The Photoelectric Effect Flashcards
On what factors do the magnitude of photoelectric current, the velocity or ejected electrons depend during photoelectric emission?
Photoelectric current depends on the intensity of the incident light, and the velocity of the emitted photo electrons depends on the frequency of the incident light. Both are directly proportional to their respective factors.
What is meant by threshold wavelength?
The maximum wavelength beyond which photo electrons cannot be emitted from a meta surface.
Two metals A and B have work functions 4 eV and 6 eV respectively. Which metal has lower threshold wavelength for photoelectric effect?
Metal B, because energy is inversely proportional to wavelength. The lower the wavelength, the higher the energy.
Does ‘threshold frequency’ depend upon the frequency of the incident light?
No, it depends on the source of the light and is a factor in determining the velocity of the velocity and kinetic energy of the emitted photo electrons.
What is cut-off or stopping potential?
It is the ‘negative’ potential applied to the second plate of the metal surface from which photo electrons are emitted. At this value, photoelectric current completely stops as electrons do not possess enough kinetic energy after emission from the first plate to reach the second plate due to the high difference in negative potential.
What is meant by the kinetic mass of a photon? What about momentum?
The mass produced due to the motion of the photon (=hf/c^2). However, rest mass is 0.
The momentum of a photon is the product of the Kinetic mass of a photon and its velocity.
How many photons are effective in the emission of one photo electron? Does every photon eject a photo electron?
One photon is effective enough for emission.
Not every photon may eject a photo electron, depending on the distance between the electron and the metal surface and the amount of energy it loses in collisions.
Radiation of frequency 10^15 Hz falls on surfaces P, Q and R. P does not emit electrons, Q emits electrons with zero KE and R emits electrons with KE. What can you say about each surface?
P has the greatest work function, Q requires exactly 10^15 Hz for emission of electrons and so cannot provide KE to its electrons, R has the least work function with threshold frequency below the given amount.
How is Stopping Potential related to Kinetic Energy?
eVo=0.5mv^2
Photons of energies twice and five times the work function fall upon a metal surface. What will be the ratio of their maximum velocities?
Using the equation E=hf+1/2mv^2,
Substitute 2hf and 5hf respectively and divide the two equations to obtain the answer:
1:2
Which of these will be most effective for electron emission: microwave, infrared, ultraviolet?
Ultraviolet, having the largest frequency and the smallest wavelength of all the mentioned rays.
Why are alkali metals most suited for photoelectric emission?
Alkali metals have comparatively lower work functions. So, visible light which is readily available is able to eject photo electrons from them.
If the maximum kinetic energy of electrons emitted by a photocell is 4 eV, what is its stopping potential?
Using the formula KE=eVo,
Vo=4 Volts
(Remember, if KE is in eV, it is the same as the stopping potential in terms of value).
A mirror reflects about 80% of visible light incident on it. How will you find out whether 20% of the photons have not been reflected at all or all the photons have been reflected but their energy has been reduced by 20%?
The first part of the question is true, and the second false.
If the energies were reduced by 20%, then the wavelength would have increased (inversely proportional) and the colour would have changed. However, this does note occur.
Calculate the momentum of a photon of energy 6*10^-19.
p=E/c
=(610^-19)/(310^8)
=2*10^-27 kg m/s