topic 7: Genetics, populations, evolution and ecosystems Flashcards
How many antigen-determining alleles will be present in a white blood cell
2 = white blood cells are diploid cells
-alleles are present on each chromosome of an homologous pair
-one maternal allele and one paternal allele
notes from the specification
The individuals of a species share the same genes but (usually) different combinations of alleles of these genes. An individual inherits alleles from their parent or parents.
A species exists as one or more populations. There is variation in the phenotypes of organisms in a population, due to genetic and environmental factors. Two forces affect genetic variation in populations: genetic drift and natural selection. Genetic drift can cause changes in allele frequency in small populations. Natural selection occurs when alleles that enhance the fitness of the individuals that carry them rise in frequency. A change in the allele frequency of a population is evolution.
If a population becomes isolated from other populations of the same species, there will be no gene flow between the isolated population and the others. This may lead to the accumulation of genetic differences in the isolated population, compared with the other populations. These differences may ultimately lead to organisms in the isolated population becoming unable to breed and produce fertile offspring with organisms from the other populations. This reproductive isolation means that a new species has evolved.
Populations of different species live in communities. Competition occurs within and between these populations for the means of survival. Within a single community, one population is affected by other populations, the biotic factors, in its environment. Populations within communities are also affected by, and in turn affect, the abiotic (physicochemical) factors in an ecosystem.
genotype vs phenotype
-genotype = genetic constitution of an organism
-phenotype = expression of this genetic constitution and its interaction with the environment
nature of alleles
-alleles can be recessive, dominant or co-dominant
-In a diploid organism, the alleles at a specific locus may be either homozygous or heterozygous.
monohybrid inheritance
-monohybrid inheritance looks at how the alleles for a single gene are passed on from one generation to the next
-when 2 individuals sexually reproduce there is an equal chance of either allele from their homozygous pair making it into their gametes. This means there is an equal chance of the zygote inheriting either allele from their parent
monohybrid diagrams (F1 generation)
One of the genes for the coat colour of horses has the following two alleles:
B, a dominant allele produces a black coat when present
b, a recessive allele produces a chestnut coat when present in a homozygous individual
In this example a heterozygous male is crossed with heterozygous female
Parental phenotype: black coat x black coat
Parental genotype: Bb Bb
Parental gametes: B or b B or b
Ratio of black to chestnut = 3:1 (phenotype)
Genotype ratio = 1:2:1
dihybrid inheritance
-dihybrid inheritance = involves the inheritance of 2 characteristics coded for by 2 different genes located on 2 different chromosomes
genotype + homozygous + heterozygous
What is the genotype: Bb
Explanation: they must be carriers of the round eye allele bc they are able to produce offspring with round eyes (bb)
GG + NN = homozygous dominant
Pure bred homozygous = AA
Mendel
-investigated the inheritance of 2 characteristics of a pea plant at the same tie
-observed flower colour, position, pea colour, pea shape
Producing the F1 generation
Phenotype: Round yellow Wrinkled Green
Genotype: RRYY rryy
Gametes: RY ry
Draw punnet square
Offspring genotype: RrYy
Offspring phenotype: Round yellow
Phenotypic ratio = 1:0
Producing the F2 generation
Phenotype: Round yellow Round yellow
Genotype: RrYy RrYy
Gametes: RY, Ry, rY, ry RY, Ry, rY, ry
Draw Punnet square (4 x 4)
Offspring phenotypes: round + yellow : round + green : wrinkled yellow : wrinkled green
Phenotypic ratio = 9 : 3 : 3 : 1
law of independent assortment
Law of independent assortment = each member of a pair of alleles may combine randomly with their of another pair
co-dominance
-when 2 dominant alleles are expressed in the phenotype (due to a pair of alleles being equally dominant)
Calculating co-dominance
Phenotype: Black Hen White Hen
Genotype: C^B C^B C^W C^W
Gametes: C^B C^W
Offspring genotype = C^B C^W
Offspring phenotype = speckled Hen
Phenotype: speckled speckled
Genotype: C^B C^W C^B C^W
Gametes: C^B C^W C^B C^W
Draw punnet square
