Repair of DNA Flashcards

1
Q

Discuss the fidelity of replication

A

There are many proteins that are involved in DNA replication- this is to maintain near perfect fidelity. A high replication accuracy arises from 5 sources:
> Cells maintain balanced levels of dNTPs - if a dNTP is present at high levels it is more likely to be misincorporated and if a dNTP is present at low levels its more likely to be replaced by the one present at high levels
> The polymerase reaction has fidelity- it occurs in two stages: a binding step in which the incoming dNTP pairs with the template while the enzyme is in open conformation, so no catalysis is occurring and then when catalysis takes place in a closed conformation.
> The 3’-5’ exonuclease activity in pol I and III detects and eliminates any errors made by the polymerase activity.
> The 5’-3’ exonuclease activity of pol I removes RNA primers
> Many enzyme systems that function to repair errors in newly synthesized DNA and any damage that occurs after synthesis.

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2
Q

Provide a brief explanation of DNA damage

A

DNA damage poses a continuous threat to genomic integrity. Cells have evolved DNA repair enzymes and repair polymerases that are complex. If DNA damage is severe it can be irreversible and can lead to a loss of genetic information and cell death. When DNA is repaired it ,ay not be perfect and this can lead to a mutation. Mutations that occur in somatic cells usually have no effect, unless they contribute to malignant transformation(cancer). Mutation that occur in germline cells are passed on to future generations.

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3
Q

Differentiate between spontaneous and induced mutations

A

Spontaneous mutations occur as a result of natural processes in cells, e.g. DNA replication errors. Induced mutations occurs as the result of interaction of DNA with an outside agent that causes the DNA damage.

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4
Q

What are the two major classes of mutations

A

The simplest type of mutation is a nucleotide substitution and mutations that alter a single nucleotide are called point mutations.

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5
Q

What are the different types of nucleotide substitutions

A

Transitions- when a pyrimidine is substituted with another pyrimidine or when a purine is subed with another purine.
Transversions- when a pyrimidine is subed with a purine or vice versa.
They can both lead to silent, missense or nonsense mutations.

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6
Q

Define synonymous mutations or silent mutations, nonsynonymous or missense mutations and a nonsense mutation

A

Mutations that change nucleotide sequence without
changing amino acid sequence
Nucleotide substitutions in protein-coding regions that do result in changed amino acids:
May alter the biological properties of the protein.
– Sickle cell anemia is an AT→TA transversion
– Glutamic acid codon in the β-globin gene replaced by a valine codon
A nucleotide substitution that creates a new stop codon:
– Causes premature chain termination during protein synthesis.
– Nearly always a nonfunctional product

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7
Q

Define indels

A

If the length of an insertion or deletion is not an exact
multiple of three nucleotides, this results in a shift in the
reading frame of the resulting mRNA.
– Usually leads to production of a nonfunctional protein.

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8
Q

Define DNA damage

A

DNA damage is any change to the double helical structure. These can result in:
> single base changes: affect the DNA sequence and has a minor effect on the overall structure of DNA
> structural distortion: an example is the induction of pyrimidine dimers by UV irradiation or intercalating agents that can cause indels during DNA replication
> DNA backbone damage: these include abasic sites(the loss of the nitrogenous base) and double-strand DNA breaks(the most severe form of DNA damage)

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9
Q

What are the 3 categories of DNA repair mechanisms

A

Direct reversal of damage, the removal of damaged DNA and replacement with undamaged DNA and mechanisms that bypass the damaged DNA(translesion DNA synthesis)

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10
Q

Provide 2 examples that involves the direct reversal of damaged DNA

A

The reversal of T-T dimers by DNA photolyase and the reversal by alkyltransferases

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11
Q

Explain the direct reversal of TT dimers by DNA photolyase

A

UV radiation induces the formation of a cyclobutane ring between adjacent thymine residues on the same DNA strand to form an intrastrand thymine-thymine dimer. The TT dimer distorts the double helix and can block replication and transcription. UV radiation can also induce dimers between cytosine and thymine. In most organisms, UV radiation damage to DNA can be directly repaired by light-absorbing enzymes called photoreactivating enzymes or DNA photolyases. DNA photolyases uses energy from near UV to blue light to break the covalent bonds holding the two adjacent pyrimidines together. DNA photolyase has 2 cofactors: a pigment that absorbs UV or blue light and fully reduced flavin dinucleotide(FADH-). The pigment absorbs UV or blue light, transfers the excitation energy to FADH-, which transfers an electron to the pyrimidine dimer already bound to the enzyme. The TT dimer is flipped out of the helix and brought close to FADH-. An electron is transferred from FADH- and the TT dimer is split. Photolyases are an ancient and efficient way to repair UV damaged DNA. However placental animals(including humans) do not have a photo reactivation pathway.

