Section 4: Spectroscopic Measurements Flashcards

1
Q

what are the quantities we obtain from a spectrum

A

-precise wavelength determination of features ie lines and edges
-spectral energy density of the continuum
-spectral line shape (intensity, width(

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

quantities obtained from a spectrum are interpreted using

A

physical models for the production of radiation

or laboratory or other standard measurements to derive parameters like density, temperature, velocity etc

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

most spectrometers in use are based on

A

diffraction gratings or interference filters

(fourier transform spectrometers based on michelson are also used for high spectral-resolution work, especially in the infrared)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Modern spectrometers often imaging spectrometers, called Integral Field Units, giving spectrum for

A

multiple x.y positions in image

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

grating spectrometer results

A

spectral resolving power
angular dispersion
grating response width

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

spectral resolving power

A

Rg = Ξ»/delta Ξ» = Ngm

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

angular dispersion

A

d theta /dΞ» = m/acos theta

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

grating response width

A

Wg=Ξ»/Nga

lower limit to the angular width of lines produced by spectrometer

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

problems with raw spectra

A

usual CCD problems (cosmic ray hits, flatfield…)

spectral lines tilted on detector

no wavelength identification

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

For ground-based instruments, wavelength calibration for gratings or prisms is sometimes done using

A

absorption lines from the Earth’s atmosphere (telluric lines)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

alternative method for ground-based instruments, wavelength calibration is done using

A

reference spectral emission lamp

(the spectrum from the source and from the calibration lamps is imaged onto the same CCD)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

standard reference lamps include

A

Thorium/Argon and He/Ne/Ar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

x is the position on the CCD, expressed in

A

β€˜pixel number’

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

the dispersed reference spectrum or the reference telluric lines provide calibration as follows

A
  1. strong lines/patterns of lines from reference spectrum identified using spectral atlas
  2. fit spectral profile (eg gaussian) on CCD to find x position of central Ξ» of ref lines
  3. a curve is fitted to these identifications, giving Ξ»(x)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

CCD-based spectroscopes provide a

A

2D image of the spectrum

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

the dispersed emission line spectrum consists of

A

multiple images of the spectroscope slit, spread in colour/position along the CCD

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

ideally, slit images should be as

A

narrow as possible and aligned with CCD columns

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

to get a spatially integrated spectrum, sum

A

down columns to produce spectrum

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

In practice, there might be slight mis-alignments of the optics, which
will result

A

in tilted slit images

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

in a ground-based instrument, tilted slit images could, in principle, be corrected by

A

rotating the detector

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
21
Q

in a space-based instrument, tilted slit images need to be correct in the

A

data analysis phase

ie rotation of the spectral lines so they are aligned with the y-axis

however this remapping can cause other issues

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
22
Q

what if the remapped pixel values are not integers, how to we assign the counts to actual pixel positions

A

this is done by interpolating the data to the integer pixel positions

(consider the 1D problem and assume that the data follows a piecewise linear cure)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
23
Q

interpolation - the gradient between i1’ and i2’ is

A

m=N(i2’)-N(i1’) / i2’-i1’

(denominator is approx 1)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
24
Q

