Topic B: The Structure and Transmission of Genetic Information Flashcards

1
Q

Briefly define chromosome territories and compartments.

A

The DNA in each chromosome occupies a defined volume of the nucleus and only overlaps with its immediate neighbors. Chr territories (CT) are irregular but typical 1 to 2 micrometers in diameter, and consists of smaller subdomains. They have been found to border each other closely, neighboring chromosomes can invade each others CT and intermingle at their peripheries. Observations of living cells have also revealed that chr are essentially immobile most likely held in place by the force exerted upon them by their neighbors. CT are semi conserved from parent to daughter cell during cell devision, with locations in the daughter cell similar to those in the parent cell.

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2
Q

List 2 regulated covalent modifications that affect chromatin structure and describe their effects.

A

DNA Methylation – condenses chromatin and silences the region Histone Acetylation – opens chromatin and typically correlated with active regions of genome

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3
Q

Define epigenetics

A

Heritable changes in phenotype or gene expression, and caused by mechanisms other than changes in the underlying DNA sequence.

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4
Q

Name two epigenetic marks that affect gene expression.

A

H3K4me3, H3K9me, and H3K27me3

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5
Q

Give 3 examples of epigenetic modifications. How do they differ from DNA mutations?

A

DNA methylation, Histone acetylation, and Histone methylation
Difference: they are Reversible. The acetylation/deacetylation of histones is often used as part of control of gene expression. DNA mutations can be corrected via mismatch repair but are typically not used as a reversible regulatory mechanism. Epigenetic modification do not change the nucleotides – instead they can change the conformation of the chromatin structure, etc.

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6
Q

Describe 2 distinct mechanisms by which a chromosomal translocation can result in activation of a proto-oncogene.

A

The promoter and/or enhancer of a housekeeping gene translocation upstream a proto-oncogene can activate constitutively. miRNA expression which typically inhibits translation of target proto-oncogene may be disrupted.

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7
Q

Give two examples of different mechanisms that produce genomic alterations in cancers.

A
  1. ) Nearby regulatory DNA sequences causes normal protein to be overproduced
  2. ) fusing to actively transcribed gene produces hyperactive fusion protein

Other ways of saying the same thing that we had put down previously:

  1. ) If the gene moves into a region of the genome that is highly transcribed
  2. ) If the gene moves into a region under the control of a strong enhancer
  3. ) gene fusions
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8
Q

What kinds of cellular and chromosomal changes would you expect to see if telomeres failed to function properly? Why?

A

cellular changes: apoptosis
chromosomal changes: non-homologous chromosome ends might fuse because they are no longer capped because they would be detected as a double stranded break, Could form circular chromosomes for the same reasons as above, If the telomeres fail to shorten (or are elongating) the cell would keep dividing

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9
Q

The human chromosomes and the chimp chromosomes have nearly the same karyotype except for human chromosome 2, which is a fusion of chimp chromosome 2A and 2B. In a bizarre experiment, soviet scientist Ilya Ivanovish attempted to create human-chimp hybrid. A. If such hybrid were to be made, would the resulting progeny be viable? Give a brief argument for why it should or should not be viable. B. If the hybrid were viable, what are the possible chromosomal segregation results of gametes pro-duced from such a hybrid? (focus on the chromosome 2/2A/2B only).

A

Looks like an open question. The Ilya’s experiments eventually failed. So the progeny probably is not viable because the different number of chromosomes, so the cells can not divide probably. [Some-how trisomy 21 patients sometimes can survive] The gametes could be (1)(2,2A,2B) and (none) (2) (2,2A) and (2B) (3) (2) and (2A,2B) (4) (2,2B) and (2A)

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10
Q

You are working on a yeast strain that keep giving rise to spontaneous mutations. You suspect that this is a mutater strain that is defective in a DNA repair pathway. Given that you have access to all commonly used mutagens, how would you determine whether the strain is defective in MGMT repair, nucleotide excision repair, or mismatch repair?

A

MGMT = methyl guanine methyl transferase

You can rule out nucleotide excision repair by exposing to UV and if thstrain i smuch less viable than the WT but acts the same as WT when exposed to different mutagens then it is prob a mutation in this pathway

You can rule out mismatch repair by doing the same but instead of UV you use alkylating agents, as they are sensitive to those.

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11
Q

What are the major components of the cell cycle?

A

M-> G1 -> S ->G2 -> m

M: mitosis is where sister chromatids separate and divide it
metaphase checkpoint
Interphase: G1 , S, G2

G1: Gap1 is cell growth and cells that cease division arrest
G1/S check point
S phase: DNA synthesis
G2: Gap 2 Cell growth

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12
Q

Describe the enzymatic activity of a cyclin-dependent kinase (Cdk) and what do they regulate?

