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Materials IA > Course B - Materials for Devices > Flashcards

Course B - Materials for Devices Flashcards

1
Q

define a dielectric material

A

“A dielectric material is an electrical insulator that can be polarised by an applied electric field”

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2
Q

give 3 polarisation mechanisms

A

1) electronic - distortion of an electron cloud around a nucleus

2) ionic - elastic distortion of an ionic bond

3) orientational - rotation of permanent dipole molecules

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3
Q

give the equation (LEARN) for dipole moment

A

the dipole moment between two opposite charges +q, -q, separated by r is

μ = qr

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4
Q

give the equations (3) for polarisation (LEARN)

A

Polarisation = total dipole moment per unit vol = charge per unit area

P = nμ
P = Q/A
n = dipoles per unit vol

and

P = εo E (κ-1)

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5
Q

give the equations (2) for the displacement field that forms when an electric field is applied to a dipole (LEARN)

A

D = εo E + P
D = ε E = κ εo E

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6
Q

give the equation for the capacitance on an empty and dielectric parallel plate capacitor (IN DATA BOOK)

A

Empty parallel plate
C = εo*A / L

dielectric parallel plate
C = ε*A / L

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7
Q

define centrosymmetric and non-centrosymmetric crystals

A

“Centrosymmetric crysals have an inversion centre”

“non-centrosymmetric crystals do not have an inversion centre”

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8
Q

give the possible polarities of a centrosymmetric crystal

A
  • centrosymmetric crystals have NO unique directions, hence they CANNOT be polar
  • whatever dipole forms on one side of the inversion centre will be perfectly cancelled by a dipole that forms on the other side
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9
Q

give the possible polarities of a non-centrosymmetric crystal

A

non-centrosymmetric crystals can be polar or non-polar

  • polar if they contain a unique direction
  • non-polar if they don’t
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10
Q

define piezoelectricity

A

“A change in polarisation due to the application of stress”

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11
Q

give the equation for the change in voltage due to stress for piezoelectric materials

A

ΔV = dσL/κεo

L = thickness
d = piezoelectric const.

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12
Q

give the necessary property of a crystal for piezoelectricity

A

piezoelectricity occurs in any non-centrosymmetric crystal because the positions of the charges move relative to each other

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13
Q

give the two effects that piezoelectric crystals are used for

A

Generator effect = stress changes, voltage change

motor effect = voltage change, change in shape

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14
Q

define pyroelectricity

A

“pyroelectricity is a change in polarisation due to a temperature change”

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15
Q

give the necessary property of a crystal for pyroelectricity

A

pyroelectricity only occurs in polar crystals because in non-polar crystals there is no relative motion between ions

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16
Q

give the equation for change in polarisation due to a temperature change for a pyroelectric crystal

A

ΔP = pΔT
p = pyroelectric constant

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17
Q

give the equation for change in voltage due to a temperature change for a pyroelectric crystal

A

ΔV = p Δt L / κ εo

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18
Q

give an example of a pyroelectric crystal and a use of pyroelectric crystals

A

Wurtzite = ZnS
Hex p lattice with half of tetrahedral interstices filled
only upwards pointing tetrahedrons filled so unique direction = [001]

used in burglar alarms

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19
Q

define ferroelectricity

A

“Stable, spontaneous polarisation which can be reversed by an external electric field”

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20
Q

when does ferroelectricity occur, what can we say about net polarisations in the absence of an electric field

A
  • below the curie temperature Tc, the unit cell moved to a lower crystallographic symmetry
  • a displacive phase transition occurs on cooling through Tc and the unit cell becomes non-centrosymmetric and gains a dipole
  • even though each unit cell contains a dipole, in the absence of an electric field there will be no net dipole on a crystal (unless it has already been poled)
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21
Q

explain how Ferroelectricity (FE) occurs in a perovskite structure (ABO3)

A

in a perovskite structure (ABO3) (usually BiTiO3) FE occurs due to B atom displacement, there are large A atoms, small B atoms

  • on cooling the crystal changes from cubic to tetragonal
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22
Q

define a domain

A

“A domain is a region in a material in which the polarisation is in the same direction”

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23
Q

what is domain wall energy

A

domain wall energy is the energy that arises at the boundary between different domains, it is minimised when aligned domains are next to each other

“There is an energy associated with the interface between differently aligned domains, hence it’s more efficient to have the same domains next to each other”

