Things to remeber for exams - specific cases Flashcards
1
Q
what to watch for in diamond structure
A
- CCP/FCC based but not fully because the close packed direction is on [111] NOT on [110] i.e. body diagonal NOT face diagonal
- this is not obvious because there are not atoms all the way across the body diagonal so atomic separation (centre to centre) is 1/4 [111] or 1/4 sqrt(3) a
- also inversion centre is not where expected, it’s at (1/8,1/8,1/8)
- there are more diagonal mirror planes than expected
2
Q
what structure does glass generally have, why would heat treated glass act differently
A
- generally glass is non-crystalline, isotropic and non-birefringent
- heat treated glass may become crystalline especially near the edges as this would be the first site of nucleation (heterogeneous)
- Hence certain regions at the edges of heat treated glass may be birefringent
3
Q
what is a useful equation in determining the magnitude of our burgers vector
A
FOR bcc and fcc:
b = mod(~b~) = a/2 sqrt(u^2 +v^2 + w^2)
where
a/2 [UVW] is our burgers vector
4
Q
what does the cooling curve for a hypo (or hyper) -eutectic composition look like
A
- initially linear negative
- change of gradient, still linear negative as entering L+α region
- then horizontal section where liquid undergoes eutectic transformation
- then decreasing again
5
Q
when calculating microstructure proportions for a eutectic alloy (even if cooled to room temperature), what temperature should we calculate it for
A
- the eutectic temperature