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12
Q

Explain damage repair by alkyltransferases

A

The alkylation of guanine at the oxygen atom results in O6-Methylguanine. The formation of these derivatives is highly mutagenic because during replication they cause the incorporation of thymine instead of cytosine. It is repaired by O6-alkylguanine-DNA alkyltransferase- this directly transfers the alkyl group to its own Cys residue. The reaction inactivates the protein, so strictly speaking it is not an enzyme.

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13
Q

Describe the steps involved in excision repair and the 2 types of excision repair mechanisms

A

These repair mechanisms have similar steps: recognition of damaged DNA, the removal of damaged DNA through excision, The replacement of DNA by DNA polymerases and the gaps sealed by DNA ligase.
The nucleotide excision repair(NER) repairs bulky DNA lesions such as structural distortions and base excision repair (BER) repairs nonbulky regions involving a single base.

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14
Q

Describe nucleotide excision repair

A

NER is a DNA repair mechanism that is found in all cells that eliminates damage to dsDNA by excising an oligonucleotide containing the lesion and filling in the resulting single-strand gap. This system is activated by a helix distortion rather than by recognition of a particular group. In humans NER is a defense against 2 important carcinogens- sunlight and cigarette smoke. In E.coli NER is an ATP-dependent process carried out by UvrA, UvrB, UvrC proteins. This system is called UvrABC endonuclease- it cleaves the damaged DNA strand at the 7th and at the 3rd or 4th phosphodiester bonds from the lesions 5’ and 3’ sides. The excised oilgonucleotide is displaced by the binding of UvrD and replaced by the actions of Pol I and DNA ligase.

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15
Q

Explain what occurs if the NER mechanism is genetically defective

A

This means that the DNA repair mechanism is not functioning. In humans a rare inherited disease called Xeroderma pigmentosum is mainly characterized by the inability of skin cells to repair UV-induced DNA lesions. Individuals with this autosomal recessive condition are extremely sensitive to sunlight. During infancy they develop skin changes- dryness, excessive freckling etc. They often develop fatal skin cancers at at a 2000-fold greater rate than the normal population. If the DNA contains a lesion, but needs to transcribe to RNA, an urgent response is required to repair the DNA.RNA polymerase cannot transcribe through DNA damage so it will stop and give time to the DNA repair system to repair. The DNA system that is recruited is transcription-coupled repair(TCR)- which only repairs the strand that needs to be transcribed. Cockayne syndrome is an inherited disease caused by defective TCR. Individuals are hypersensitive to UV radiation, exhibit stunted growth, but have a normal incidence of skin cancer.

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16
Q

Describe base excision repair

A

DNA bases are modified by reactions that occur under physiological conditions and by environmental agents, e.g. adenine and cytosine spontaneously deaminate to yield hypoxanthine and uracil. DNA that contains a damaged base is restored by base excision repair(BER). Cells contain a variety of DNA glycosylases that cleave the glycosidic bond of a corresponding specific type of altered nucleotide, thereby leaving a deoxyribose residue in the backbone. These apurinic or apyrimidinic sites(abasic sites) are also generated in physiological conditions by the spontaneous hydrolysis of a glycosidic bond. The deoxyribose is then cleaved on one side by an AP endonuclease and a cellular exonuclease removes the adjacent residues. The gap is filled in and sealed by DNA pol and DNA ligase.

17
Q

Why does DNA not contain any uracil

A

There is no uracil present in DNA- if there is then it is because cytosine is spontaneously deaminated to uracil. If uracil was normal in DNA, the deamination of cytosine would be highly mutagenic because there would be no indication of whether the resulting mismatched GU had originally been GC or AU- T in DNA and any U is the result of the deamination of C. Us that occur in DNA are excised by uracil-DNA glycosylase (UDG).