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24
Q

what is stray field energy

A

when there are large domains of the same polarisation, there is an energy cost as a field forms
UE = 1/2 ε E^2

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25
Q

what can we say about the size of domains given the two energy factors at play

A
  • it is a balance between domain wall energy and stray field energy
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26
Q

what can we say about the angles between domains in a single crystal

A
  • the angles between domains in a single crystal depend on the symmetry of the crystal and the preferred dipole direction
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27
Q

what can we say about the orientation of FE dipoles in a polycrystal when in an external electric field

A

they will align on the crystallographic direction closest to that of the field

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28
Q

explain hysteresis in a FE crystal, give the 6 stages, how do the domain walls move

A
  • hysteresis occurs when a cycling E field is applied to an FE

consider a graph of P (on Y) against E (on X):
1) start at origin, unpolarised, dipoles point in many directions, no field

2) field applied, domains in the same direction as E field grow as this is more energy efficient, polarisation increases, irreversible domain wall motion

3) saturation polarisation Psat is reached, all domains aligned with E field

4) E field removed, polarisation remains as the sample has been ‘poled’

5) field is reversed, domain wall motion starts to occur in opposite direction, polarisation decreases, E = Ecoercive at point where P = 0

6) same as 3 but in opposite direction

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29
Q

give some uses of ferroelectrics

A
  • as piezo or pyro electrics
  • as dielectrics
  • memory devices, +P and -P can be used as 0,1 in computing
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30
Q

when (considering electron shells) does magnetism occur

A
  • Partially filled electron shells
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31
Q

give the equation for a magnetic moment (IN DATA BOOK)

A

m = IA
I = current (A)
A = area (m^3)

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32
Q

give two equations for magnetism

A

M = m/V

M = χ H

χ = susceptibility (unit-less)
H = mag. field strength

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33
Q

define diamagnetism

A

“Change in orbital motion of electrons due to applied B field”

  • all atoms are diamagnetic
  • V weak effect
  • not permanent
  • electron orbits change to oppose applied field
  • χ = -ve, V small
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34
Q

define paramagnetism

A
  • some electrons in partially filled shells, dipoles exist
  • they are isolated/ non-interacted
  • with no field there is no magnetisation
  • when field, moments align with field
  • χ = +ve, v small
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35
Q

define ferromagnetism

A
  • many unpaired electrons, strong interaction between moments
  • moments align with each other, lowest exchange interaction energy
  • moments align with an external applied field, orientation becomes permanent, large M
  • χ = large, +ve
36
Q

define antiferromagnetism

A
  • many unpaired electrons, strong interaction between moments
  • antiparallel moments are lowest energy
  • sets of antiparallel moments exactly cancel
  • net M = 0
  • χ = small, +ve
37
Q

define ferrimagnetism

A
  • moments exist, strong interaction between moments
  • antiparallel moments form
  • moments on sub-lattices not equal so net magnetisation
38
Q

what is exchange interaction energy, how does it link to ferromagnets

A
  • comes from Pauli exclusion principle
  • lowest energy is where electrons have the same spin part but different spacial parts
  • means misaligned moments are higher energy
  • Ferromagnets form at lower temperatures because EIE ‘wins’ over thermal energy to give aligned moments
39
Q

Define magnetocrystalline anisotropy

A

the interaction between the crystal lattice and the magnetic moments mean energy can be higher or lower depending on direction of B fields

easy axis = easy to magnetise on this direction, Msat reached at lower field

Hard axis = harder to magnetise on this direction, Msat reached at higher field

40
Q

define shape anisotropy (linking to magnetism)

A
  • it is easier to magnetise along the length of an object
41
Q

define magnetostriction

A

“a change in shape when a material is magnetised”

Λ = magnetostriction coeff = fractional change in length when magnetisation from 0 —> Msat

42
Q

why may ferromagnets not necessarily be magnetised

A
  • Ferromagnetic materials are not necessarily magnetised as stray fields have an energy cost
  • so different domains form, each domain is magnetised but in different directions
43
Q

what are domain/bloch walls in ferromagnets, what are the two factors which determine how wide/narrow they are

A

“A domain wall or Bloch wall is a transition between two differently oriented domains in a ferromagnet”

1) exchange interaction energy (EIE)
- lowest when misaligned spins are apart
- encourages wide Bloch walls