interpolation - the value of N(i’) at pixel i’ is

A

starting point:
N(i’)=N(i1’) +m(1- deltai’)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
25
interpolation - the counts value at this pixel is the
distance weighted mean of the counts at the two neighbouring locations
26
the distance weighted mean of N(i1') and N(i2') gives us
N(i')
27
linear interpolation is only an example, can also
fit a quadratic, or a polynomial through several neighbouring points depending on how rapidly the data is changing from point to point
28
Sources of instrumental noise should be reasonably well removed by
subtracting dark current, flat-fielding etc
29
even after noise removed, the source of interest will be seen against
the background (or foreground) contribution of the sky
30
if optically thin emission from the source of interest, would have to consider
emission from behind this all has to be removed to get at the source spectrum
31
usually background is not constant - how to deal with
define two background regions, on either side of the feature and then do a linear interpolation using data points in these two regions
32
let background = Nb(Ξ») =
mΞ»+c
33
(background subtraction) the total real counts in the source are
sum from Ξ»=Ξ»1 to Ξ»2 of (N(Ξ»)-Nb(Ξ»))
34
Whether subtracting background from an image or a spectrum, we deal with errors
in the same basic way
35
Ns+b=
Ns +Nb
36
total counts in the source is, Ns=
Ns+b - Nb =(Ns+Nb)-Nb
37
the combined errors (assuming poisson noise) are Οƒs^2=
Οƒs+b^2 +Οƒb^2 =... =Ns+2Nb
38
combined errors assumes gain and quantum efficiency are
1 otherwise would need to take into account (see section 2)
39
uncertainty in N=
Οƒ= sqrt (Ng/Q) (Q/g) =sqrt (NQ/g) [in DN]
40
The β€œsignificance” of an observation is defined as
the signal expressed as a number of standard deviations aka SNR
41
if Ns is 4 times Οƒs, then this is called
a 4Οƒ measurement
42
if we consider a situation where the background is low compared to the signal then Ns/Οƒs=
sqrt (Ns)
43
if Ns=rate x delta t and rate=const the significance
increases as sqrt(delta t) ie 10x more signficance = 100 x longer exposure time
44
Properties of spectral lines can be analysed to understand the conditions in the emitting medium. Because this is done β€œremotely” without affecting the astronomical objects, the analysis is said to
provide 'diagnostics'
45
An absorption line is formed by a
cooler less-dense gas overlying a hotter dense one
46
In general, the more atoms there are in the correct state to absorb the radiation from below, the
deeper the (absorption) line profile will be
47
absorption lines - also have to take into account the effect of
convolution with instrumental line profile
48
The equivalent width 𝑾 is a way to
measure the total absorption in a spectral line W such that the area of rectangular region = area of the spectral line
49
equivalent width - let the line intensity be described by
B_Ξ» which is a function of wavelength
50
equivalent width - let the continuum intensity be
Bc which is taken as a constant
51
area of absorption line=
integral form 0 to inf of (Bc-BΞ»)dΞ» =WBc
52
equivalent width, W=
integral from - to inf of Bc-BΞ» / Bc dΞ»
53
The absorption of photons is described by
the optical depth Ο„_Ξ»
54
in the absorption line, photons are taken out of the continuum (in the simplest case) and this is described by
BΞ»/Bc = e^-Ο„_Ξ»
55
if Ο„_Ξ» is large then
BΞ» is small relative to Bc (strong absorption)
56
for a weak spectral line (Ο„_Ξ»<<1), what do you use for expression for W
the series expansion for the exponential function to simplify the expression for W
57
The optical depth is related to
the atomic properties of the absorbing material, and the density of absorbers
58
the atomic properties are encapsulated in the
absorption crosssection, πˆπ€, which is a function of wavelength
59
A narrow slab of absorbing gas, with thickness πš«π’”, number density 𝒏 [m-3], has optical depth
πœπœ† = π‘›πœŽπœ†Ξ”π‘  = πœŽπœ†N
60
column density
N= 𝑛Δ𝑠
61
But it is clear that from 𝑾 we can obtain the
total amount of absorbing matter 𝑡, hence the usefulness of W
62
strong lines
𝝉𝝀 ≫1 WΞ» prop to sqrt N
63
intermediate lines
𝝉𝝀 β‰ˆ 𝟏 wΞ» prop to sqrt lnN
64
curve of growth
shows how the equivalent width varies with density curve of growth is calculated theoretically and the measured equivalent width can be linked directly to N
65
Spectral lines are produced by
