Stuff Flashcards
Even though you have a turning point, that is not neccessarily the smallest points e.g. for cubics consider the end points
The minimum could be higher than the y intercept so check the stationary points, the intercepts and the end points of the domain
a
Can do show thats from LHS or RHS e.g. show that A = B
a
Write out properly, clearly, systematically
a
0.5absinC = 0.5bcsinA = 0.5acsinB
/ by 0.5abc gives sine rule
Determine which one to use and where the height is drawn by rotating the traingle dependent on the asked variables
a
Xn+1 = Xn + n+1
Xn+1 - Xn = n+1
Therefore the terms are increasing by n+1
And so the sum of these increases is (n+1)(n+2)/2
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The sequence goes: 3, 6, 10, 15, 21 The difference of each term is: 3, 4, 5, 6 The difference of these terms are: 1, 1, 1 (Keep going until all 1's) 1's represent x^0 i.e. +c 3, 4, 5, 6 represent x^1 i.e. +bx 3, 6, 10, 15 represent x^2 i.e. +ax^2
Therefore the closed form of the formula is ax^2 + bx +c = an^2 + bn + c = Xn
By subbing in values for n and Xn i.e. n = 1 X(n=1) = 3 three times we can find answers for a, b and c via simultaneous equations
Or considering each term:
3, 6, 10, 15, 21
1+2, 1+2+3, 1+2+3+4, 1+2+3+4+5,…, 1+2+3+…+(n+1)
Therefore the Xn = (n+1)(n+2)/2
X^2 + Y^2 <=1 find the max of ax+by
X^2 + Y^2 = 1
Therefore sin^2(A) + cos^2(A) = 1
Therefore we can represent ax+by as asinA + bcosA which equals Rsin(A+c) where R^2 = (a^2 + b^2) therefore the max of ax+by = the max of asinA + bcosS = the max of Rsin(A+c) = the max of (a^2+b^2)^0.5
or just let a=b=1 !!!
SYSTEMATICALLY, USUALLY NOT THAT LONG WINDED
LOOK AT OTHER QUESTIONS !!!
a
2 letters, n-1 positions –>
2^n-1 combinations
6 numbers 4 positions repeats allowed
6!/(6-4)! = 360
Number of ways of arranging n things in a line is
n!
Sin(pi/2 - x) =
cos(x)
periods
2pi, p
a^x = b
logab = x
order matters, selecting r objects from n =
nPr = n!/(n-r)!
order doesn’t matter, selecting r objects from n =
nCr = n!/r!(n-r)!