Thermochemistry Flashcards
exothermic
produces heat
temperature rises
delta H -ve
involves making bonds
endothermic
Absorb (take in) heat
Temperature falls (feel cold)
ΔH is +ve
Involves breaking bonds
Heat changes of Physical Changes
solid => gas sublimation (endo) gas => solid (exo) liquid => gas evaporation (endo) gas => liquid condensation (exo) solid => liquid melting (endo) liquid => solid solidification (exo)
Exothermic Reaction Profile
starts of high and ends low nearly touching the X-axis X- axis ( energy ) Y- axis ( reaction pathway ) delta Hr heat change -ve activation energy without catalyst effect of adding catalyst activation energy lowered by catalyst reactanst product
Endothermic Reaction Profile
X- axis energy Y- axis reaction pathway reactant product activation energy delta H - heat taken in absorbed catalyst E act starts of low then ends high
bond energy
Average energy required to break 1 mole of bonds
into separate atoms in the gaseous state
Heat of Combustion
Heat of Reaction
Heat of Formation
Heat change when one mole of a substance is burned completely in excess oxygen
Heat change when The number of moles of reactants in the balanced equation react completely
Heat change when 1 mole of compound formed from its elements in their standard states
Hess’s Law
Law of Lavoisier and Laplace
The heat change for a reaction is the same whether the reaction takes place in one step or several steps
heat change for the forward reaction is equal to the heat change for the reverse reaction, but opposite in sign
what measures heat produced when substances burn
Bomb Calorimeter
how is the heat produced calculated
H = m c ΔT
H = heat change
m = mass (usually kg);
c = specific heat capacity:
ΔT = temperature change (oC)
Bomb Calorimeter
To get accurate results we use a Bomb Calorimeter
Oxygen pumped in under pressure to ensure rapid and complete combustion
Often so rapid that it exploded
Hence the name “ bomb calorimeter”
Bomb Calorimeter is accurate because
Fast
Complete
There are no side reactions
There is no heat loss
Three things must apply if a reaction is to be suitable for study in a calorimeter
It must be rapid
It must go to completion
Must have no side reactions
combustion equation
write down the compound to be burnt
then add
+ O2 = CO2 + H20
then balance
calculate calorific value
example
If the heat of combustion of ethane is -1560 kJ mol-1calculate its kilogram calorific value.
1 mole = -1560 kJ C2H6 = 12 * 2 + 1*6 = 30g 30g = -1560 1 g = -1560/30 1000g = (-1560/30) * 1000 = -52000 kJ kg-1