Speckled : Black : White
2 : 1 : 1
Phenotype: the observed characteristic due to the genetic constitution of an organism and its interactions with the environment
position of a gene on a particular DNA molecule
locus
homozygous
bb
heterozygous
Bb
true or false = only one pair of alleles can be present in a single gamete
true
what is meant by the term phenotype
the observed characteristic due to the genetic consitution of an organism and its interaction with the environment
Gametes of AaBb genotype
AB, Ab, aB, ab
gametes of aabb
ab
explain 2 reasons why the fruit fly is a useful organism for studyin genetic corsses
1) large sample (400 eggs)
2) short life cycle 7-14 days so can produce many crosses in a short length of time
suggest one reason why observed ratios are often not the same as expected ratios
random fertilisation of gametes
male fruit flies are more likely than female fruit flies to show a phentype produced by a recessive allele carried on the x chromosome. Explain why
-males = one allele for recessive to be shown in phenotype
-females = need 2 recessive alleles to be present in phenotype
explain what is meant by a dominant allele
allele which is always expressed in the phenotype
suggest one reason why farmers would want the calves to be all of the same sex
-females = milk production
-males = meat
-male or female for breeding
explain what causes the sperms of one kind to have 3% more DNA than sperms of the other kind
sperm with more DNA has X chromosome which is larger than Y
in fruit flies the genes for body colour and wing length are linked. Explain what this means
genes are on the same chromosome
use your knowledge of gene linkage to explain these results
-autosomal linkage means that genes on the same chromosome are inherited togethe
-this means that most offspring were GGNN or ggnn
-however due to crossing over some gametes were Gn or gN meaning that some offspring were GgNn or ggNn
give reason for your choice of statistical test
chi squared
categorical data
why are the phenotypic ratios not the same as expected ratios. Give 2 reasons
1) Random fertilisation of gametes
2) crossing over linked genes
sex linkage male genotype =
X^a Y
heterozygous definition
pair of homologous chromosomes carrying 2 different alleles for the same gene
codominance definition
both alleles are equally dominant and expressed in the phenotype
genotype for carriers of CF
what is the probability that 2 carriers of cystic fibrosis would have a girl sufferer
Cc = one dominant and one recessive
cc = recessive = 25%
chance of girl = 50%
25% x 50% = 12.5%
how to know its a monohybrid question
only 2 possible phenotypes
gametes for RRYY
RY
when parental genotype is not homozygous then there are more options than e.g ab for the gametes
sex linkage
-humans have 23 pairs of chromosomes
-22 of these have homologous partners (autosomes)
-23rd pair = sex chromosomes
Any gene carried on the X or Y chromosome is sex linked
female vs male chromosome
XX = female
XY = male
The Y chromosome
Y chromosome is shorter than the X chromosome
This means that homologous chromosomes arent present across the entire length of the X chromosome as Y is shorter (only one homologous pair)
Recessive disorders and genetic disorders are more common as females require 2 recessive alleles on sex chromosome while males require only 1 on the X chromosome to express a recessive phenotype
cannot form typical bivalent
-XY chromosomes are not homologous along the entire length of the chromosome so crossing over doesnt occur. Y is shorter than X chromosome which means a typical bivalent doesn’t form. Chromatids cannot pair up due to short pairing region
typical bivalent
Typical bivalent = cross over of 2 homolgous pairs
Predict the genotypes of offspring of a female who carries the allele for haemophillia and a normal male:
Phenotype: Female carrier Male carrier
Genotype: X^H X^h X^H Y
Gametes: X^H X^h X^h Y
Female normal : male normal : female carrier : male sufferer
1: 1 : 1: 1
autosomal linkage
-refers to the inheritance of genes carried on the same autosome
-the further apart 2 genes are on autosomes the higher the chance of crossing over and therefore genetic variation
Model answer : autosomal linkage
Phenotype: grey body, long wings black body, short wings
Genotype: GgNn ggnn
Gametes: GN, Gn, gN, gn gn
Phenotype: Grey long, grey short, black long, black short
1: 1 : 1 : 1
multiple alleles
Multiple alleles –> where there are more than 2 alleles of which only 2 may be present at the loci of an individuals homologous chromosomes
Any two genes that occur on the same chromosome are said LO be linked.