2) magnetocrystalline anisotropy energy
- lowest when moments align with the easy axis of the material
- minimised by aligning spins with preferred directions so encourages narrow walls

actual width determined by balance of these

44
Q

give the stages of ferromagnetic hysteresis

A

consider an M (magnetisation) (on Y) against H (magnetic field) (on X) graph

1) no net magnetisation, many different domains all aligned with easy axis
2) as H increases, domain walls move, M increases, irreversible due to domain wall pinning
3) whole sample aligns on easy axis as 1 domain
4) moves away from easy axis to align with H, Msat reached
5) applied field reduced, M decreases as moments align with easy axis again
6) field reversed, domain growth in opposite direction

7) M = 0, many different domains, then repeats in opposite direction

45
Q

what is the spinel structure

A
  • Fcc oxygen sublattice conventional cell
  • 4 octahedral interstices - 1/2 are occupied by trivalent ions (Al3+)
  • 8 tetrahedral interstices - 1/8 occupied by divalent ions (Mg2+)
46
Q

what is the inverse spinel structure, what is its significance

A
  • same as spinel structure but now consider Fe(2+)O Fe(3+)O3
  • Fe2+ is in an octahedral interstice
  • Fe3+ are half in octahedral interstices and half in tetrahedral interstices
  • the Fe3+ magnetisations cancel as the octahedral and tetrahedral interstices point in opposite direction
  • the Fe2+ give an overall magnetisation
  • it is Ferrimagnetic
47
Q

define ionic mobility

A

“Ions/Atoms aren’t stationary on their lattice sites, they can migrate through the lattice by swapping positions with other ions through vacant sites”

48
Q

what are the main two factors on ionic mobility (just state)

A

1) number density of vacant sites
2) energy barrier between sites

49
Q

explain the factor of number density of vacant sites on ionic mobility, give the two types of defect that lead to vacant sites

A
  • we can either have vacancy defects where an atom/ion is missing or an interstitial defect where there is an extra atom in an interstice

this leads to:
1) Shottky defect: A- vacancy, B+ vacancy
2) Frenkel defect: B+ vacancy, B+ interstitial

50
Q

explain the factor of energy barrier between sites on ionic mobility, give the equations which determine this

A
  • for an ion to be able to move through a lattice, it must be able to overcome the energy barrier, Q
  • mobility or diffusivity, D, depends upon probability it can overcome barrier
  • defined by Arrhenius
    D = Do exp(-Q/RT)
    D = Do exp(-Q/kT)

D = diffusivity

51
Q

when can we have a net current flow from ionic mobility/ which two things will create a net current flow

A

1) a concentration gradient of ions or vacancies - leads to diffusion current

2) an electric field, E, leads to drift current

52
Q

explain how a diffusion current (ionic motion) forms and give the suitable equations for it

A
  • we can define J, diffusion flux, number of ions crossing a unit area per unit time
    J = I/A = -D dn/dx

ions diffuse DOWN a conc. grad so -ve

diffusion current density (Am^-2) = jdiff = -qD dn/dx

  • this ONLY applies to steady state diffusion in a uniform conc. grad.
53
Q

explain how a drift current forms (ionic motion) and give the suitable equations for it

A
  • if an electric field E is applied then the energy barrier to ionic motion increases in one direction and decreases in the other,

drift current density given by
jdrift = -σ dv/dx = σE

54
Q

how can drift currents and conc. grads be manipulated to show that applying an electric field leads to a conc. grad

A

we know
n = no exp(-qV/kT)
dn/dx = (-q/kt) n dv/dx = (qn/kt) E

so applying an electric field leads to a conc. grad.

55
Q

derive the nernst-einstein eq.

A
  • we know that appying an electric field leads to a drift current, it also encourages a conc. grad which leads to a diffusion current
  • at equil, they are equal and opposite

qD dn/dx = σE
qd (qnE/kT) = σE
σ/D = nq^2/kT
this is nernst-einstein eq.

various arrhenius plots can be made with this

56
Q

what is the general purpose of doping zirconia with Yttria to make YSZ

A
  • it stabilises the cubic Zirconia phase over a much larger temperature range
57
Q

what occurs (atomic level) when we make YSZ

A
  • fluorite structure
  • Y2O3 is added to ZrO2
  • Y3+ but Zr4+
  • so when two Zr4+ are replaced by two Y3+ there is a charge disparity
  • to conserve charge, when this occurs, an oxygen vacancy is formed so ionic motion can occur
58
Q

give an example (other than YSZ) of an ionic conductor

A

δ-Bi2O3
- same fluorite structure as YSZ
- Bi sublattice is FCC

On average in each unit cell:
- 8 tetrahedral oxygen sites
- 6 oxygens filling
- 2 oxygen vacancies

