Statistics and Mechanics Chapter 2 - Measures of Location and Spread Flashcards

1
Q

What is the modal value?

A

The value or class that occurs the most often.

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2
Q

What is the median?

A

The middle value when the data values are put in order.

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3
Q

How do you calculate x bar (the mean, which is symbolised by an x with a line over it)?

A

(Sum of x) divided by n. The sum of the data values divided by the number of data values.

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4
Q

What is the formula for the mean when the data is in a frequency table?

A

x bar = sum of xf / sum of f

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5
Q

How do you find the lower and upper quartiles?

A

For the LQ, divide n by 4. For the UQ, divide my 3/4 n. If the answer is a whole number, the quartile is halfway between that data point and the one above. If it is not a whole number, round UP and pick that data point.

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6
Q

What assumption are you making when you use interpolation on a frequency table?

A

You are assuming that the data values are evenly distributed within each class.

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7
Q

The formula for standard deviation.

A

The square root of the formula for variance. (Make sure to know the actual formula)

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8
Q

What is coding?

A

A way of simplifying statistical calculations. Each data value is coded to make a new set of data values which are easier to work with.

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9
Q

If data is coded using the formula y=(x-a)/b, what is the mean and standard deviation of the coded data?

A

Mean:
y bar = (x bar - a)/b

Standard deviation:
standard deviation of y = standard deviation of x/b

You would generally have to rearrange these equations to find x.

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10
Q

If the coding formula was x = (t - 20) / 2, what would you do differently to finding the mean when finding the standard deviation?

A

Multiply by 2 but don’t add 20. This is because if you add things the standard deviation will not change. (Imagine having a classroom full of people, and the standard deviation for the hight is 2cm. Then everyone stands on a chair, adding a foot to their height. The standard deviation is still 2cm because the heights have all increased by the same amount.)

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