Bohr's Theory Of Hydrogen Atom Flashcards
Why was ‘gold’ foil used in Rutherford’s experiment?
Gold consists of heavy atoms which could produce much larger deflections in the path of the alpha particles. It is also very malleable and can be beaten into a thin sheet, to ensure a ‘single’ collision.
What is the significance of the distance of closest of approach?
It leads to an estimation of the nuclear radius.
Fro the scattering of alpha particles, only the nucleus of the atom is responsible and not the electrons. Why?
Electrons are very light compared to alpha particles and due to conservation of momentum cannot scatter alpha particles.
Is the probability of scattering alpha particles at angles greater than 90o predicted by Thomson’s model less or greater than Rutherford’s?
It is less, because in Thomson’s model, the positive charge is spread out all over the atom which in Rutherford’s it is concentrated in a very small place.
What is the meaning of: ‘angular momentum of an orbiting electron is quantised’?
Electrons can revolve only in certain discrete orbits of definite radii.
Calculate the angular momentum of an electron in the third Bohr orbit of hydrogen atom.
Using J=nh/2pi,
Arrive at the answer 3.15*10^-34 Js
What is Bohr’s frequency condition?
f=(E2-E1)/h
Explain the meaning of ‘excited atom’.
When a normal atom gets appropriate energy from outside, it is raised from its lowest-energy state to some high-energy state. Then it can be called an excited atom.
The ionisation potential of hydrogen is 13.6 eV. Will it be more or less for helium?
More, because it will require more energy to excite an electron enough so that it can be released from the pull of the nucleus.
State the transition that emits the first line of the Balmer series of spectral lines of hydrogen.
n=3 —> n=2
If the hydrogen atom goes from the 3rd to the 2nd excited state, what kind of radiation is emitted?
Visible light, as it is part of the Balmer series.
On passing visible light through hydrogen, lines of which series are absorbed most and why?
The Lyman series lines are absorbed most because maximum absorption starts in the ground state when n=1.
Only certain definite lines are found in the atomic spectrum of substances. Why?
Atom has only certain definite energy states and so only certain definite frequencies can be emitted by electrons in the atom.
What is the radius of the second orbit of a hydrogen atom if it’s first radius is r?
Using radius=n^2(h^2epsilon)/(pimZ*e^2),
Get the answer 4r.
How can the energy of a Bohr orbit be calculated? Calculate for the third of the first is -27.2 eV.
Use the formulae E=-Z^2*Rhc/n^2
The answer is -3.02 eV.