Series part 2 Flashcards
Taylor’s theorem
Let $z_0$ ∈ C and $R_0 > 0$, and suppose that
a complex function f is analytic on the disk
$D(z_0, R_0)$. Then
$f(z) = \sum_{n=0}^{\infty} a_n(z−z_0)^n$ whenever $|z−z_0| < R_0$,
where $a_n = \frac{f^{(n)}(z_0)}{n!}
(n = 0, 1, 2, . . .).$
This series is called the Taylor series of f at
$z_0$.
When does the taylor series of a function converge
the Taylor series of f converges to f at each point within the circle with centre z0 whose radius is the distance from z0 to the nearest point z1 at which f is not analytic.
Maclaurin series for $\frac{1}{1-z}$
$\frac{1}{1-z} = \sum_{n=0}^{\infty} z^n = 1 + z + z^2 +z^3 + …$
for $|z|<1$
Maclaurin series for $e^z$
$e^z$ is entire so it = its Maclauirn (and Taylor) seireis on C
$\sum_{n=0}^{\infty} e^z = \frac{z^n}{n!} = 1 + z + \frac{z^2}{2} + \frac{z^3}{3!} + … $
$\forall z \in \ C$
Maclaurin series for $sinz$
$ \sin{z} = \sum_{n=0}^{\infty} blahh = z - \frac{z^3}{3!} + \frac{z^5}{5!} - \frac{z^7}{7!} + …$
$\forall \ z \in \ C$ since sinz is entire
sinh is the same but with all plus signs (also for all z in C)
Maclaurin series for $cosz$
Differentiate
$$ \sin{z} = z - \frac{z^3}{3!} + \frac{z^5}{5!} - \frac{z^7}{7!} + …$$
to get
$$ \cos{z} = 1 - \frac{z^2}{2!} + \frac{z^4}{4!} - \frac{z^6}{6!} + …$$
$\forall \ z \in \ C$ since cosz is entire
cosh is the same but with all plus signs (also for all z in C)