Things to remeber for exams - specific cases Flashcards

1
Q

what to watch for in diamond structure

A
  • CCP/FCC based but not fully because the close packed direction is on [111] NOT on [110] i.e. body diagonal NOT face diagonal
  • this is not obvious because there are not atoms all the way across the body diagonal so atomic separation (centre to centre) is 1/4 [111] or 1/4 sqrt(3) a
  • also inversion centre is not where expected, it’s at (1/8,1/8,1/8)
  • there are more diagonal mirror planes than expected
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2
Q

what structure does glass generally have, why would heat treated glass act differently

A
  • generally glass is non-crystalline, isotropic and non-birefringent
  • heat treated glass may become crystalline especially near the edges as this would be the first site of nucleation (heterogeneous)
  • Hence certain regions at the edges of heat treated glass may be birefringent
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3
Q

what is a useful equation in determining the magnitude of our burgers vector

A

FOR bcc and fcc:

b = mod(~b~) = a/2 sqrt(u^2 +v^2 + w^2)
where
a/2 [UVW] is our burgers vector

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4
Q

what does the cooling curve for a hypo (or hyper) -eutectic composition look like

A
  • initially linear negative
  • change of gradient, still linear negative as entering L+α region
  • then horizontal section where liquid undergoes eutectic transformation
  • then decreasing again
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5
Q

when calculating microstructure proportions for a eutectic alloy (even if cooled to room temperature), what temperature should we calculate it for

A
  • the eutectic temperature
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