Statistics 3 - Geometric and negative binomial distributions Flashcards

1
Q

What is the geometric distribution?

A

For successive independent trials, each with a constant probability of success, 𝑝, the number of trials needed to get one success, 𝑋, has the geometric distribution (written as π‘‹βˆΌGeo(𝑝)), with the probability function:
P(𝑋=π‘₯)=p(π‘₯)=𝑝(1-𝑝)ˣ⁻¹ Where π‘₯=1,2,3,…

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2
Q

How is the cumulative geometric distribution calculated?

A

The values of p(π‘₯) form a geometric distribution with first term 𝑝 and common ratio, (1-𝑝). As such the cumulative geometric distribution can be derived by considering the sum of the terms of the geometric series.
β‚“
Ξ£p(r)=𝑝(1-(1-𝑝)Λ£)/1-(1-𝑝)Λ£=𝑝(1-(1-𝑝)Λ£)/𝑝=1-(1-𝑝)Λ£
ʳ⁼¹
Thus if π‘‹βˆΌGeo(𝑝), then the cumulative geometric distribution is given by:
P(𝑋≀x)=1-(1-𝑝)Λ£ Where π‘₯=1,2,3,…

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3
Q

How is the mean of a geometric distribution calculated?

A

If π‘‹βˆΌGeo(𝑝), then:

The mean of 𝑋=E(𝑋)=ΞΌ=1/𝑝

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4
Q

How is the variance of a geometric distribution calculated?

A

If π‘‹βˆΌGeo(𝑝), then:

The variance of 𝑋=Var(𝑋)=σ²=1-𝑝/𝑝²

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5
Q

What is the negative binomial distribution?

A

The binomial distribution, π‘‹βˆΌB(𝑛,𝑝), models the number of successes in a fixed number of trials, 𝑛. The probability of success in each trial, 𝑝, is constant and the trials are independent.
The negative binomial distribution, often written as π‘‹βˆΌNB(π‘Ÿ,𝑝) or π‘‹βˆΌNegative B(π‘Ÿ,𝑝), models the number of trials needed to achieve a fixed number of successes, π‘Ÿ.
For successive trials, each with the constant probability of success, 𝑝, the number of trials needed to get π‘Ÿ successes, 𝑋, has the negative binomial distribution with probability function:
P(𝑋=π‘₯)=p(π‘₯)=(ˣ⁻¹ᡣ₋₁)𝑝ʳ(1-𝑝)ˣ⁻ʳ π‘₯=π‘Ÿ,π‘Ÿ+1,π‘Ÿ+2,…
This is the probability of π‘Ÿ-1 successes in π‘₯-1 trials multiplied by the probability of success in the π‘₯th trial

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6
Q

How is the mean of a negative binomial distribution calculated?

A

If π‘‹βˆΌNB(π‘Ÿ,𝑝), then:

The mean of 𝑋=E(𝑋)=ΞΌ=π‘Ÿ/𝑝

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7
Q

How is the variance of a negative binomial distribution calculated?

A

If π‘‹βˆΌNB(π‘Ÿ,𝑝), then:

The variance of 𝑋=Var(𝑋)=σ²=π‘Ÿ(1-𝑝)/𝑝²

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