  • so ionic motion can occur
59
Q

explain the use of ionic conductors in oxygen concentration cells, explain how an oxygen concentration cell works

A
  • two electrodes both containing oxygen but at different partial pressures
  • YSZ solid electrolyte in between, which oxygen ions can move through to balance the partial pressures

reaction at cathode (reduction) = O2(g) + 4e- —> 2O(2-)

reaction at anode (oxidation) = 2O(2-) —> O2(g) + 4e-

then electrons move through external circuit back to cathode

E = -RT/4F ln(p(O2)(II) / p(O2)(I))
(Nernst eq.) (in data book)

60
Q

explain the use of ionic conductors in lambda sensors/ how lambda sensors work

A
  • fitted to exhaust systems to measure oxygen levels and adjust fuel levels to maximise efficiency, minimise emissions
  • exhaust gas enters exhaust manifold, there are permeable Pt electrodes around a YSZ electrolyte and a heater the other side
  • voltage across electrodes is measured
  • this gives a difference in partial pressures between exhaust and atmosphere
  • linked to computer which adjusts air-fuel ratio to give complete stoichiometric combustion
61
Q

how does an oxygen pump work

A
  • same as an oxygen conc. cell but this time potential is applied to drive O2 from low conc. to high conc. area
62
Q

how do fuel cells work/ what is their general structure

A

“Fuel cells produce energy by direct oxidation of fuel”

general structure:
- Anode (porous) - must be electrically conductive
- Cathode (porous) - must be electrically conductive
- electrolyte, must be oxygen conductive but low e- conductive

63
Q

what are some types of fuel cells/ different electrolytes, different fuels

A

YSZ as electrolyte, O(2-) conducting, needs high operating temps
or
Polymer electrolyte membrane, H+ conducting, need Pt catalysts

either H2(g) as fuel or CH4(g) as fuel

1/2 cell reactions can usually be derived

64
Q

give the advantages and disadvantages of fuel cells

A

Advs:
- high efficiency
- little noise
- if no C in fuel then no CO2 emissions
- can run continuously if fuel is always provided

Disadvs:
- H2(g) storage challenging

65
Q

how can we derive the rms length of a polymer chain

A

if we model the polymer as a series of shorter rigid segments of length l, and that they can rotate freely where they join then

if chain stretched out then l=nl

Rn = (n)Σri
R(n-1) = (n-1)Σri

Rn = R(n-1) + rn
averaged we conclude <Rn> = 0 so we do rms
Rn = <R^2 n>^1/2
Rn ^2 = (R(n-1) + rn) dot (R(n-1) + rn) = R^2 (n-1) + 2(R(n-1) dot rn) + rn ^2
= R^2 (n-1) + (2R(n-1) l cosγ) + l^2
cosγ = 0</Rn>

so by induction
<Rn ^2> = nl^2

so rms length is sqrt(n)l

66
Q

what is the Kuhn length/ how can we use it

A
  • our rms model for polymer length does not consider how not all C-C bonds can rotate freely
  • Hence we make the model more accurate by defining Lk (the Kuhn length) as the length below which the chain is effectively straight
  • we consider a fewer number of larger segments
67
Q

what are liquid crystals

A
  • crystalline materials have long-range order so are anisotropic
  • non-crystalline materials and liquids are generally isotropic
  • Liquid crystals are anisotropic liquids where their anisotropy comes from their molecular shape
  • liquid crystals often consist of rod-shaped molecules with a long rigid axis
  • they are free to flow so have no long range positional order
  • there is some orientational order as their long axes remain roughly parallel
68
Q

what is a nematic LC structure

A
  • no positional oder
  • long range orientational order, they tend to align along a common axis, the director D
  • anisotropic
  • the degree of orientational order decreases with temp
69
Q

define the order parameter

A

a parameter used to describe the degree of orientational order
Q = (3<cos^2(θ)> -1) / 2

all aligned - Q = 1
all random - Q = 0

70
Q

difference between polarised and unpolarised light

A
  • polarised light has oscillations in 1 direction
  • unpolarised light has oscillations in many directions
71
Q

define the refractive index, n, of a material

A

n = c/v
c = speed of light in vacuum
v = speed of light in material

72
Q

what occurs to EM waves on passing through polymers, how does this change at higher temps

