Test 3 Flashcards

1
Q
A
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2
Q
A
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3
Q
A

syn addition

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4
Q
A
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5
Q
A

trans glycol

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6
Q
A

Syn addition

cis glycol

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7
Q
A
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8
Q
A

syn addition

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9
Q
A

syn addition

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10
Q
A

anti-markovnikov

Br on less subs c

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11
Q
A

markovnikov= OH on most subs C

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12
Q
A

markovnikov= OH on most subs C

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13
Q
A

anti-addition

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14
Q
A

anti-addition

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15
Q
A

syn addition, anti-markovnikov=OH on less subs C

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16
Q
A

anti-addition

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17
Q
A

anti-addition

18
Q
A
19
Q
A
20
Q
A
21
Q
A
22
Q
A

Other alkylating agents can be used: MeO and MeS

23
Q
A

K2Cr2O7 in aqueous H2SO4 may also be used

24
Q
A

2o alchohol most likely via SN1 so stereochem lost

25
Q
A
26
Q
A

best with 1o alcohols

27
Q
A

Best with 1o alcohols

28
Q

poor nucleophiles/weak bases

A

O with no formal charge

29
Q

Good nucleophiles/weak bases

A

Cl-, Br-, I-, NC-, N3-, S-, Se- or CH3COO-, or N, S, Se with no formal charge

30
Q

Good Nucleophile/strong base

A
31
Q

1o Carbon, poor Nuc/weak base

A

no reaction

32
Q

2o Carbon, poor Nuc/weak base

A

95% Sn1

5% E1

33
Q

3o Carbon, poor Nuc/weak base

A

95% Sn1

5% E1

34
Q

1o or 2o Carbon, good Nuc/weak base

A

Sn2

35
Q

3o Carbon, good Nuc/weak base

A

95% Sn1

5% E1

36
Q

1o Carbon, good Nuc/strong base

A

E2 w/ tert-butyl-oxide (bulky base), otherwise Sn2

37
Q

2o or 3o Carbon, good Nuc/strong base

A

E2

38
Q

Sn2

A

One Step: Nucleophile joins alpha carbon and leaving group leaves alpha carbon, inversion of stereochem

39
Q

Sn1

A

Step 1: leaving group leaves alpha carbon

Step 2: Nucleophile joins alpha carbon

racemization

40
Q

E2

A

One step: Base takes Beta hydrogen, pi bond forms between alpha and beta carbons, leaving group leaves alpha carbon

-H and LG have to be antiperiplanar

41
Q

E1

A

Step 1: Leaving group leaves alpha carbon

Step 2: Base takes Beta hydrogen, pi bond forms between alpha and beta carbons

both cis and trans are made

42
Q

Good leaving groups

A

Cl, Br, I, N+, O+, P+, S+, sulfonate