Stoichiometry Flashcards

1
Q

What does chemistry explain?

A

Chemistry explains everything you can see. How it looks, how it feels, the way it behaves the way it does by describing everything that you can’t see

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2
Q

What does chemistry help us understand?

A

Chemistry helps us understand the biggest stuff in the universe by helping us understand the tiniest

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3
Q

In regards to the chemical scale how big are we?

A

On a chemical scale we are huge. Literally massive

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4
Q

What is stoichiometry?

A

The science of measuring chemicals that go into, and come out of, any given reaction In Greek it means “Measuring Elements” It allows us to count atoms and molecules by weighing them

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5
Q

What is Relative Atomic Mass?

A

Relative Atomic Mass is the average atomic mass of all the naturally occurring isotopes of that element

For example all Carbon occurs as one of 3 isotopes

12C 13C 14C all have 6 protons but number of neutrons varies

The relative atomic mass of Carbon is weighted average of these 3 masses which comes out as 12.01amu

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6
Q

What are amu?

A

Atomic Mass Units.

The value for a single amu is 1/12 of the mass of an atom of 12C

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7
Q

How was amu decided upon as a universal form of measurement?

A

Until the 1800s chemists around around the world used different yard sticks for measuring aroms. Most commonly used was Hydrogen atom and Oxygen atom. In 1912 Isotopes were discovered ruining many scientists methods for weighing atoms. 50 years later everyone agreed to use carbon 12 as it is common

AMU has been used universally since 1961

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8
Q

What is a mol?

A

Moles are arguably the most important unit in chemistry as they allow us to express a chemical’s relative atomic mass in terms of grams

Moles

6.022x1023 = number of atoms in 12 grams of 12C

This is known as Avogadro’s Number named in his honour

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9
Q

How many atoms in a mol?

A

A mole of any element contains

6.022x1023 atoms of that element no matter what

This allows us to express elements in grams allowing us to weigh the atoms

1 mole of 12C = 6.022x1023atoms (12 grams)

1 mole of 8O = 6.022x1023 atoms (16 grams)

8O=16amu

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10
Q

How do molar mass (M) and relative atomic mass compare(RAM)?

A

Molar Mass (M) in grams = Relative Atomic Mass (RAM) in amu

The muber of atoms per mole remains the same but the mass of a mole depends on the average mass of the element

1H 1 mol H = 1.008g

26Fe 1 mol Fe = 55.85g

6C 1 mol C = 12.01g

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11
Q

What is the chemical formula for Sucrose?

A

C12H22O11

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12
Q

How many mols of each element does sucrose contain?

A

Sucrose = C12H22O11

12 mols Carbon

22 mols Hydrogen

11 mols Oxygen

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13
Q

What is the mass of 1 mol of sucrose?

A

Sucrose = C12H22O11

Carbon > 12 mol x 12.01g/mol = 144.12g

Hydrogen > 22 mol x 1.008g/mol = 22.176g

Oxygen > 11 mol x 16.00g/mol = 171g

Mass of 1 mol sucrose = 342.296g

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14
Q

Why does this equation not reflect chemical reality?

C12H22O11 + O2 = CO2 + H2O

Reactants ^^ ^^Prodcuts

A

During a reaction bonds are broken and new ones are formed but THE NUMBER OF ATOMS OF EACH ELEMENT REMAINS THE SAME

CONSERVATION OF MASS YO!

Reconciling the reactants with the products is called Equation Balancing

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15
Q

How can the equation become a balanced equation?

C12H22O11 + O2 = CO2 + H2O

Reactants ^^ ^^Prodcuts

A

Start with the most complicated mlecule in this case Carbon

C12 Right off the bat you know you’ll have to end up with at least 12 molecules of CO2 as this is the only place the carbon ends up

Next the Hydrogen

H22 We start with 22 molecules of Hydrogen

There are 2 Hydrogen atoms in water molecule H2O

So at least 11 water molecules 11 H2O

Finally Oxygen

Since we know we have:

12 CO2 molecules = 24 O Atoms

11 H2O molecules = 11 O Atoms

total = 35 Atoms

C12H22O11 + O2 = 12CO2 + 11 H2O

35 O Atoms - 11 O Atoms (from H2O)

= 24 O Atoms (missing from equation)

C12H22O11 + 12 O2 = 12 CO2 + 11 H2O

Conservation of Mass YO!

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16
Q

How much oxygen will I need to inhale in order to burn 5 grams of Sugar?

A

C12H22O11 + 12 O2 = 12 CO2 + 11 H2O

Focus on left part of the equation as we only need to quantify the reactants

First convert your balanced equation into molar masses in order to get from molecules to grams

C12H22O11 + 12 O2

1 mol sucrose (342,296g) + 12 mol OF O2 (348g)

342.296g Sucrose

384g Oxygen

=

5g Sucrose

X Oxygen

Compare this ratio to masses of reactants in your expirment

Solve for X

5g Sucrose = 5.6g Oxygen