in a male with AS where would the sex linked mutation be located
non-homologous section of an X chromosome
null vs alternate hypothesis
-Null hypothesis –> there is no relationship between variables (observed and expected results)
-Alternate hypothesis –> there is a relationship between variables
epistasis + pedigree analysis
Peidgree analysis = show the inheritance of a particular phenotype over several generations
Epistasis:
-9:4:3
-one gene affects the expression of another gene to determine some of the phenotype
characteristics of chi-squared test
-large sample size
-discrete categories e.g hair colour
-data is provided as raw count (not percentages)
-comparing experimental with hypotheical results
chi squared equation
Chi squared (X^2) = sum of (observed – expected)^2 / expected results
We square the numbers to make sure there arent any negative values
0.05 = critical value
calculating degrees of freedom
Calculating degrees of freedom = number of categories – 1
do we accept or reject the null hypothesis
If chisquared values are below 0.05 we accept the alternate hypothesis and reject the null hypothesis
If chi-square values are above 0.05 we accept the null hypothesis and reject the alternate hypothesis
A heterozgous pair of rabbits for coat colour and ear length were crossed and the following offspring were produced
calculate observed results and total
total / 9:3:3:1 ratio
calculate expected results
input in equation
find degrees of freedom
look at critical value tables
p and q
-p = dominant
-q = recessive
define population
Population –> group of organisms of the same species occupying a particular space at a particular time that can potentially interbreed
define gene pool
Gene Pool –> all of the alleles of all of the genes of all the indviduals in a population at a given time
Larger gene pool = greater genetic diversity
Small gene pool = increase in recessive mutations + less genetic diversity
e.g in a population of 10,000 people the gene pool is 20,000 alleles for a single gene
2 hardy weinberg equations
-p + q = 1
-p^2 + 2pq + q^2 = 1
what does the hardy weinberg equation tell us
The frequency of dominant and recessive alleles will remain constant in a population from one generation to the next provided certain conditions are met
–> population is large
-no migration in or out of the population
-there are no mutations resulting in new alleles in the population
-mating is taking place randomly within the population
The allele y for blue pigmentation occurs with a frequency of 0.78 in a populatin of clams. Give the frequencies of the genotyypes YY, Yy and yy.
1) p + q = 1
2) p^2 + 2pq + q^2 = 1
3) P + 0.78 = 1
4) p = 0.22
5) (0.22)^2 + 2(0.22x0.78) + (0.78)^2
Yy = 0.0484
YY = 0.3432
Yy = 0.6084
The gene for albinism is known to be a recessive allele. 7ppl in a sample of 10,000 were found to have albino phenotypes. 9993 had skin pigmentation that was normal. Assuming the hardy-weinberg equilibrium what is the allele frequency for the dominant pigmentation allele in this population.
1) p + q = 1
2) p^2 + 2pq + q^2 = 1
3) q^2 = 0.0007
4) q = 0.0265
5) p + 0.0265 = 1 so p = 0.974
Find p2 value
explain the proportions of the two types of clover plant in different parts of the field
-both plants present in low slug density conditions as there is less selection pressure
-however only cyanide plants into high slug density conditions since cyanide can kill slugs so more survive
the inheritance of body colour in fruit flies was investigated. 152 = grey 48 = black
give the genotype of parents and explain
Gg
ratio 3:1
explain why a statistical test should be applied to the data obtained in this investigation
to determine the probability of results being due to chance
what does the hardy weinberg principle predict about the frequency of the t alleles afte another 10 generations
frequency remains the same
suggest 2 factors that scientists should have taken into account when selecting people
age
sex
family history
recreational drugs
explain how resistance to an antibiotic could become widespread in bacterial population following a gene mutation
-frequenct use of antibiotic creates selection pressure
-bacteria with…..
-reproduce and pass on alleles…
-overtime allele freqency increases
-frequency of resistant types increase in subsequent generations