Second Order Differentiaks Flashcards

1
Q

Why 2nd order

A

Because the value of derrivstive is 2nd

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2
Q

How would we long method solve
- why can we add our two solutions at the end?

A

By assuming amdeer to equation, subbing this in by finding dy/dx and d2y/ dx2 and then solving to find m.

We find that we got two solutions, and subbing any of these in will give 0

  • however adding them together ALSO works if we sub that in
  • this is because they cancel independently and si adding them together you’re allowed

Thus we get ONE EQUATION with two constants

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3
Q

So now that we saw way, how can we do short it (AE)

A

Auxhilhar equation means replace with m and solve for m

As long as you know the format it should be , then can find the answer very easily
- so repeated roots, distinct, real roots

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4
Q

What are the THREE ways for distinct , repeated and complex?

A

Distinct = A e root x + B e root x

Repeated = (Ax+B) e to the root x

Complex = E to the real part (Acos (img ) x + B sin (img x)

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5
Q

How do you get to the complex roots showing proof?

A

Find roots, and assume distinct so use first form

Now Solti up using indicted

So,it up again using Euler

Collect and manipulate to show

A and B must be resl here in our situations

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6
Q

How does a linear differntiate using zu Hillary equation look

A

A e to the root of the x !

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7
Q

How to do cyclic integration for integration by parts

A

Here, if yiu end up having to INTEGRATE what you initially wanted to integrated, let that be I, and add to other side which is already I, and now must divide !

Makes it very possible for parts

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8
Q

How to solve 2 ODE non HOMOGENOUS?

A

Use left hand sind with AE to find first part of answer , called COMPLEMENTARY FUNCTION

Use right hand side with hints to guess the last part of solution, called PARTICULAR INTEGRAL

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9
Q

How to go about finding the particular integral after learning each case?

A

Say let y = px +q

Then differntiate and sub into left

And COMPARE COEFFICIENTS EASY

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10
Q

What are all the trial function scenarios

A

Constsnt = c
Linear = ax +b
Quadratic = a x 2 +bx +c
Expoential = ae ^ (same vlaue ) x
Trig = a sin (same) x + b cos (same x)

Sum of functions = sum of trial

SPECIAL CASE = x( in front of normal trial)

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11
Q

What happens if special case AND repeated root?

A

That means you already have something like a x e to something x

So need a x SQAURED

(Multiply whatever you have by x basiclaly)

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12
Q

So hot to fully solve 2ODE?

A

First auxhillary for complimentary, solve for complimentary

2) see if second part is of form of complementary. If it is, multiply by x
3) differentiate twice and sub in trial to oringak equation
4) compare coeeficntd and find the particular integral

Add them together done

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13
Q

If there are two of the same function for particular ringegral what to do?

A

Still need to do SUM OF FUNCTIONS

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14
Q

How to solve 2ODE particular solution, what to look out for to sub In?

A

If they say at time 0 the velocity is one or something , that means NEED to differntiate your equation and sub in

In General it is quite common for you having to differntiate and sub in somethinf for second , so if don’t know , then think what could the differential represent, oh speed, then sub in speed at that time etc…

Anyways you should get a DIMULATENOUS solution at the end!

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15
Q

Why when a yute attached to a string extends the speed is given by change in extension over time

A

They move together obviously, so if the extensions given by an equation then the speed will, be given by the rate of change foe xtension

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