Stresses and Strains Flashcards

1
Q

Define Stress

A

Force per unit area acting on a surface

Force/Area

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2
Q

What’s the difference between Normal Force and Shear force

And therefore Normal Stress and Shear Stress

A

Normal Force is applied perpendicular to a section

Shear Force is applied parallel to a section

Stress associated with the normal force is Normal or Direct Stress

Stress associated with the shear force is Shear Stress

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3
Q

Explain the Method of Section

A

Cut the member by passing an imaginary section through it

Provided the entire member is in equilibrium, any part after the imaginary cutting must also be in equilibrium.

So The internal forces must balance the external forces on each part

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4
Q

+ve Normal Stresses are ________

-ve Normal stresses are ________

Equation for Normal Stress =

A

Tensile

Compressive

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5
Q

Equation for Shear Stress =

A
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6
Q

What is the unit of stress

A

Pa or Nm^-2

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7
Q

What is an allowable stress.

What is a Safety factor

A

A Material Property , Maximum stress a material can withhold without fracture

A multiplier that is less 1, multiplied by allowable stress. To keep the stress way below the allowable.
The maximum stress of your system cannot surpass the safety factor

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8
Q

Define Yield Strength

A

Stress at which a material starts to deform plastically

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9
Q
A

1) Find section with maximum internal stress and use that in allowable stress calculation.

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10
Q
A
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11
Q

Define Normal Strain, & what is the equation

A

ratio of the change in length of the material against its original length ε
Due to a Normal Stress acting on the body

ε = New Length/ Origional

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12
Q

Define Shear Strain

What’s the approximation made with this result

A

Shear Strain γ is the measured distortion of a body due to shear stress

It’s defined as the sum of the angles made between a side of the body in its original position and the same side of the body in its deformed position.

tan (shear strain) = Displacement between the vertex post deformation and pre deformation/ Height of the original side.

That tan(shear strain) = Shear Strain when shear strain is small.

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13
Q

Explain Strain hardening

A

Strain hardening is when a material starts to deform plastically,the stress required to continue deforming continues with increasing strain.

This is due to the formation of dislocations, imperfections in the crystal lattice. As Number of dislocations increase, they will germinate snagged on each other preventing the material to move and deform

Occurs Until the Ultimate Tensile Stress - Maximum stress a material can withstand before fracture

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14
Q

What is the Equation for Young’s modulus

Units?

A

Stress / Strain

Pa

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15
Q

What’s the Equation for Shear Modulus

A

Shear Stress/ Shear Strain

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16
Q

Explain what did Poission Discover

A

That when a bar is placed in tension, Lateral Contractions accompany the longitudinal extension

Or when a bar is placed in compression , lateral extensions accompany the longitudinal contraction

The ratio between how a material deforms laterally and longitudinally is called the Poisson Ratio.

17
Q

Derive an Equation that calculates Extension in terms of length, load force, young modulus and area of cross section

A

P = Load force
E = Young’s modulus
L = length
A = Area

18
Q

Derive an equation that calculates the strain laterally due to a longitudinal strain, in terms of Poissons ratio , Load force, Width of cross section , Height of Cross section , length of body, Youngs Modulus

A

P = Load force
E = Young’s modulus
L = length
b = width of cross section
d = height of cross section

19
Q
A
20
Q
A
21
Q

What’s the equation that links Shear Modulus to Young’s modulus

A
22
Q

Define Young’s modulus

A
23
Q

Define Shear Modulus

A
24
Q

Define Poissons Ratio

A
25
Q

What is Fracture Stress

A

Stress at which total failure Occurs

26
Q
A
27
Q

What does engineering stress assume?

A

constant cross sectional Area while deformation

28
Q

What is Ultimate Stress

A

Maximum Stress a material can sustain

29
Q

What is Yield Stress

A

Stress which Permanent Plastic Deformation Starts

30
Q

question with billet of steel

A
31
Q
A