a hot, tenuous gas eg coronae, gas clouds
66
lyman break
everything at shorter wavelengths completely absorbed due to neutral H along LOS in IGM
67
Atomic line diagnostics often involve
measuring the ratio of intensities between two emission lines from the same element
68
The possible transitions in an element are illustrated by diagrams called
Term or Grotrian diagrams
69
Grotrian diagrams for neutral Fe, once-ionised and twice ionised Fe show
the richness of spectra from heavy ions so many possible transitions
70
Most common spectroscopic diagnostics rely on assuming that
the radiating gas/plasma is in local thermodynamic equilibrium
71
In local thermodynamic equilibrium (LTE) the matter is
in thermal equilibrium in some small neighbourhood around a point in space can be heating/cooling but doing so slow matter and radiation do not have to be in equilibrium
72
* For a gas/plasma, LTE means that the particle distribution function 𝒇(𝒗) is
a Maxwell-Boltzmann distribution
73
LTE also means that the system reaches equilibrium via
collisions between particles
74
In many cases we can also assume that interaction with radiation is
negligible the radiation escapes the gas/plasma without interaction - optically thin approximation
75
most of the collisional excitation is by
free electrons Being faster than ions or atoms at the same temperature, the free electrons have more interactions per second
76
a collision -
a free electron perturbs an orbital electron
77
In LTE, the probability π’‘π’Š of finding an atom in state π’Š is determined by
the boltzmann factor, pi
78
boltzmann factor is proportional to
po, gi (degeneracy) and energy
79
what is po in the boltzmann factor
constant found by normalising the probability over all possible states of energy π‘¬π’Š
80
For two levels π’Š and 𝒋 (𝒋 = upper level and π’Š = lower level) the ratio of the number of atoms in each level is
ni/ni =gi/gi exp (-(Ej-Ei)/kT)
81
Ej-Ei is the
transition energy between levels
82
the population ratio of two levels depends on
the temperature
83
In an optically thin gas/plasma, the excitation to the upper level is by
collisions
84
The average number π’π’Šπ’‹ of transitions per second per unit volume, from state π’Š to state 𝒋, due to collisions is
nij = ni ne Cij
85
Cij
the collisional rate coefficient, and depends on the electron speed, and the atomic properties
86
ne
the number of electrons per unit volume
87
ni
the number of atoms in state π’Š per unit volume
88
In a true equilibrium, the average state does not change, so for...
every upwards transition π’Š β†’ 𝒋 must be accompanied somewhere by a downwards transition 𝒋 β†’ π’Š. this is called detailed balance
89
In the case where upwards transitions are collision-dominated, and downward transitions are due to spontaneous radiation (the β€œcoronal approximation”) we have
ni ne Cij = nj Aji
90
the coronal approximation
the case where upwards transitions are collision-dominated, and downward transitions are due to spontaneous radiation
91
einstein coefficient
the average number of transitions per second per atom
92
Iji
photon emission rate per unit volume =nj Aji
93
Consider two levels of an atom - call them 1 and 2. Assume that they are both excited by collisions from the ground level, and decay by radiation back to the ground state. Then:
I2g/I1g = Cg2/Cg1
94
the ratio of intensity of these 2 lines gives a measure of the
gas temperature
95
Collisions between fast electrons and atoms in a hot gas can result in
the ejection of a bound electron into a free state (ie collisional ionisation)
96
Atoms with more than one electron can exist in different stages of ionisation. Removing successive electrons takes
increasing amounts of energy
97
ionisation potential
the energy required to remove an electron represented by Chi
98
Consider the situation where the upper level is an ion plus a free electron with speed 𝒗. The energy of this level is
E= X +1/2me v^2
99
To calculate the number of e-i pairs in this ionisation stage, we
calculate the number, πœŸπ’(𝒗) of states for an ion and a free electron with velocity 𝒗, and then integrate over all possible v
100
The statistical weight of a particle is
the number of states that it can occupy
101
Electrons are fermions, so obey
Fermi-Dirac statistics at most only 2 e- per state
102
saha ionisation equation relates
the number of ions in ionisation stages r+1 and r
103
population of different ionisation stages of the same species depends sensitively on
