Spectroscopy, Telescopes Flashcards
What is a blackbody?
A blackbody is an ideal object that does not reflect any light and thus emits electromagnetic radiation in all wavelengths entirely as a result of its temperature.
What is blackbody radiation?
Refers to the light emitted by a blackbody.
What is Wein’s Law?
The blackbody radiation consists of a continuous spectrum that peaks at a certain wavelength. This wavelength is inversely proportional to the temperature.
What is Stefan-Boltzmann’s Law?
The higher an object’s temperature, the more intensely the object emits electromagnetic radiation at all wavelengths and the shorter the wavelength at which it emits most strongly.
Formula for Wein’s Law.
Max wavelength = 0.0029 (Wein’s Constant) / Temperature
Stefan-Boltzmann Formula.
F = sigma * T^4
where F = energy flux measured in W m^-2
T = temperature in K
sigma = 5.67 * 10^-8 W m^-2K^-4
What is the temperature of the sun?
5800K
State Kirchhoff’s 1st Law.
A hot opaque body (blackbody) or dense gas, produces continuous spectrum
State Kirchhoff’s 2nd Law.
A hot, transparent gas produces an emission line spectrum.
State Kirchhoff’s 3rd Law.
A cool, transparent gas in front of a source of a continuous spectrum produces an absorption line spectrum.
What do we observe if a hot gas A is in front of an even hotter object or gas B?
The emission lines of A will darken the spectrum of B, we would see them as absorption lines.
NOTE: Gas in front must be cooler
Name for series of electron transistions from higher orbits to
(a) n = 1
(b) n = 2
(c) n = 3
(a) Lyman series (ultraviolet)
(b) Balmer series (visible)
(c) Paschen series (infrared)
Does the wavelength increase by the doppler effect when moving toward or away.
away.
In red-shift is wavelength of light increasing or decreasing.
Increasing.
Which is hotter a blue or red flame?
blue
If I have the brightness across the EM spectrum what can I get?
Temperature (SB law)
If a cloud of gas at 5000K is located between us and a red star (3000K) what will we on Earth observe.
(a) if the cloud is transparent
(b) the cloud is not transparent
(a) We will see the star’s continuous spectrum
(b) We will see emission lines from the gas and nothing from the star.