Reaction Reagents 8 Flashcards
alcohols have – BP?
much higher BP bc it can do HB with O or H
alcohols are
amphoteric! act as base or acid
making alkoxide reaction
alcohol gets deprotonated by strong acid (NaH) or becomes salt with metal (Na, K, Li)
H- of NaH acts as base and removes H from OH of alcohol making alkoxide
Factors that stabilize alcohols and phenols?
- resonance: phenol + benzene + OH
- induction: add EWG to OH
- solvation effects: less sterically hindered = can solvate and stabilize charge better = stronger acid
alcohol synthesis from alkyl halide
substitution:
primary alkyl halide + strong nuc/base -> alcohol (Sn2)
tertiary alkyl halide + weak base -> alcohol (Sn1)
alcohol synthesis from alkenes
addition rxns
ACID CATALYZED HYDRATION
alkene pi attacks H on H3O, makes carbocation, carbocation gets attacked by H2O, gets deprotonated (OH ends up on most subbed C)
HYDROBORATION OXIDATION
alkene attacks B on BH3, and BH2 adds to least hindered group, H2O2 + NaOH substitutes BH2 (OH ends up on least subbed C)
DIOLS
syn: OsO4/KMnO4
anti: peroxyacid - 1)RCO3H, 2)H3O+
How can you determine oxidation state of C?
treat bonds as ionic and count a neg charge to most EN atom in bond
What is the general mechanism of reduction to make alcohols?
carbonyl group has pi bond, C in pi bond gets attacked, other group adds to C and O on carbonyl gets protonated
catalytic hydrogenation reaction to make alcohol
carbonyl + H2 + metal catalyst (Pt, Pd, Ni)
adds H to C and O turns to OH, pi bond becomes single bond
this is not selective; all pi bonds get H’s added
carbonyl + NaBH4 (sodium borohydride)
H of BH4 attacks C of C=O -> puts H on to carbonyl C
O- of carbonyl intermediate attacks proton donor (H2O, EtOH, MeOH) to protonate O
makes alcohol
**
unsymmetrical ketone or aldehyde gets attacked by H- on either side = enantiomers**
NaBH4 is a common reducing agent for aldehydes and ketones
carbonyl + LiAlH4 (lithium aluminum hydride)
H of AlH4 acts as H-, adds C to C=O of carbonyl
second step: proton donor for O- to become OH
alcohol formation
How does NaBH4 compare to LAH?
LAH stronger bc Al is less EN than B so more polarized bond of H-Al
What can LAH reduce that NaBH4 can’t?
esters and carboxylic acids ==> makes primary alcohols
ester + LAH
- H of LAH attacks C of C=O
- single bonded O (and its group) (alkoxide) LG
- double bond C=O reforms
- H of LAH attacks C of C=O again
- O- from carbonyl basic attack on proton donor
makes primary alcohol
alkyl halide + Mg metal
R-Mg-X = C-
C- = really good nucleophile = strong base
can’t be made in presence of proton source