Real Numbers Flashcards
Heine-Borel Theorem
S is compact if and only if it is closed and bounded
Bolzano-Weierstrass Theorem
A bounded infinite set has at least one accumulation point
Archimedean Property of R
A set N of natural numbers is unbounded above in R
Archimedean Property Equivalents
1) For every z in R, there is a n in N such that n>z (there’s always a greater integer than any number) 2) For x>0 and y in R, there is an n in N such that nx>y (equivalently, n>y/x) 3) For each x>0 there is an n in N such that 0>1/n>x
Density of Ir/rationals
If x and y are real numbers x<y>
</y>
The intersection of ANY collection of closed sets
is closed
The union of any FINITE collection of closed sets
is closed
Definition of Compactness
S is covered by an infinite open cover and also by a finite sub cover of the open cover
Triangle Inequality
|x+y|<=|x|+|y|
Let sn and an be sequences and let s be a real number, if for some k>0, m in the natural numbers and an→0
|sn-s|<=k|an| for all n>=m, then sn→s
Find an upper bound for numerator and lower for denominator
Completeness Axiom
Every nonempty subset S of real numbers that is bounded above has a least upper bound. (sup S exists and is a real number)
1) rationals are not complete, i.e (0, sqrt(2)) the sup would be sqrt (2), but it is not in the set of Q rationals
The union of any collection of open sets
is an open set
The intersection of any finite collection of open sets
is an open set
Boundedness
*Set S is said to bounded if it bounded above and bounded below
*it has a sup S and an inf S
Neighborhood
N(x,epsilon)=
{y in R : |x-y| < epsilon}
Neighborhood x of radius ep is open interval (x-ep, x+ep)
Related: interior points
Deleted Neighborhood
N*(x,epsilon)=
{y in R : 0 < |x-y| < epsilon}
(x-ep, x) U (x, x + ep)
Related: accumulation points
Interior Point
A point is an interior point if there is A (at least one) N(x,ep) C S
Boundary Point
If for EVERY neighborhood N(x,ep) the intersection of N with S is not empty and the intersection of N with Sc is not empty
Open/Closed Sets
If bd S C S then S is closed
OR
if bd S C Sc then S is open
(MOST sets are neither/both)
Accumulation Point
set of all accumulation points is S’
A point x in R is an acc pt if EVERY N*(x, ep) contains a point in S
Intersection of N*(x) and S is not empty
Isolated Point
x in S but NOT in S’
it’s literally isolated (likely to be a bd since it’s neighborhoods will intersect with Sc)
Closure
cl S = S U S’
S is closed iff S contains of its accumulation points
cl is closed set
S is closed iff S = cl S
cl S = S U bd S