity and migrates, looking for promoter. The sigma subunit recognises promoter sequence.
RNA polymerase holoenzyme and promoter form closed promoter complex (DNA not unwound) - Ki = 10E-6 to 10E-9 M.
Polymerase unwinds about 12 pairs to form open promoter complex - Kii =10E-14M

22
Q

What are promoters?

A

Sequences in the DNA just upstream of transcripts (coding sequences) that define the sites of initiation.

23
Q

What is the role of the promoter?

A

Attract RNA polymerase to the correct start site so transcription can be initiated.

24
Q

How were promoter sites defined (bacteria)?

A
  1. Bioinformatics - comparison of known start sites to identify consensus sequences - not wholly conserved but still shows high conservation.
    Regions of similarity found between -10 and -35 bases
  2. Biochemical - DNAse protection - DNAse foot printing can be used to identify sites where RNA polymerase is in close contact with DNA.
  3. Genetic - mutations of the sites can lead to elimination/reduction of transcriptional initiation at a promoter. Strong promoters have sites that are very similar to the consensus sequence while weak promoters show many differences.
25
Q

What happens in DNAse protection?

A
  1. Add purified RNA polymerase to DNA.
  2. Digest extensively with DNAse (digests all uncovered DNA into nucleotides).
  3. Isolate and identify the protected region (usually about 60 bp in prokaryotes.
26
Q

What do sigma factors do?

A
  1. increase initiation rate (not elongation rate).
  2. Contacts with core occur throughout its length.
  3. Can no bind DNA unless bound to core (must bury inhibitory region).
  4. Decreases affinity of core for nonspecific DNA.
  5. Recognises bases in coding strand at -10 and also double strands at -35.
27
Q

What is the function of sigma factor subunit?

A

Subunit of RNA polymerase - initiation factor.
Ensures RNA polymerase binds stably to DNA promoter.
Destabilises nonspecific binding to non-promoter DNA.
Sigma stabilises specific binding to promoter DNA. (Affinity increases in holoenzyme in specific promoter DNA).
Accelerates the search for promoter DNA.
Diff sigma factors recognise diff promotes and have diff regulons.

28
Q

What is the principal sigma factor?

A

RpoD - cannot be knocked out as it is very important. The other sigma factors have specialised functions eg work when heat shocked.

29
Q

When does sigma 54 work?

A

Involved in activation of genes for nitrogen starvation conditions.
Can bind to promoter without the core RNA polymerase (it has no inhibitory domain) - more like eukaryotic transcription factor.
Can only facilitate closed complex formation - specific activators needed for open complex formation and successful transcriptional initiation.

30
Q

What is the interaction between DNA and RNA polymerase?

A
  1. Core RNA polymerase is stored at non-specific DNA sites before sigma binds. Core has high affinity for DNA, which is increased by the presence of nascent RNA. Affinity for loose binding sites too high to find promoters efficiently from other sequences.
  2. By reducing the stability of the loose complexes, sigma allows the process to occur much more rapidly and by stabilising the association at tight binding sites, the factor drives the reaction irreversibly into the formation of open complexes.
    3) When sigma released, the core plus nascent transcript (ternary complex) is essentially locked onto the DNA until termination.
31
Q

What happens in abortive initiation?

A

AKA cycling.
RNA pol transcribe 2-9 nt and then restarts.
Does not leave the promoter.
May occur several-hundreds times before elongation.
Only 8 bases can fit in active site of an enzyme. Hence the abortive products of 8-10 base.

32
Q

How many bases can fit in an enzymes active site?

A

8

33
Q

What happens in the sigma cycle?

A

Closed promoter complex (moderately stable).
Sigma subunit binds to -10 region.
Holoenzyme + sigma factor.
Open promoter complex (highly stable).
Holoenzyme has high affinity for promoter regions due to sigma.
Once initiation takes place, RNA polymerase does not need very high affinity for the promoter.
Sigma factor dissociates from core after few elongation reactions.
Elongation takes place w/ core.
Sigma rebinds to other core enzymes.

34
Q

What happens in elongation?

A
  1. After 8-9 bp RNA synthesis occurs, sigma released and recycled in other reactions.
  2. RNA polymerase completes the transcription at 30-50 nt/sec.
  3. DNA untwists rapidly and reanneals behind enzyme.
  4. Part of new RNA strand is hybrid DNA-RNA, but most RNA is displaced as helix reforms.
35
Q

Why is coding strand called that?

A

Same as mRNA but uses uracil. Template strand is used for mRNA to code off of.

36
Q

What causes supercoiling during transcription?

A

DNA in front of polymerase is overwound and DNA behind in underwound.
Transcription causes stress.

37
Q

What needs to be done to compensate for supercoiling during transcription?

A

Two enzymes are needed: gyrase in front to introduce negative supercoils and topoisomerase trailing to relax the supercoils.

38
Q

What are the two types of termination?

A

Factor independent
Factor dependent (Rho dependent termination)

39
Q

What does factor independent termination need?

A

Inverted repeats (GC rich region - very stable)
Followed by run of Ts on coding strand.
Forms hairpin loop.
RNA:RNA hybrid very stable.
Transcription bubble is destabilised RNA polymerase falls off.

40
Q

What does factor dependent termination need?

A

Requires proteins that interact w/ polymerase or transcript to stop transcription.
E coli has 3 termination factors: Rho (best known), Tau and NusA.

41
Q

What happens in Rho-dependent termination?

A

Works only if RNA not being translated. -Bacteria can have simultaneous transcription/translation.
Rho is RNA-dependent ATPase only cleaves ATP if RNA is present.
Rho is RNA-DNA helicase. Will only unwind double helix if RNA:DNA hybrid.
1. Termination can not occur if rut (Rho Utilisation site) is being translated.
2. Rho binds to rut mRNA and slides along mRNA chasing polymerase.
3. RNAP pauses at termination site; Rho catches polymerase. (Rho sliding requires hydrolysis of ATP).
4. Helicase activity unwinds RNA:DNA hybrid.
5. Disruption of RNA:DNA hybrid causes RNA poly and mRNA to fall off.