topic 4 Flashcards
eukaryotes vs prokaryotes
longer vs shorter
histone proteins vs no histone proteins
linear vs circular
mitochondri and chloroplasts DNA
similar to prokaryotes as shorter, circular and not bound by histone protein
gene
base sequence of DNA that codes for
amino acid sequence of a polypeptide
functional RNA
locus
fixed position of gene on the chromosome
the features of the genetic code
degenerate
universal
non overlapping
degenerate- more than one codon codes for the same amino acids so mutations may result in no effect as even though the codon has changed, it still produces the same amino acid
universal- the same codons code for the same amino acieds in most organisms on earth
non overlapping- each codon is read as a discrete unit
adfvantage as if mutation occurs, it will only affect one codon and one amino acid.
introns and exons
introns- sections of DNA that do not code for polypeptides
introns are only in eukaryotic not prokaryotic DNA
Exons are sequences of DNA that do not code for amino acids
in eukaryotes a lot of the nuclear DNA is made up of introns
codon
3 bases on mRNA that code for specific amino acid
start codon
3 bases at the start of the gene which intiiate translation
stop codon
3 bases at the end of the gene which cause the ribosome to detach and translation stops.
genome and proteome
genome- organisms’s entire srt
mRNA
has a codon
complimentary to tRNA anticodon
short
length of one gene
found in the cytooplasm and nucleus
tRNA
has a sequencee of three basees/anticodon, which is complimentaaary to mRNA codon
single stranded
clover leaf shape
held in place by hydrogen bonds between complimentary bases
brings specific amino acids to the cytoplasm
each tRNA is specific to one amino acid
transcription
occurs in the nucleus
DNA helicase enzyme breaks hydrogen bonds between cmomplimentary bases, separating the two polynucleotide strands
free mRNA nucleotides align opposite complimentary exposed DNA bases
enzyme RNA polymerase joinss adjacent nucleotides by fforming phosphodieesster bonds.
formation of pre mRNA
introns removoed from premRNA through splicing to form mRNA
only one strand of DNA acts as a template
translation
mRNA attaches to ribosome at start codon
tRNA anticodon aligns opposite mRNA codon
tRNA brings specific amino acids to the cytoplasm
two amino acids are joined via a peptide bond- requires an enzyme and ATP
ribosome moves along codon on mRNA
continues until ribosome reaches stop codon- ribosome dettaches and polypeptide chain released
polypeptide chain is now formed and enters golgi apparatus for folding and modification
chromsome mutations- non disjunction
chromsomes/chromatids do not separate equally during anaphase of meiosis