A
  • EM waves passing through a polymer will couple to electron density in the molecules
  • it will usually couple more strongly in one direction than another

at high temps:
- randomly aligned molecules so non net effect

at lower temps:
- one direction couples more so has a higher refractive index

73
Q

what are the fast and slow axes of a material, what are PVDs

A
  • the direction in which light couples strongly is the slow axis, light travels slower
  • the direction in which light couples weakly is the fast axis, light travels quicker
  • These directions are perpendicular, both to each other and to the propagation direction
  • they are called the PVDs, (permitted vibration directions)
74
Q

define birefringence

A

“Birefringence is the property of a material where refractive index depends on the polarisation and propagation directions of light”

birefringence = Δn

75
Q

what are polarisers

A

“polarisers are materials which only allow a specific polarisation of light to pass through”

  • usually polymer films with polymers uniaxially aligned
  • 2 polarising filters perp to each other let no light through
76
Q

what occurs when polarised light passes through birefringent materials, include suitable eqs.

A

Polarised light passing through a birefringent material is resolved into 2 components:
- 1 along fast axis
- 1 along slow axis
- ONLY along PVDs
- unless perfectly aligned to 1 PVD then no splitting

the difference in speeds of light along each PVD creates an optical path difference (OPD)
ΔT = Δnt/c = phase difference
OPD = tΔn
t = thickness

δ/2π = Δnt / λ

77
Q

what occurs when there is a birefringent sample between two polarisers, which wavelengths of light are removed, which remain

A
  • light passes through polariser, polarised light remains, it then passes into material and splits into two components
  • as passing through birefringent sample OPD occurs
  • if OPD is λ/2 then δ = π radians, 180° so polarisation of light is rotated through 90 degrees and it can pass through the second polariser, light is transmitted
  • if OPD is nλ then δ = 2nπ radians, n(360°) so polarisation does not change and it cannot pass through the analyser so is removed
78
Q

what occurs when white light passes through two crossed polars and a birefringent material

A
  • white light is formed from all possible λs
  • phase difference δ depends on λ

when between crossed polars:
- most λs pass through
- certain λs where OPD = nλ don’t
- these colours are removed and the resultant colour is observed

  • these can be analysed using the michel-levy chart
79
Q

what are extinction positons

A
  • this occurs when the incident polarised light has a plane of polarisation parallel to one of the PVDs
  • it simply passes directly along a PVD and no OPD occurs
  • it is not rotated
  • it will be moved by the analyser
80
Q

how can we determine the sign of birefringence

A
  • add a compensator of a known birefringence
  • align both sample and compensator so that PVDs are at 45 degrees to polariser/analyser

Addition:
- if the fast axes of sample and compensator and slow axes of sample and compensator align then greater OPD, colour higher on michel-levy chart

Subtraction:
- if fast axis of sample aligns with slow axis of compensator and vice versa then lower OPD, and colour lower on michel-levy chart

81
Q

are LCs birefringent, what are their PVDs

A

LCs are birefringent, their PVDs are para and perp. to the director

82
Q

what is a smectic LC

A

the molecules arrange in layers

83
Q

what is a chiral nematic LC

A
  • contains a helical twist
  • greater twist at higher temps
  • also greater twist for shorter molecules
84
Q

explain the structure of an LCD

A
  • the director of an LC can be made to lie in a particular direction by creating grooves on a surface it is in contact with
  • if a nematic LC is sandwiched between two plates with perp grooves then it twists across the sandwich and makes a twisted nematic structure
85
Q

explain the on/off states of an LCD

A

ON: light enters through bottom polariser, twisted by nematic structure, makes it aligned with top polariser, passes through top polariser as normal, light fully transmitted

OFF: electric field applied, the molecules tend to align with the field, Freedericksz transition, molecules near plates align with grooves, molecules in middle become vertical, no twisting, no light transmission

86
Q

Can a resultant voltage occur on a piezoelectric polycrystal without it being Ferroelectric,

what about a single crystal?

A
  • If polycrystalline, the induced polarization would occur in different directions in the differently oriented grains
  • this leads to zero net polarization, and
    hence zero voltage
  • therefore to obtain a resultant voltage it must be ferroelectric and poled
  • single crystals can display piezoelectricity without poling so no ferroelectricity is required

Materials IA (9 decks)

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