the plasma temperature
104
calculations of the saha equation for various ion pairs as a function of temperature results in
ionisation balance curves
105
ionisation balance curves
ratio will peak at some temp and then fall off
106
contribution function
g(t) calculated from atomic physics and peaks strongly at some T
107
By plotting the ratio of two spectral lines from the same ion, the 𝚺 and 𝒏𝒆 terms
cancel and we are left with the ratio of the two g(t) functions this ratio depends on temperature
108
Assuming emission from isothermal plasma, the temperature can be determined from
the observed intensity ratio
109
contribution function sensitive only over a limited temperature tange, depending on
the lines used
110
If we allow also for collisional de-excitation from level 𝒋 to level π’Š, then the expression for detailed balance becomes
same as before but with an additional njneCij term
111
collisional de-excitation from level j to level i might happen if
Aji is very small ie the natural (radiative) decay time of level j is very long
112
Aji=
1/Ο„ where Ο„ is the radiative lifetime
113
forbidden transition - the upper level is called a
metastable level
114
de-population of metastable levels can be largely due to
collisions which depend on the electron density ie this gives diagnostic on electron density
115
intensity of spontaneously de-excited allowed line 2 --> 1
I21=n1neC12
116
metastable level m can be depopulated by
radiation or by collisions C* either to the ground state or other states
117
n1neC1m=
nm Am1 + Ξ£ nm ne C* the sum is over all possible states accessible by collisions
118
Only that fraction of the excited metastable population that decays by radiation contributes to
the line intensity
119
the observed ratio is dependent on
electron number density ne (derivation on slides 150 and 151)
120
The width of the observed spectral line is due to
a number of different processes and hence a diagnostic
121
finite lifetime of electron in the excited sates (lorentzian) causes
natural broadening and collisional broadening
122
doppler motion on micro or macroscale (gaussian) causes
thermal, turbulent and rotational broadening
123
Overall line we observe is a convolution of
these processes lorentzian * gaussian ==> voigt (and convolved with the ILP)
124
this course focuses on which types of broadening
thermal and turbulent this keeps everything gaussian
125
The emission lines from a hot gas are broadened due to
random particle motions Ξ»-Ξ»0/Ξ»0 = v/c
126
line profile Ξ¦(Ξ») is given by
Ξ¦th(Ξ») dΞ» = f(v)dv
127
f(v) is the 1D Maxwellian distribution so Ξ¦th is proportional to
exp(-mv^2/2kT)
128
Using our other temperature diagnostics (line ratios), we can determine
T and hence the expected thermal line width and vth
129
Sometimes the observed spectral line width exceeds this thermal value, even once the ILP is removed. One cause of this is
the additional speed can be turbulence i.e. macroscopic motions of different parcels of emitting gas/plasma in addition to the microscopic thermal motions
130
Let the emitting gas have a distribution of macroscopic speeds p(vl)dvl=
the probability that gas is moving at turbulent LOS speed vl --> vl+dvl
131
Ignoring other broadening for the moment, the shape of the spectral line profile 𝝓𝒕𝒖𝒓𝒃 𝝀 emitted by this gas is given by:
πœ™π‘‘π‘’π‘Ÿπ‘ (πœ†) π‘‘πœ† = 𝑝 (𝑣𝐿) 𝑑𝑣
132
To obtain the overall line profile, we need to evaluate
the probability that a particle ahs a total LOS speed vtot=vl+v
133
The functions 𝒑(𝒗𝑳) and 𝒇(𝒗) are both probability density functions and the LOS speeds 𝒗𝑳 and 𝒗 can be assumed to be
independent
134
the probability of obtaining 𝒗𝑻𝑢𝑻 is obtained by
multiplying the pdfs and then integrating over all values of 𝒗, subject to 𝒗𝑻𝑢𝑻 = 𝒗𝑳 + v
135
total line profile is thus given by
the convolution of the individual line profiles
136
line emitted by the thermal plasma convolved with turbulent broadening =
overall emitted line
137
the total line profile is the convolution of
the thermal Gaussian profile and the turbulent line profile
138
Assume that the turbulent line profile is also Gaussian and define a β€œturbulent broadening” such that
(Δλturb/Ξ»0)^2 = (vturb/c)^2
139
We can evaluate the resulting overall line profile using
the convolution theorem
140
So the total line profile is also a Gaussian, with line width πš«π€π‘»π‘Άπ‘», from the combined effects of
turbulence and thermal broadening
141