A

CDKs regulate the cell ccycle. CDKs bind to cyclins which are regulatory proteins . Without cyclin, CDK has little kinase activity, but the cyclin-CDK complex is an active kinase. CDKs are serine-threonine kinases, as they phosphorylate their substrates on serines and threonines. Cyclin binding induces a conformation change that reveals Thr160 residue. Phosphorylation of Thr160 by CAK (CDK activating kinase) activates and stabilizes it. CDK activity is inhibited by phosphorylation of Try15 by Wee1. Dephosphorylation of Tyr15 by Cdc25 activates it.

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13
Q

Briefly describe how Cdk activity changes during exit from mitosis and how this change is controlled.

A

Cdk activity decreases through cyclin degradation. MPF (maturation promoting factor) which is made up of cyclinB and Cdk1 must be activated to enter mitosis and must be inhibited to exit mitosis. Cyclins are synthesized and degraded with the cell cycle. They are degraded by ubiquitin dependent pathway by APC (anaphase promoting complex,E3 ligase)

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14
Q

What mediates the destruction of cyclins during the cell cycle phase?

A

Ubiquitin-mediated proteolysis used to degrade cyclins, and this provides irreversible directionality.

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15
Q

What are checkpoints?Describe two examples of the consequence of defective checkpoint function.

A

Checkpoints are major events in the cell cycle that determine whether or not to proceed with the cell cycle.

Example 1. Start or restriction checkpoint between G1 and S decided whether or not to replicate the chr

A defective checkpoint can result in a chr not finished undergoing DNA repair to replicate, which will result in chrosomal abberations or inherited mutations.

Example 2. Metaphase checkpoint ensures all chromosomes are lined up at the plate and are ready to undergo anaphase. Consequence of defect in non-dis-junction that results in aneuploidy or abnormal number of chr in gametes.

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16
Q

Describe meiotic cell division in five steps.

A
  1. line up homologous chromsomes
  2. recombination
  3. cells divide into two 2n
  4. sister chromatids line up (no combination)
  5. cells divide into 4 cells with n chr
17
Q

A gene you believed to be necessary for proper centromere function is disrupted in a yeast experiment. If your hypothesis is correct, what kind of cellular changes might you expect to see and why?

A

Aneuploidy because the segregation during mitosis would be messed up and possible misregulaion of genes in the region that are affected by changes in heterochromtain cells should stop dividing and senesence or undergo apoptosis if the spindle checkpoints sense poor alignment of the chr and arrest the cell at the stage

18
Q

What are three major types of proteins that are involved in segregation during mitosis?

A
  1. kinetachores: adheres chr to rest of the machinery (microtubles)
  2. microtubles (actin): spindles that attach to he chr and segregate to poles
  3. centrioles: polarize cell and anchors microtubles
19
Q

In a diploid organism, describe what takes place in meiosis in regards to chr at each step. Don’t forget crossing over.

A

prophase I: condensation of chr, chr
metaphase I: homologous pairs move to metaphase plate
anaphase I: homolgous chr separate
telophase I: chr are at the pole
cytokinesis: cells divide into two 2n cells
prophase II: thickening of chr
metaphase II: chr align to meta phase plate
anaphase II: sister chr separate
telophase II: chr at poles
cyokinesis: cells divide four n cells

20
Q

How does the process of mitosis differ from meiosis?

A

2 diploid vs 4 haploid daughter cells
crossing over in meiosis
centromeres divide in anaphase during mitosis and anaphase 2 in meiosis
mitosis: identical daughter cells
meiosis: promotes variation (4 genetically distinct daughter cells)

21
Q

What is the cellular explanation of Mendel’s law of segregation and law of independent assortment?

A

During meiosis (gamete formation) , alleles of traits on different chr will segregate, thus following law of segregation and each alleles trait will be expressed independently, thus following law of independent assortment.

22
Q

Define causality and contrast it with correlation. Give biological examples.

A

Causality means something is responsible for a phenotype where as correlation just means something is associated with phenotype.If A causes B then no A will result in no B. Correlation does not imply a direction. A and B appear together but don’t know which ultimately causes the other.
Causality is a direct consequence.

Ex. Two gene A and B , TF C. If TF C is expressed then A and B are expressed. If TF C is knockdown, and we dont see A and B expressed then TF C causes the expression of A. It is a causal relationship. Here, A and B are correlated, when A goes up B goes up and vice versa but A doesn’t cause B nor does B cause A.

23
Q

In genetic analysis, what is a complementary group?

A

Occasionally, multiple mutations of a single wild type phenotype are observed. The appropriate genetic question to ask is whether any of the mutations are a single gene or whether each mutations represents one of the several genes necessary for a phenotype to be expressed. The simplest test to distinguish between the two possibilities is the complementation test. The test is simple to perform - two mutants are crossed, and the F1 is analyzed. If the F1 expressed the wild type phenotype, we conclude that each mutations is in one fot two possible genes necessary for the WT phenotype. When it is shown genetically that two genes control phenotype the genes are said to form a complementary group. Alternatively, if the F1 does not express the WT phenotype, but rather a mutant phenotype, we conclude that both mutations occur in the same gene.