18
Q

Explain mismatch repair

A

Any replication mispairing that has not been recognized by DNA polymerases may still be corrected by a process known as mismatch repair. It can also repair insertions and deletions. The importance of the MMR system is that defects in the human MMR system result in a high incidence of cancer. E.coli MMR involves the participation of 3 proteins and occurs as follows: MutS binds to a mismatched base pair or unpaired bases, the MutS-DNA complex binds MutL, the MutS-MutL complex translocates along the DNA in both directions thereby forming a loop in the DNA (it must be able to distinguish between the parental and daughter strand). The translocation is driven by the ATPase function of MutS. When a hemimethylated GATC palindrome is encountered, the MutS-MutL complex recruits MutH. Mut H is a single-strand endonuclease- it makes a nick on the 5’ side of the unmethylated GATC. MutS-MutL complex recruits UvrD helicase and exonuclease which separates the strands and degrades the nicked strand from the nick to beyond the mismatch. The gap is filled by DNA pol III and sealed by DNA ligase.

19
Q

Explain the damage bypass or translesion DNA synthesis

A

This is when DNA replication proceeds and is not stopped or paused, It proceeds without proofreading- different DNA polymerases are involved, The DNA polymerase catalytic reaction has fidelity- only Watson-Crick base pairs can fit into the active site, The active sites of translesion DNA polymerases are larger, so non-Watson-Crick base pairing is allowed.

20
Q

Explain SOS response

A

In E.coli, when excessive DNA damage by e.g UV radiation induces a DNA damage bypass response system called SOS response. The cells stop dividing and increase their capacity to repair damaged DNA. When E.coli are exposed to agents that damage DNA or inhibit DNA replication, their RecA mediates proteolytic cleavage of LexA. RecA is activated to do so on binding to ssDNA. LexA functions as a repressor of genes that participate in DNA repair and control of cell division- it binds to the genes’s SOS boxes( a sequence that occurs before the gene that LexA represses- interferes with transcriptional initiation by RNA polymerase). The procedure is as follows: when DNA is damaged, RecA binds to ssDNA. The RecA-DNA complex activates LexA to cleave itself (autoproteolysis). This results in the SOS genes- lexA, recA, UvrA, UvrB to be expressed. When the DNA lesions have been repaired RecA ceases to induce LexAs autoproteolysis.

21
Q

Explain the statement SOS repair is error prone

A

The E.coli Pol III holoenzyme is unable to replicate through damaged DNA. When the replisome encounters these regions it stalls and disassembles by releasing its Pol III holoenzymes- a process called replication fork collapse. There are 2 methods to restore a replication fork: recombination repair- a homologous chromosome is used as the DNA template to repair the replication fork and SOS repair can be used. In SOS repair the Pol III cores that have been lost is replaced by one of the DNA bypass polymerases- Pol IV or Pol V. Pol IV and V have low fidelity and they lack proofreading exonuclease activity, They will replicate the DNA, but they will introduce mutations.

22
Q

Why does E.coli use the SOS repair system if it caused mutations and is highly mutagenic

A

The SOS repair is the last resort. It is only induced when there is severe DNA damage that no other mechanism can repair. It allows for the bacterial cell to survive conditions that would have otherwise resulted in cell death. It allows E.coli to survive but at a risk of losing or gaining functions which can be advantageous over cell death. The SOS repair system functions to increase the rate of mutation in order to increase the rate at which the cells adapt to new conditions, such as environmental stress.

23
Q

Explain double strand break repair

A

Double strand breaks is when both the DNA strands are affected and is the most severe form of DNA damage. DSBs are produced when: a replication fork encounters a nick and it results in replication fork collapse or through the action of reactive oxygen species which are the by-products of oxidative metabolism. Cells have two mechanisms that repair DSBs: recombination repair and nonhomologous end-joining(NHEJ).

24
Q

Explain nonhomologous end-joining

A

It directly rejoins DSBs. In NHEJ, the broken ends of DSNs must be aligned, the uneven ends must be trimmed and /or filled(blunt ends need to be produced) and their strands ligated. In eukaryotes Ku, an end-binding protein, binds to DSBs and can dimerize. The Ku-DNA complexes enable the binding of polymerases that fill the gaps and nucleases that trim the DNA. Blunt-ended ligation is therefore prepared, by DNA ligase IV in complex with Xrcc4. NHEJ is a mutagenic repair mechanism- these mutations are considered acceptable , only a small fraction of the mammalian genome is expressed.