Redox I & II Flashcards

1
Q

What does a half equation show

A

Shows the gain or loss of electrons and is balanced for atoms and charge

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2
Q

What is oxidation

A

Loss of electrons

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3
Q

What is reduction

A

Gain of electrons

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4
Q

What does the oxidation state number represent

A

represents the number of electrons lost/gained by an atom relative to its elemental/atomic state.

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5
Q

Whats an oxidising agent

A

a species that oxidises other species (by gaining electrons from them)

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6
Q

Whats a reducing agent

A

a species that reduces other species (by losing/giving electrons to them)

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7
Q

What does the overall redox equation show

A

the species or ions changing oxidation states.

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8
Q

What is a half cell / electrode

A

an equilibrium system consisting of a solid metal in a solution of its own ions.

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9
Q

What is electrode potential?

A

a measure of the equilibrium position for a half-cell / electrode.

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10
Q

What is the standard electrode potential

A

the voltage produced by a half-cell when connected to a standard hydrogen electrode, under standard conditions (298K, 100kPa, all solutions 1 mol dm-3)

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11
Q

What is the problem with not having a salt bridge

A

The circuit of a cell is not complete

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12
Q

What is a half cell / electrode

A

An equilibrium of a metal and its ions
e.g. Cu(s) ⇌ Cu2+(aq) + 2e-

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13
Q

What are the standard conditions for a standard electrode potential

A

100kPa, 298K, 1 mol dm-3

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14
Q

Describe a standard hydrogen electrode (4 marks)

A

Platinum rod allowing the H2 half reaction to take place, the rod being unreactive
H2 gas bubbles form
under standard conditions which are 298K, 100kPa and in this case, 1 M of H+ ions (acid)

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15
Q

What happens if we heat up the below reaction and why
Na+ + e- ⇌ Na

A

equilibrium shifts left
as the forwards reaction is exothermic as we are making bonds and forming attractions
so the system shifts its equilibrium to counteract the change and so it moves in the endothermic direction
this is the backwards reaction

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16
Q

What happens if we heat up the below reaction and why
Cr3+ + 3e- ⇌ Cr

A

equilibrium shifts left
as the forwards reaction is exothermic as we are making bonds and forming attractions
so the system shifts its equilibrium to counteract the change and so it moves in the endothermic direction
this is the backwards reaction

17
Q

How do represent a cell with a magnesium electrode and a silver electrode

A

Mg(s) I Mg2+(aq) I I Ag+(aq) I Ag(s)

18
Q

What goes on the right side of the shorthand for representing cells and what does this mean

A

The most positive thing
this means Ecell values will always positive UNLESS its with a hydrogen cell. Then it could be either positive or negative

19
Q

If a iron cell has an E value of -0.44 and a lead cell has an E value of -0.13, what is the
Ecell value

20
Q

Why are fuel cells awesome (good)

A
  • only waste product is water
  • light weight
  • doesn’t require fossil fuels
21
Q

Why are fuel cells not awesome (bad)

A
  • isn’t widely available
  • often made from methane
  • hydrogen is explosive when stored badly
22
Q

why can a titration be self indicating

A

one of the reactants is coloured, and a tiny excess of one of the reagents signals the end point

23
Q

When does a redox reaction show feasibility?

A

when the emf is positive

24
Q

When is a redox reaction not feasible using emf ?

A

When the emf is negative

25
Q

Why might a redox reaction not happen even if the emf is positive?

A

kinetic factors, such as Ea, temperature, concentrations

26
Q

Copper reacts with concentrated nitric acid. Why?
2H+ = H2 E = 0.0
Cu2+ + 2e- = Cu E = +0.34
NO3- + 2H+ + e- = NO2 + H2O E = +0.80

A

NO2- runs right and Cu runs left
Cu is less positive than the NO3-
E cell = +0.80 + -0.34 = +0.46
emf is pos and so the reaction is feasible

27
Q

How do E cell and Δ S total link?

A

ΔG = -n F Ecell
ΔG = -T ΔStotal
so…
-n F Ecell = -T ΔStotal
and because n and F are both constant for a GIVEN CELL REACTION and temperature
ΔS total is directly proportional to E cell

28
Q

what is a salt bridge usually soaked in

29
Q

what is the point if a salt bridge

A

maintains electrical neutrality within the cell by providing ions to either side

30
Q

why is a salt bridge made up of soaked paper rather than metal

A

the metal may form their own metal/ion potentials in the circuit

31
Q

why are the comparative readings in the data book called the right hand electrode systems

A

because the left hand electrode will always be the hydrogen electrode when we measure them

32
Q

if the value of an electrode potential is positive where does equilibrium lie

A

to the right

33
Q

if the value of an electrode potential is negative where does equilibrium lie?

A

to the left

34
Q

combine the half cells
Al3+ + 3e- ⇌ Al -1.66
Cu2+ + 2e- ⇌ Cu +0.34

A
  • rewrite in the correct directions
    combine them like normal redox, by balancing the electrons

so 3Cu2+ + 2Al -> 3Cu + 2Al3+

35
Q

how do ln k and e cell link

A

ΔG = - n F Ecell
ΔG = -RT ln K
so - n F E cell = - RT ln K
so at a given T, ln K = E cell due to the removal of constants

36
Q

You want to find the concentration of a solution of
FeSO4.

You take 25cm3 of the solution, acidify it, then titrate
with 0.01mol dm-3 KMnO4 solution. It requires 14.30cm3
of KMnO4 solution to fully react.

A

Half equations:

Fe2+ 🡪 Fe3+ + e-

MnO4- + 8 H+ + 5 e- 🡪 Mn2+ + 4H2O

  1. Ratio will be 5 Fe2+ : 1 MnO4-
  2. Moles of KMnO4 = 0.01 x 0.0143 = 0.000143 mol
  3. So mol Fe2+ = 0.000143 x 5 = 0.000715 mol
  4. So conc of Fe2+ = 0.000715 / 0.025 = 0.0286 mol dm-3
37
Q

You want to find the conc of another solution of FeSO4.
You take 25cm3 of the solution, acidify it, then titrate
with 0.02mol dm-3 K2Cr2O7 solution. It requires
22.60cm3 of K2Cr2O7 solution to fully react.

A

Half equations:

Fe2+ 🡪 Fe3+ + e-

Cr2O72- + 14 H+ + 6 e- 🡪 2 Cr3+ + 7H2O

  1. Ratio will be 6 Fe2+ : 1 Cr2O72-
  2. Moles of K2Cr2O7 = 0.02 x 0.0226 = 0.000452 mol
  3. So mol Fe2+ = 0.000452 x 6 = 0.002712 mol
  4. So conc of Fe2+ = 0.002712 / 0.025 = 0.108 mol dm-3
38
Q

What does an alkali fuel cell electrode look like

A

At the negative electrode:
H2 (g) + 2OH- (aq) -> 2H2O (l) + 2e-
At the positive electrode:
½ O2 (g) + H2O (l) + 4e- -> 4OH- (aq)

39
Q

What does an acid fuel cell electrode look like

A

At the negative electrode:
H2(g) 🡪 2H+(aq) + 2e-
At the positive electrode:
½ O2(g) + 2H+(aq) + 2e- 🡪 H2O(l)