Sections 1-6 Flashcards

1
Q

What is the equation for Coulomb’s Law?

A

F12 = (q1q2)/(4πϵ0)*(r2 − r1)/(|r2 − r1|^3)

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2
Q

What is the value of the permittivity of free space and what are its units?

A

8.8*10^-12 C^2 N^-1 m^-2

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3
Q

What is the equation for an electric field around a point charge q?

A

E(r) = q/(4πϵ0)*(1/r^2) (same as coulombs law, but with only one charge rather than two)

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4
Q

What is the equation for the electric dipole moment?

A

p = qd q = charge d = distance between charges p = moment [Units: Cm]

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5
Q

In what direction does an electric field flow?

A

From positive to negative.

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6
Q

What are the equations for linear, surface and volume charge density?

A

Whatever the letter is divided by a change in the value, so dl, dS and dV.

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7
Q

How do you work out the electric field of a dipole?

A

FInd the contribution from each end of the dipole using the electric field equation and then add them together.

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8
Q

How do you work out the electric flux through a flat surface?

A

flux = electric field * area of surface * cos(angle)

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9
Q

How do you find the electric flux through an arbitrary surface?

A

Surface integral of the electric field * the change in area/surface (electric field is constant on surface so can take out of integral).

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10
Q

What is the surface integral of E*dS of a sphere centered on a charge q?

A

q/ϵ0

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11
Q

What is the main statement in Gauss’s Law?

A

That the electric flux through the Gaussian surface is the charge enclosed divided by the permittiviy of free space (Qencl/ϵ0)

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12
Q

How do you apply Gauss’s Law?

A

1 - Look at the symmetry to find out the electric field direction (using appropriate coordinate system)

2 - Pick a Gaussian surface and consider all parts the and electric flux going through each part

3 - Work out the enclosed charge of the Gaussian Surface

4 - Summarise and ensure you have answers for different values of radius

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